Compare two binary files in C - c

Question

I am writing a program to compare two binary files and plot the first difference. I want to read 16 bytes of data from each file continuously and compare them. For that I am storing 16 bytes from both file into char *buffer1, buffer2. When I print the output I am getting that buffer1 has both the data of file1 and file2.
The code is as follows:
#include <stdio.h>
#include <string.h>
#include <stdlib.h>
void printConversion(char *buf1, char *buf2) {
size_t len = strlen(buf1);
char *binary = malloc(len * 8 + 1);
binary[0] = '\0';
for (size_t i = 0; i < len; ++i) {
char ch = buf1[i];
for (int j = 7; j >= 0; --j) {
if (ch & (1 << j)) {
strcat(binary,"1");
} else {
strcat(binary,"0");
}
}
}
printf("File1: %s\t", binary);
free(binary);
printf("File2:");
for (int i = 0; i < sizeof(buf2); i++) {
printf("%x", buf2[i] - '0');
}
}
void fileRead(FILE *fp, char *buf, int count) {
fseek(fp, count, SEEK_SET);
fread(buf, 1, 16, fp);
}
int fileSize(FILE *fp) {
fseek(fp, 0, SEEK_END);
int size = ftell(fp) + 1;
return size;
}
int main(int argc, char *argv[]) {
printf("***Binary File Comparator***\n ");
int count = 0;
int index = 0;
char buffer1[16];
char buffer2[16];
char buffer3[16];
char buffer4[16];
// Invalid Number of Arguments
if (argc < 3 || argc > 3) {
printf("Invalid Number of Arguments\n");
}
FILE *fp1, *fp2;
fp1 = fopen(argv[1], "rb");
int size = fileSize(fp1);
int size1 = size;
fclose(fp1);
while (size > 1) {
fp1 = fopen(argv[1], "rb");
fileRead(fp1, buffer1, count);
fclose(fp1);
fp2 = fopen(argv[2], "rb");
fileRead(fp2, buffer2, count);
if (size1 < count) {
int lastSize = count - size1;
count = count + lastSize;
fclose(fp2);
} else {
count = count+16;
fclose(fp2);
}
**printf("buffer1:%s\tbuffer2:%s\n", buffer1, buffer2)**;
size = size - 16;
int result = strcmp(buffer1, buffer2);
if (result != 0) {
for (int i = 0; i < sizeof(buffer1); i++) {
if (buffer1[i] != buffer2[i]) {
int count1 = (count - 16) + i;
index++;
if (index == 1) {
printf("Byte_Offset:%x\n", count1);
fp1 = fopen(argv[1], "rb");
fileRead(fp1, buffer3, count1);
fclose(fp1);
fp2 = fopen(argv[2], "rb");
fileRead(fp2, buffer4, count1);
fclose(fp2);
printConversion(buffer3, buffer4);
break;
}
} else {
continue;
}
}
}
}
}
I have tried to highlight the printf part that is printing my buffer1 and buffer2
The output is as follows:
buffer1:83867715933586928386771593358692 buffer2:8386771593358692
buffer1:49216227905963264921622790596326 buffer2:4921622790596326
buffer1:40267236116867294026723611686729 buffer2:4026723611686729
buffer1:82306223673529228230622367352922 buffer2:8230622367352922
buffer1:25869679356114222586967935611422 buffer2:2586967935611422
Can anybody help what I am doing wrong. Please point me the error and what optimization changes could be done in code. I am at learning stage your feedback will be very helpful.

Answer 1

You are complicating the task by reading 16 bytes at a time. If the goal is to indicate the first difference, just read one byte at a time from both files with getc() this way:
int compare_files(FILE *fp1, FILE *fp2) {
unsigned long pos;
int c1, c2;
for (pos = 0;; pos++) {
c1 = getc(fp1);
c2 = getc(fp2);
if (c1 != c2 || c1 == EOF)
break;
}
if (c1 == c2) {
printf("files are identical and have %lu bytes\n", pos);
return 0; // files are identical
} else
if (c1 == EOF) {
printf("file1 is included in file2, the first %lu bytes are identical\n", pos);
return 1;
} else
if (c2 == EOF) {
printf("file2 is included in file1, the first %lu bytes are identical\n", pos);
return 2;
} else {
printf("file1 and file2 differ at position %lu: 0x%02X <> 0x%02X\n", pos, c1, c2);
return 3;
}
}
In terms of efficiency, reading one byte at a time does not pose a problem if the streams are buffered. For large files, you can get better performance by memory mapping the file contents if available on the target system and for the given input streams.

