I have a column in format as
yyyyMM
in a table and a column of date as yyyyMMdd in another table,
which is month end value.
I want to compare both in a query where I can't perform any action on 2nd one.
is there any way to convert yyyyMM to end of month as yyyyMMdd?
It's a total hack, but you can do this:
DECLARE #BadDate CHAR(6) = '202004';
SELECT EOMONTH(#BadDate + '01');
Answer is:
2020-04-30
You can also try the following:
DECLARE #d CHAR(6) = '202004';
select format(DATEADD(s,-1,DATEADD(mm, DATEDIFF(m,0,#d+'01')+1,0)), 'yyyyMMdd')
db<>fiddle.
Related
Insert a column: received_by as text in the format of Day Month.
i.e. 25/06/2018 should be inserted as 25 June. The format dd/mm/yyyy should be converted into day month - whereby month should be written out.
You can use below select statement to get the desired return
select FORMAT(convert(datetime, '25/06/2018', 103), 'dd MMMM')
Or You can create the custom function in SQL server which will take a date in 'dd/mm/yyyy' format and return day and month as required. use below code to achieve the desired result.
create function GetDateDaynMonth(#date varchar(20))
returns varchar(20)
as
begin
declare #DaynMonth varchar (20)
SELECT #DaynMonth = FORMAT (convert(datetime, #date, 103), 'dd MMMM')
return #DaynMonth;
end
go
select dbo.GetDateDaynMonth('25/06/2018')
I want to get date from yyyy-mm-dd to yyyy-mm-dd in SQL.
Example: I have two parameter #startdate : 2015-12-28 and #enddate : 2016-01-02, and database in SQLServer, datatype is varchar(10)
DATE_ORDER
28-12-2015
30-12-1996
29-12-2016
30-12-1997
24-12-2015
27-12-1993
03-01-2016
01-01-1992
02-01-2016
etc...
Ok,now I want to get data from #startdate : 2015-12-28 and #enddate : 2016-01-02. I use SELECT * FROM TABLE_X WHERE DATE_ORDER >= #startdate AND DATE_ORDER <= #enddate . But the results are not what I expected. Here are the results I want
28-12-2015
30-12-1996
29-12-2016
30-12-1997
01-01-1992
02-01-2016
I think to solve this problem, I need to do two things :
First, get date range from #startdate to #enddate , in here 28/12/2015, 29/12/2015, 30/12/2015, 31/12/2015, 01/01/2016, 02/01/2016.
The second: get the date in database same in range 28/12, 29/12, 30/12, 31/12, 01/01, 02/01, ignoring the year.
Can you give me some ideas about this ?
Your actual format is "105-italian" find details here.
You can convert your existing VARCHAR(10)-values with this line to real datetime
SELECT CONVERT(DATETIME,YourColumn,105)
Next thing to know is, that you should not use BETWEEN but rather >=StartDate AND < NakedDateOfTheFollowingDay to check date ranges
So to solve your need Get date-range from 2015-12-28 to 2016-01-02 you might do something like this:
DECLARE #Start DATETIME={d'2015-12-28'};
DECLARE #End DATETIME={d'2016-01-02'};
SELECT *
FROM YourTable
WHERE CONVERT(DATETIME,YourDateColumn,105)>=#Start AND CONVERT(DATETIME,YourDateColumn,105)<#End+1
Attention Be aware, that the conversion lets your expression be not sargable. No index will be used.
Better was to store your date as correctly typed data to avoid conversions...
Try this query
SET DATEFIRST 1
DECLARE #wk int SET #wk = 2
DECLARE #yr int SET #yr = 2011
--define start and end limits
DECLARE #todate datetime, #fromdate datetime
SELECT #fromdate = dateadd (week, #wk, dateadd (YEAR, #yr-1900, 0)) - 4 -
datepart(dw, dateadd (week, #wk, dateadd (YEAR, #yr-1900, 0)) - 4) + 1
SELECT #todate = #fromdate + 6
;WITH DateSequence( Date ) AS
(
SELECT #fromdate AS Date
UNION ALL
SELECT dateadd(DAY, 1, Date)
FROM DateSequence
WHERE Date < #todate
)
--select result
SELECT * FROM DateSequence OPTION (MaxRecursion 1000)
So, after the 2nd or 3rd edit, it slowly becomes clear, what you want (i hope).
So you REALLY WANT to get the dates with the year beeing ignored.
As someone pointed out already, date-values are stored internally not as string, but as internal datatype date (whatever that is in memory, i don't know).
If you want to compare DATES, you cannot do that with ignorance of any part. If you want to, you have to build a NEW date value of day and month of given row and a hard coded year (2000 or 1 or whatever) for EVERY row.
SELECT * FROM TABLE_X WHERE convert(date,'2000' + substring(convert(char(8),convert(datetime, 'DATE_ORDER', 105),112),5,4),112) >= #startdate AND convert(date,'2000' + substring(convert(char(8),convert(datetime, 'DATE_ORDER', 105),112),5,4),112) <= #enddate
If your startdate and enddate go OVER sylvester, you have to do 2 queries, on from startdate to 1231, one from 0101 to enddate.
How do I convert a numbers in the columns with values like 20160912 into date formats of the form 09/12/2016 and order them by the dates in the date format.
You can use cast and convert built-in functions. Depending on what type is 20160912 you can do following.
