C Unhandled exception 0xC0000094: Integer division by zero - c

Question

I have been given this error for two days straight, and I have worked on it for about three hours, altogether. When I run it, it will tell me how many $10 bills I need but just stops at the $5 line and gives me this exception every time.
#define _CRT_SECURE_NO_WARNINGS 'code'
#include <stdio.h>]
#include <stdlib.h>
#include "math.h"
int main()
{
int ten = 10;
int five = 5;
int one = 1;
float quarter = .25;
float dime = .10;
float nickel = .05;
float penny = .01;
double money=0;
printf("Please enter a monetary amount:");
scanf_s("%lf", &money);//scanning the entry in, and & is allowing it to be entered
//money is the input number
printf("You entered: %lf \n", money);//creates too many zeroes but for now move on
ten = money / ten;//dividing the change = 10, and then
money = (int) money % ten;//this determines how many tens there are in the mix
//casted it because it only needs to be an integer not a double
printf("$10 : %d \n", ten);//printing an integer of how many tens are needed to make up money
five = money / five;//dividing the change = 10, and then
money = (int) money % five;//this determines how many tens there are in the mix
//casted it because it only needs to be an integer not a double
printf("$5 : %d \n", five);
//first problemm I had was putting in const, and that gave me a bajillion errors
return(EXIT_SUCCESS);
}

Answer 1

The error that you have mentioned will be shown if you divide a number by zero.just like hanie mentioned in her answer but in your case i don't see a line were you are dividing a number by zero but you have some lines were you overwrite the ten and five variables using modulo operator i guess it might be throwing the error.
I am posting a modified version of your code. Hope it helps you.
#define _CRT_SECURE_NO_WARNINGS 'code'
#include <stdio.h>
#include <stdlib.h>
#include "math.h"
int main()
{
int tens = 0;
int fives = 0;
double money=0;
printf("Please enter a monetary amount:");
scanf("%lf", &money);
printf("You entered: %lf \n", money);
tens = money / 10;
printf("$10 : %d \n", tens);
money = money - tens * 10;
fives = money / 5;
printf("$5 : %d \n", fives);
money = money - fives * 5;
return(EXIT_SUCCESS);
}
Sample Input and Output
Please enter a monetary amount:125
You entered: 125.000000
$10 : 12
$5 : 1
Please enter a monetary amount:123
$10 : 12
$5 : 0

Answer 2

Note that most implementations of floating point math will follow a standard (e.g. IEEE 754), in which case operations like divide-by-zero will have consistent results and the C standard says the operation is undefined.
before doing division you need to do something like this:
if(denominator != 0)
a = a / denominator;
or
if(denominator != 0)
a = a % denominator;