Difference between Join and Subquery in SQL Server 2017 - sql-server

This is my first query:
select
r.[ProductID], [Name],
[Color], [UnitPrice]
from
[Production].[Product] r
inner join
[Sales].[SalesOrderDetail] d on d.productid = r.productid
This is my second query:
select [ProductID], [Name], [color]
from [Production].[Product] o
where [ProductID] in (select [UnitPrice]
from [Sales].[SalesOrderDetail] s
where s.ProductID = o.ProductID)
The first query returns correctly what I want to achieve, but the second query returns null. I want to use the second query to have the same result. Is that possible?

You can use exists :
select p.*
from product p
where exists (select 1 from SalesOrderDetail sd where sd.productid = p.product);
Your second query is not same as first query. It is comparing ProductID against UnitPrice which is invalid. Should produce no result.
For original version of query you can just change the sub query unit price with Productid :
where [ProductID] in (select sd.productid from SalesOrderDetail sd)
However, if you want unitprice (which is available in SalesOrderDetail) then this subquery will not help you. You need JOIN instead.

Related

SQL Query Group by Count and Left Join Tables

i need your help! I got some simple SQL skills, but this query kills me...
My Tables
Now i want the TOP5 WorkTimes on the Equipment (What Equipment got the longest WorkTime).
I want this OUTPUT:
MY Query:
SELECT
Equipment, EquipmentName, count(Equipment) as Count
FROM
Operations o
LEFT JOIN Orders ord ON ord.Id = o.[Order]
LEFT OUTER JOIN Equipments e ON ord.Equipment = e.EquipmentNumber
GROUP BY
Equipment, EquipmentName
ORDER BY Count DESC;
Another Question is how i can show o.Worktime?
i got an error with GroupBy...
please help me Thanks!
You can try this query:
select equip_nr,
(select equipmentname from table_equipments where equipmentnr = [to].equip_nr) equip_name,
sum(timeInMins) / 60.0 Worktime
from (
select (select equipmentnr from table_orders where id = [to].[order]) equip_nr,
case when workunittime = 'RH' then worktime * 60 else worktime end timeInMins
from table_operations [to]
where exists(select 1 from table_orders
where [to].[order] = id
and location = '152')
and [start] >= '2018-07-01 00:00:00.000' and [start] < '2018-08-01 00:00:00.000'
) [to] group by equip_nr
By the way, LEFT JOIN is equivalent to LEFT OUTER JOIN.
Just use SUM(worktime) as aggregate function, instead of COUNT(Equipment)
SELECT
e.[ID_Equipment]
, Name
, SUM( IIF(o.WorkUnitTime='MIN', worktime/60.0, worktime) ) as WorktimeMIN
FROM
Operations o
LEFT JOIN Orders ord ON ord.ID_Order = o.ID_Order
LEFT OUTER JOIN Equipment e ON ord.ID_Equipment = e.ID_Equipment
GROUP BY
e.[ID_Equipment]
, Name
ORDER BY
WorktimeMIN DESC
See SQL Fiddle here: http://sqlfiddle.com/#!18/5b5ed/11

Using sub-queries and filter in WHERE clause while joining tables

SELECT DISTINCT(t1.Ticker),t2.SecurityID,t2.ClosePrice,t2.QuoteDateTime FROM [Hub].[SecurityMaster].[SecurityMasterDetails] as t1
INNER JOIN [Hub].[SecurityMaster].[SecurityPrices] as t2
ON t2.SecurityID =t1.SecurityID
WHERE t2.QuoteDateTime IN (SELECT max(QuoteDateTime) FROM [Hub].[SecurityMaster].[SecurityPrices]) AND t1.SecurityTypeName = 'REIT'
I get an output with no data. The subquery doesn't run along with the other filter in the WHERE clause. I am not sure what I am doing wrong. Can somebody please help!
If you are trying to get the lastest row from SecurityPrices for each Ticker, one option is to use cross apply():
select --distinct /* distinct not needed if `Ticker` is unique on `smd`
smd.Ticker
, sp.SecurityID
, sp.ClosePrice
, sp.QuoteDateTime
from [Hub].[SecurityMaster].[SecurityMasterDetails] as smd
cross apply (
select top 1
i.SecurityID
, i.ClosePrice
, i.QuoteDateTime
from [Hub].[SecurityMaster].[SecurityPrices] i
where i.SecurityID = smd.SecurityID
order by i.QuoteDateTime desc
) as sp
where SecurityTypeName = 'REIT' /* which table does this column belong to? */
I think your query would be
SELECT DISTINCT TOP 1 WITH TIES
t1.Ticker,
t2.SecurityID,
t2.ClosePrice,
t2.QuoteDateTime
FROM [Hub].[SecurityMaster].[SecurityMasterDetails] as t1
INNER JOIN [Hub].[SecurityMaster].[SecurityPrices] as t2 ON t2.SecurityID =t1.SecurityID
WHERE SecurityTypeName = 'REIT'
ORDER BY t2.QuoteDateTime DESC
You aren't getting results because the max(QuoteDateTime) record doesn't have SecurityTypeName = 'REIT'. I think you want the max(QuoteDateTime) for this SecurityTypeName, so this can be done with an INNER JOIN.
SELECT DISTINCT
(t1.Ticker),
t2.SecurityID,
t2.ClosePrice,
t2.QuoteDateTime
FROM [Hub].[SecurityMaster].[SecurityMasterDetails] as t1
INNER JOIN [Hub].[SecurityMaster].[SecurityPrices] as t2
ON t2.SecurityID =t1.SecurityID
INNER JOIN
(SELECT max(QuoteDateTime) DT FROM [Hub].[SecurityMaster].[SecurityPrices]) P on P.DT = t2.QuoteDateTime
WHERE SecurityTypeName = 'REIT'
EDIT
Your data doesn't have what you think it does, I suspect. Here is how you can check...
--Find the SecurityID that matches the max date
SELECT
SecurityID ,
max(QuoteDateTime) DT
FROM [Hub].[SecurityMaster].[SecurityPrices]
GROUP BY SecurityID
--I'm betting this ID isn't in your SecurityMasterDetails where the Type is REIT
SELECT DISTINCT
SecurityID
FROM SecurityMasterDetails
WHERE SecurityTypeName = 'REIT'
Since the SecurityID returned in the first query isn't in the second query result set, you are going to get NULL results.