Answer 2

Not an actual answer, but a word on optimisation. You can increase the speed of the program if you have a bigger buffer. Basically the larger the buffer the faster the program runs HOWEVER the speed you gain from just making it larger will increase logarithmically.
Here is a picture of a graph that will help you understand. Also, what i mentioned applies to any simmilar situation. This includes: Copying files, filling the sound buffer etc. Loading the entire file in your RAM first and operationg on it will usually be faster than loading parts of it. Ofc this is not possible with larger files but still this is what you should aim for if you want speed.
PS: I'm writting here because i don't have rep to comment.
EDIT: I came up with solution but since you did not state what you need to do with your buffer3 and buffer4 i packed it up inside a function.
If you are sure that you are only going to use 16 bytes as a buffer size, remove the nBufferSize parameter and replace the buffer dynamic allocation with a static one.
If after the execution you need the buffers, add them as parameters and keep the nBufferSize param. Keep in mind that if you intend to use them outside the function, you should also allocate them outside the function, so things don't get messy.
/** Returns 0 if files are identical, 1 if they are different and -1 if there
is an error. */
int FileCmp(char* szFile1, char* szFile2, int nBufferSize)
{
FILE *f1, *f2;
f1 = fopen(szFile1, "rb");
f2 = fopen(szFile2, "rb");
// Some error checking?
if (f1 == NULL || f2 == NULL)
return -1;
// You can check here for file sizes before you start comparing them.
// ...
// Start the comparrison.
/// Replace this part with static allocation. --------
char* lpBuffer1 = malloc(sizeof(char)*nBufferSize);
if (lpBuffer1 == NULL) // close the files and return error.
{
fclose(f1);
fclose(f2);
return -1;
}
char* lpBuffer2 = malloc(sizeof(char)*nBufferSize);
if (lpBuffer2 == NULL) // close the files, free buffer1 and return error.
{
free(lpBuffer1);
fclose(f1);
fclose(f2);
return -1;
}
/// --------------------------------------------------
while(1)
{
unsigned int uRead1 = fread(lpBuffer1, sizeof(char), nBufferSize, f1);
unsigned int uRead2 = fread(lpBuffer2, sizeof(char), nBufferSize, f2);
if (uRead1 != uRead2)
goto lFilesAreDifferent;
for(unsigned int i = 0; i < uRead1; i++)
if (lpBuffer1[i] != lpBuffer2[i])
goto lFilesAreDifferent;
if ((feof(f1) != 0) && (feof(f2) != 0))
break; // both files have nothing more to read and are identical.
goto lSkip;
lFilesAreDifferent:
free(lpBuffer1);
free(lpBuffer2);
fclose(f1);
fclose(f2);
return 1;
lSkip:;
}
// The files are the same. Close them, free the buffers and return 0.
free(lpBuffer1);
free(lpBuffer2);
fclose(f1);
fclose(f2);
return 0;
}
A simple Demo:
#define BUFFER_SIZE 16
int main(int nArgs, char** szArgs)
{
if (nArgs != 3)
{
printf("Invalid number of arguments.");
return 0;
}
int nResult = FileCmp(szArgs[1], szArgs[2], BUFFER_SIZE);
switch (nResult)
{
case 0: printf("Files [%s] and [%s] are identical.", szArgs[1], szArgs[2]); break;
case 1: printf("Files [%s] and [%s] are different.", szArgs[1], szArgs[2]); break;
case -1: printf("Error."); break;
}
return 0;
}
EDIT II: Personally, i have never used the C standard FILE library (it was either C++ fstream or pure win32 fileapi) so don't take my word here for granted but fread is the fastest function i could find (faster than fgets or fgetc). If you want even faster than this you should get into OS dependant functions (like ReadFile() for Windows).

Answer 3

chqrlie's solution using getc is absolutely the right way to do this. I wanted to address some points brought up in comments, and find it's best to do that with code. In one comment, I recommend pseudo code which could be confusing (namely, you can't write fwrite(file1...) || fwrite(file2 ...) because of the short circuit. But you can implement the idea of that with:
#include <stdio.h>
#include <string.h>
#include <stdlib.h>
/*
* Compare two files, 16 bytes at a time. (Purely to demonstrate memcmp.
* Clearly, this should be implemented with getc.)
*/
FILE * xfopen(const char *, const char *);
size_t xfread(void *, FILE *, const char *);
int
main(int argc, char **argv)
{
FILE *fp[2];
size_t n[2];
char buf[2][16];
unsigned count = 0;
if(argc != 3) { return EXIT_FAILURE; }
fp[0] = xfopen(argv[1], "r");
fp[1] = xfopen(argv[2], "r");
do {
n[0] = xfread(buf[0], fp[0], argv[1]);
n[1] = xfread(buf[1], fp[1], argv[2]);
if( n[0] != n[1] || (n[0] && memcmp(buf[0], buf[1], n[0]))) {
fprintf(stderr, "files differ in block %u\n", count);
return 1;
}
count += 1;
} while(n[0]);
puts("files are identical");
return 0;
}
size_t
xfread(void *b, FILE *fp, const char *name)
{
size_t n = fread(b, 1, 16, fp);
if(n == 0 && ferror(fp)) {
fprintf(stderr, "Error reading %s\n", name);
exit(EXIT_FAILURE);
}
return n;
}
FILE *
xfopen(const char *path, const char *mode)
{
FILE *fp = strcmp(path, "-") ? fopen(path, mode) : stdin;
if( fp == NULL ) {
perror(path);
exit(EXIT_FAILURE);
}
return fp;
}