A) int
declare #d int=20160912
select convert(varchar(20),convert(date,convert(varchar,#d)),101)
--step by step
declare #dStr varchar(20)
set #dStr = convert(varchar,#d) --'20160912'
-- or = cast(#d as varchar)
declare #dDate date --or datetime
set #dDate = convert(date, #dStr) --2016-09-12 (this is external representation)
--show in MM/dd/yyyy format
select convert(varchar(20), #dDate, 101) --magic 101 for MM/dd/yyyy
--09/12/2016
B) varchar just omit innermost conversion
I have a RegDate column of nvarchar(max) type in my table in which dates are stored in mm/dd/yyyy (5/22/2015 11:09:39 PM) and dd-mm-yyyy (19-05-2015 22:55:05) format. I want to get all these entries in one format i.e. dd/mm/yyyy. I tried to convert it by using
Convert(varchar(10),cast(vr.RegDate as DATETIME),105) as RegistrationDate
but it gives following error:
The conversion of a nvarchar data type to a datetime data type resulted in an out-of-range value.
Please help me regarding this problem.
You need to determine the format of the value you are converting before you can convert it. If it's simply between those two formats, you can simply search for - to determine it's format.
I would also suggest storing the value in a datetime column as opposed to a varchar, and if you can't do that for whatever reason, you should definitely store it in an ISO format: YYYY-MM-DD HH:MM:SS.
Here's a sample that uses a case statement to provide optional formatting of your two date formats, using the presence of the - character:
CREATE TABLE #temp ( RegDate VARCHAR(50) )
INSERT INTO #temp
( RegDate )
VALUES ( '5/22/2015 11:09:39 PM' ),
( '19-05-2015 22:55:05' )
SELECT CASE WHEN CHARINDEX('-', RegDate) != 0
THEN CONVERT(DATETIME, RegDate, 105)
ELSE CONVERT(DATETIME, RegDate, 101)
END AS FormattedToDate
FROM #temp
DROP TABLE #temp
Produces:
FormattedToDate
2015-05-22 23:09:39.000
2015-05-19 22:55:05.000
I am using the following way to compare two dates:
if CONVERT(varchar(20), #ScheduleDate, 101) >= CONVERT(varchar(20), #CurrentDateTime, 101)
This is working fine for the current year, but when the comes in yearly like one date is 12/31/2012 and 1/1/2013 then its not working.
Please help me how can I resolve this.
why do you comparing strings?
you can compare dates
if #ScheduleDate >= #CurrentDateTime
but if your date contains time, I usually do
if convert(nvarchar(8), #ScheduleDate, 112) >= convert(nvarchar(8), #CurrentDateTime, 112)
112 datetime format is YYYYMMDD so it's good for compare dates
You have to remember that string comparison is from left to right, so "1/...." is smaller than "12/...".
You need to use DATETIME comparisons, not string comparison.
Something like
DECLARE #ScheduleDate DATETIME = '1/1/2013',
#CurrentDateTime DATETIME = '12/31/2012'
IF (#ScheduleDate >= #CurrentDateTime)
BEGIN
SELECT #ScheduleDate, #CurrentDateTime
END
DECLARE #ScheduleDateString VARCHAR(20) = '1/1/2013',
#CurrentDateTimeString VARCHAR(20) = '12/31/2012'
IF (CONVERT(DATETIME,#ScheduleDateString,101)>=CONVERT(DATETIME,#CurrentDateTimeString,101))
BEGIN
SELECT CONVERT(DATETIME,#ScheduleDateString,101),CONVERT(DATETIME,#CurrentDateTimeString,101)
END
SQL Fiddle DEMO
Note that if the variables are already datetimes, you do not need to convert them.
Assuming that both variables are currently DateTime variables, can't you just compare them without converting to strings?
declare #ScheduleDate DATETIME, #CurrentDateTime DATETIME
SET #ScheduleDate = '1 Jan 2013'
SET #CurrentDateTime = GetDate()
IF (#ScheduleDate >= #CurrentDateTime)
BEGIN
SELECT 'Do Something'
END
ELSE
BEGIN
SELECT 'Do Something Else'
END
when you use CONVERT(nvarchar(8), #ScheduleDate, 112) function it's return string instead of date.
so,
Use "112" DateFormat in Sql Server it's return string in "YMD" format without any sepration.
compare that string in your query and get desire output.
Such as "if CONVERT(nvarchar(8), #ScheduleDate, 112) >= CONVERT(nvarchar(8), #CurrentDateTime, 112)"
I would not use CONVERT to compare formatted strings. It is slow (well, more like microseconds, but still)
I use a UDF for SQL prior to version 2008
CREATE FUNCTION [dbo].[DateOnly] (#Date DateTime)
RETURNS Datetime AS
BEGIN
Return cast (floor (cast (#Date as float)) as DateTime)
END
and for versions >=2008 this approach
select convert(#MyDateTime as DATE)
Of course, you can compare datetime values directly, but to know whether two datetime values are on the same date (ignoring the time component), the above versions have proven to be effectivy.
Date : From and To with following format
from_Date# = #dateformat("#form.from#", "mm/dd/yyyy")
to_Date# = #dateformat("#now()#" + 1, "mm/dd/yyyy")
In SQL Statement
WHERE a.DateCreated >= CAST ('#from_date#' AS DATE) and a.DateCreated <= CAST('#to_date#' AS DATE)
This is working fine without any cast of original date time column