How to achieve grouping within grouping in sql query

I am using following query and it displays following result
Query
SELECT
Id,
COUNT(Id) AS Cnt,
VehNo,
VehName,
ValidTo,
IMIE,
dr.DriD,
DriName,
MAX(SignalDateTime) SignalDateTime,
MAX(DateTime) DateTime
FROM tbl_gpsData gps
LEFT JOIN tbl_Veh eq
ON eq.ID = gps.VehID
LEFT JOIN tbl_DriMaster dr
ON dr.DriID = gps.DriID
GROUP BY ID,
VehNo,
VehName,
ValidTo,
IMIE,
dr.DriID,
DriName
ORDER BY ID ASC
I get the following result after execution but as highlighted in image i get 4 records for same vehid EQM0000009 and some other Vehids because the driID(6 th column.'DRV0000100' and so on ) is different.
I want only one record for EQM0000009 which has maximum datetime value out of 4 records . Datetime is the last column in image. How could i do that grouping within grouping?
Below query will help you
select Id,count(Id) as Cnt,VehNo,VehName,ValidTo,IMIE
,dr.DriD,DriName
,MAX(SignalDateTime)SignalDateTime,MAX(DateTime) [DateTime]
into #temp
from tbl_gpsData gps left join tbl_Veh eq
on eq.ID=gps.VehID
left join tbl_DriMaster dr on dr.DriID=gps.DriID
group by ID,
VehNo,VehName,ValidTo,IMIE
,dr.DriID,DriName
SELECT * FROM #temp a INNER JOIN (SELECT Id,MAX([DateTime]) AS Dt FROM #temp
GROUP BY Id) b ON a.Id =b.Id AND a.[DateTime] = b.Dt

How to select multiple columns from a detail table in SQL Server

I have the following tables:
MASTER table (ID(PK), NAME, etc)
DETAIL table (ID(PK), IDMASTER(FK), VALUE1, DATE1, etc)
What I need is a SQL query or a way to do a select like
I work with SQL Server.
What I need is a SQL query or a way to do a select like
SELECT
M.ID, M.NAME,
(SELECT TOP 1 DT.ID, DT.VALUE1
FROM DETAIL D
WHERE D.IDMASTER = M.ID
ORDER BY DATE 1 DESC)
-- more than one column with a where clause and an order clause
FROM
MASTER M
Use OUTER APPLY:
SELECT M.ID,
M.NAME
D.ID,
D.VALUE1
FROM dbo.[MASTER] M
OUTER APPLY(SELECT TOP 1 ID, VALUE1
FROM dbo.DETAIL
WHERE IDMASTER = M.ID
ORDER BY [DATE] DESC) D;
You do this with APPLY operator:
select * from master m
outer apply(select top 1 * from detail d where d.masterid = m.id order by d.date1 desc)oa

Performing a conditional join in SQL Server

I have a SQL Server database. My database has two tables:
Customer Order
-------- -----
ID (int) ID (int)
Name CustomerID (int)
EmailAddress
When I query these tables, I might have a orderID. If I have an order ID, I want to return the customer associated with it. If I do NOT have an order ID, or if it equals 0, I want to return all of the customers. In an attempt to do this, I've written the following query:
SELECT
o.[ID]
FROM
[Order] o
WHERE
o.[ID]=#orderID
This query returns all orders with OrderID. However, I'm not sure how to do my conditional query. Is that even possible in SQL Server? If so, how?
For what you want you could use a case statement with Conduit's answer. Basically
CASE
WHEN #orderid = 0 OR #orderid IS NULL
SELECT * from Customer
ELSE
select c.*
from Customer c
inner join order o
on c.ID = o.CustomerID
where o.orderID = #orderID
END;
It may not be exact, I am not on a box with Sql Server installed.
I can think of a few ways to do this:
SELECT *
FROM Customer
WHERE CustomerID = coalsece( (select TOP 1 customerID from Orders WHERE OrderId= #OrderID), CustomerID)
.
With CustomerOrders As (
SELECT CustomerID, ID as OrderID
FROM Orders
WHERE OrderID = #OrderID
)
SELECT DISTINCT c.*
FROM Customer c
INNER JOIN CustomerOrders co ON c.ID = coalesce(co.CustomerID, c.ID)
You can achieve it using COALESCE in sql server -
SELECT c.*
FROM customer c
WHERE c.Id IN (
SELECT o.[CustomerID]
FROM [Order] o
WHERE o.[ID] = COALESCE(#orderID, o.[ID])
)

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