How to modify code to match output Linux - c

Question

Code below outputs child and parents PID output however need it to look more like the sample output below. How could I modify my code to allow this to happen.
Any help is greatly appreciated.
parent process: counter=1
child process: counter=1
parent process: counter=2
child process: counter=2
The code is (edited to fix missing semicolon and make more readable):
#include<stdio.h>
#include<unistd.h>
#include<stdlib.h>
int main(void) {
int pid;
pid = fork();
if (pid < 0)
{
printf("\n Error ");
exit(1);
}
else if (pid == 0)
{
printf("\n Child Process ");
printf("\n Pid is %d ", getpid());
exit(0);
}
else
{
printf("\n Parent process ")
printf("\n Pid is %d ", getpid());
exit(1);
}
}

Answer 1

You have a missing ; in your code, so it wouldn't compile cleanly. Also, there is no loop outputting the text that you require.
Consider instead the following:
#include <stdio.h>
#include <stdlib.h>
#include <unistd.h>
int
main()
{
pid_t pid;
char *child = "child";
char *parent = "parent";
char *me;
pid = fork();
if (pid < 0) {
perror("fork()");
exit(EXIT_FAILURE);
} else if (pid == 0)
me = child;
else
me = parent;
for (int i = 0; i < 2; ++i)
printf("%s: counter is %d\n", me, i + 1);
return EXIT_SUCCESS;
}
This calls fork() and detects whether the current process is the child or the parent. Depending on which it is, we point me to the correct string and enter a short loop that just prints our string and the counter.
The output may be
parent: counter is 1
parent: counter is 2
child: counter is 1
child: counter is 2