How to print out multiple rows of XML values using SQL - sql-server

Question

I have a database called Companies.
There is a table within Companies called Employees.
Within Employees there is a column that contains an XML response. The Column is called Data.
The XML Response looks like this
<Employee>
<Tenure>7</Tenure>
<Age>55</Age>
<OfficesVisited>
<int>1132</int>
<int>3345</int>
<int>7534</int>
</OfficesVisited>
</Employee>
What I would like my sql query to print out is:
OfficesVisited
1132
3345
7534
What I am currently getting is 113233457534
I am using this sql query:
use Companies
SELECT Employees.Data.query('(/Employee/OfficesVisited/int/text())') as OfficesVisited
FROM Employees
Where Employee.Employee_ID = 65035277
I've tried using OUTER APPLY and CROSS APPLY and I can get it into 3 rows but all three rows look like the above.
Can Anyone help?
Thanks!

Answer 1

Please try the following. It shows how to use .nodes() and .value() XML methods correctly.
SQL
-- DDL and sample data population, start
DECLARE #tbl TABLE (ID INT IDENTITY PRIMARY KEY, [data] XML);
INSERT INTO #tbl ([data]) VALUES
(N'<Employee>
<Tenure>7</Tenure>
<Age>55</Age>
<OfficesVisited>
<int>1132</int>
<int>3345</int>
<int>7534</int>
</OfficesVisited>
</Employee>')
, (N'<Employee>
<Tenure>77</Tenure>
<Age>58</Age>
<OfficesVisited>
<int>7777</int>
<int>8888</int>
</OfficesVisited>
</Employee>')
, (N'<Employee>
<Tenure>90</Tenure>
<Age>50</Age>
<OfficesVisited>
<int>1111</int>
</OfficesVisited>
</Employee>');
-- DDL and samplex data population, end
SELECT c.value('(./text())[1]','INT') AS OfficesVisited
FROM #tbl AS tbl
CROSS APPLY tbl.[data].nodes('/Employee/OfficesVisited/int') AS t(c)
WHERE id IN (1,2);
Output
+----------------+
| OfficesVisited |
+----------------+
| 1132 |
| 3345 |
| 7534 |
| 7777 |
| 8888 |
+----------------+