accessing individual array elements in VBA function - arrays

Question

VBA newbie here. I am trying to pass an array (it is static, but please answer for dynamic range as well) to a function. Then assign individual array elements to unique variables and use these variables in a custom formula. I just browsed around and wrote the code but keep getting #VALUE! error. The gist of the code is below:
Public Function mytest(ByRef arr1 As Range)
Dim A As Double
Dim B As Double
A = arr1(0)
B = arr1(1)
mytest = A + B 'The actual formula is a bit more complicated than simple addition
End Function
I am not sure what am i doing wrong at all. If anyone has a solution, can you please explain why it works as well. I appreciate any and all help I can get.
Many thanks !

Answer 1

As Coleman pointed out a range is not an array, consider:
Public Function mytest(ByRef arr1 As Range)
Dim A As Double
Dim B As Double
A = arr1(1, 1)
B = arr1(2, 1)
mytest = A + B 'The actual formula is a bit more complicated than simple addition
End Function
NOTE:
we treat the Range similar to an array
it is two dimensional
it is 1 based
if you are only dealing with the Range's value, you could create an internal array within your function that directly maps to the passed Range.
if the Range is truly dynamic, (like a Spill range) then all you need to pass is the anchor cell.

Answer 2

You seem to be trying to use a worksheet range as a 0-based array. That doesn't really make sense although using the Cells property of a range (which you are actually trying to do implicitly) you can come close:
Public Function mytest(arr1 As Range)
Dim A As Double
Dim B As Double
A = arr1.Cells(1)
B = arr1.Cells(2)
mytest = A + B 'The actual formula is a bit more complicated than simple addition
End Function
In the above code, you can drop Cells() since it will function as the default property here, but most experienced VBA programmers like to make explicit what property they are using.
This will more or less work for 1-dimensional ranges but might not work as expected with 2-dimensional ranges. Cells takes up to 2 indices and in general I think that the code is clearer when you are explicit about the full indices (e.g. A = arr1.Cells(1,1) and B = arr1.Cells(2,1)).

Answer 3

The question isn't in the code you posted but in the procedure that calls it. Here the calling procedure first assigns values to the cells in the worksheet (for testing purposes), then passes the range to the function which extracts the values into an array and then uses that array to calculate a return value.
Private Sub TestmyTest()
Dim Rng1 As Range
Cells(1, "A").Value = 3.14
Cells(2, "A").Value = 3
Set Rng1 = Range("A1:A2")
Debug.Print myTest(Rng1)
End Sub
Function myTest(Rng1 As Range) As Double
' procedures are 'Public' unless declared as 'Private'
' Therefore only declare "Private" or nothing
' Arguments are passed ByRef unless they are declared as 'ByVal'
' Therefore I recommend to omit "ByRef"
Dim Arr As Variant
Dim A As Double
Dim B As Double
' this creates a 1-based 3-D array of 2 row and 1 column
Arr = Rng1.Value
A = Arr(1, 1)
B = Arr(2, 1)
myTest = A + B 'The actual formula is a bit more complicated than simple addition
End Function