Iterate through all DBs - Get constraints in all tables - sql-server

Question

I'm trying to iterate through all databases by listing all table constraints. I've achieved the following:
DECLARE #sql nvarchar(max) = ''
SET #sql =
'
USE ?
select con.[name] as constraint_name,
schema_name(t.schema_id) + ''.'' + t.[name] as [table],
col.[name] as column_name,
con.[definition],
case when con.is_disabled = 0
then ''Active''
else ''Disabled''
end as [status]
from sys.check_constraints con
left outer join sys.objects t
on con.parent_object_id = t.object_id
left outer join sys.all_columns col
on con.parent_column_id = col.column_id
and con.parent_object_id = col.object_id
order by con.name
'
PRINT #sql
EXEC sp_MSforeachdb #sql
I would like to have the query UNION all of my results in one clean select.
Can anyone help?
Using SQL Server 2016.

Answer 1

One way is to insert the intermediate results into a temp table. Below is an example that also includes the database name in the results.
CREATE TABLE #results (
[database_name] sysname
,[constraint_name] nvarchar(128)
,[table] nvarchar(257)
,[column_name] nvarchar(128)
,[definition] nvarchar(max)
,[status] varchar(8)
);
DECLARE #sql nvarchar(max) = ''
SET #sql =
N'
USE [?];
INSERT INTO #results
select
N''?'' as database_name,
con.[name] as constraint_name,
schema_name(t.schema_id) + ''.'' + t.[name] as [table],
col.[name] as column_name,
con.[definition],
case when con.is_disabled = 0
then ''Active''
else ''Disabled''
end as [status]
from sys.check_constraints con
left outer join sys.objects t
on con.parent_object_id = t.object_id
left outer join sys.all_columns col
on con.parent_column_id = col.column_id
and con.parent_object_id = col.object_id;
';
PRINT #sql;
EXEC sp_MSforeachdb #sql;
SELECT * FROM #results;