Pointer pointing older address while printing the array elements through loop - c

Question

I want to read array elements defined in main function through another user defined function. The array is 2D and it shows the first three elements correctly but as next loop starts the address pointed by that pointer is 2 step back from the intended address. Why's that?
Here is the main function calling the frame() function where the problem is:
void main(){
char dec,player[2][20];
int i,counter=0,palo,winner=0;
for(i=0;i<2;i++){
printf("Enter Player%d's name: ",(i+1));
scanf("%s",player[i]); //ASK PLAYER NAME
}
startAgain: //GAME RESTART POINT
system("cls");
palo=0;
char spot[][3]={"123","456","789"};
//------------------MAIN GAME AREA-------------------------------
for(counter=0;counter<9;counter++,palo++){
frame(*spot);
read(&palo,*spot,*player);
palo %=2;
}
}
Here is the frame() function:
void frame(char *count){
int i,j;
printf("\t\t\t");
line(24);
for (i = 0; i < 3; i++){
printf("\t\t\t");
for (j = 0; j < 3; j++){
printf("| %c ",(*(count+i)+j));
}
printf("|\n\t\t\t");
line(24);
}
}
The intended output is :
1 2 3
4 5 6
7 8 9
What it displays:
1 2 3
2 3 4
3 4 5

Answer 1

Make life easier for yourself and others, use normal array indexing instead of pointer arithmetic.
for(counter=0;counter<9;counter++,palo++){
frame(spot);
read(&palo,spot,player);
palo %=2;
}
...
void frame(char count[][3]){
int i,j;
printf("\t\t\t");
line(24);
for (i = 0; i < 3; i++){
printf("\t\t\t");
for (j = 0; j < 3; j++){
printf("| %c ",count[i][j]);
}
printf("|\n\t\t\t");
line(24);
}
}