What am I doing wrong in converting char to int? - c

Question

I am basically trying to convert a char vector to int values: in file stage_03.txt I have something like 10011 10101 10011 11001 etc. and the stage_04.txt file should look like 19 21 19 etc. This code works perfectly fine in Code::Blocks. However, the stage_04.txt file is totally messed up when I run the code in Linux terminal: ^R ^S ^D etc.
#include <stdio.h>
#include <math.h>
int main(void) {
char x[256];
int aux[1000];
int numar = 0;
int z = 0;
int i = 0;
int l = 0;
int ch;
FILE *fin = fopen("stage_03.txt", "r");
FILE *fout = fopen("stage_04.txt", "w");
while ((ch = fgetc(fin)) != EOF) {
x[i++] = ch;
}
for (int i = 0; i < l; i = i + 6) {
numar = 0;
for (int j = 0; j <= 4; j++)
numar = numar + (x[i + j] - '0') * pow(2, (4 - j));
aux[z++] = numar;
}
for (i = 0; i < z - 1; i++) {
fputc(aux[i], fout);
fputc(' ', fout);
}
return 0;
}
What can I do to solve this?

Answer 1

Here is my solution. Please do not regard this as a "final" code. In final code one should divide the code into subprocedures and add error handling. I left this out for simplicity, here. The solution adds more flexibility concerning the separators and lengths of the numbers in the source file.
It can easily deal with source files such as:
0 1 00 01 10 11 000 001 010 011
100 101 110 111
0000 0001 0010 0011 0100 0101
0110 0111 1000 1001 1010 1011 1100 1101 1110
1111 10011 11001
You can see that fields do not need to have a fixed size of 6 character like in the original code.
#include <stdio.h>
#include <math.h>
#include <string.h>
int main(void) {
char sourceValues[256];
int targetValues[1000];
int number = 0;
int numLength = 0;
int i = 0;
int charsToProcess = 0;
int ch;
const char *srcPtr = &sourceValues[0];
int* targetPtr = &targetValues[0];
FILE *fin = fopen("stage_03.txt", "r");
FILE *fout = fopen("stage_04.txt", "w");
// read source file and determine number of chars to be processed
while ((ch = fgetc(fin)) != EOF) {
sourceValues[i++] = ch;
}
sourceValues[i] = '\0'; // terminate source data
charsToProcess = i;
srcPtr += strcspn(srcPtr, "01"); // eventually skip leading whitespace
do {
numLength = strcspn(srcPtr, " \t\n\r\v"); // determine runlength until next separator
// Convert ASCII into binary form
number = 0;
for (int i = 0; i < numLength; ++i)
{
number <<= 1; // Make room for next digit and propagate existing digits stepwise to their final place
number += (*srcPtr++ == '1'); // Insert new digit at starting pos
}
*targetPtr++ = number; // Store converted number in binary representation in target array
srcPtr += strcspn(srcPtr, "01"); // Skip whitespace. Set srcPtr to next numeric sequence
} while (srcPtr < sourceValues + charsToProcess);
for (const int *ptr = &targetValues[0]; ptr < targetPtr; ++ptr) {
fprintf(fout, "%d ", *ptr);
}
return 0;
}
Here is the output to the input given above:
0 1 0 1 2 3 0 1 2 3 4 5 6 7 0 1 2 3 4 5 6 7 8 9 10 11 12 13 14 15 19 25