What am I doing wrong in passing a struct around in C? - c

So I am working on a project in C that requires that I pass pointers to a struct into functions. The project is structured as follows:
struct structName {
unsigned short thing2;
char thing1[];
};
void function_1(struct structName *s) {
strcpy(s->thing1, "Hello");
printf("Function 1\n%s\n\n", s->thing1); // prints correctly
}
void function_2(struct structName *s) {
// can read thing2's value correctly
// thing1 comes out as a series of arbitrary characters
// I'm guessing it's an address being cast to a string or something?
printf("Function 2\n%s\n\n", s->thing1); // prints arbitrary characters ('É·/¨')
}
int main() {
struct structName s;
function_1(&s);
printf("Main\n%s\n\n", s.thing1);
function_2(&s);
printf("Main 2\n%s\n\n", s.thing1);
}
This code outputs the following:
Function 1
Hello
Main
Hello
Function 2
É·/¨
Main 2
É·/¨
Obviously, the program has more than just what I've written here; this is just a simplified version; so if there's anything I should check that might be causing this let me know. In all honesty I reckon it's probably just a stupid rookie error I'm making somewhere.
[EDIT: Seems like s.thing1 is being mutated in some way in the call to function_2(), since the odd value is replicated in main() - I should point out that in my program the printf()s are located right before the function call and in the first line of the function, so there's no chance that it's being written to by anything I'm doing. I've updated the example code above to show this.]
Thanks in advance!

The structure contains a flexible member at its end, if you declare a static object with this type, the length of this member will be zero, so strcpy(s->thing1, "Hello"); will have undefined behavior.
You are supposed to allocate instances of this type of structure with enough extra space to handle whatever data you wish to store into the flexible array.
Here is an example:
#include <stdio.h>
#include <stdlib.h>
#include <string.h>
typedef struct pstring {
size_t length;
char data[];
} pstring;
pstring *allocate_pstring(const char *s) {
size_t length = strlen(s);
pstring *p = malloc(sizeof(*p) + length + 1);
if (p != NULL) {
p->length = length;
strcpy(p->data, s);
}
return p;
}
void free_pstring(pstring *p) {
free(p);
}
int main() {
pstring *p = allocate_pstring("Hello");
printf("Main\n%.*s\n\n", (int)p->length, p->data);
free_pstring(p);
return 0;
}

Related

Automatic generation of struct printing function in C

I have many programs where structs are defined. And each time, I have to create a function to print the members. For example,
typedef struct {
char name[128];
char address[1024];
int zip;
} myStruct;
void printMyStruct(myStruct myPeople) {
printf("%s\n",myPeople.name);
printf("%s\n",myPeople.address);
printf("%d\n",myPeople.zip);
}
int main()
{
myStruct myPeople={"myName" , "10 myStreet", 11111};
printMyStruct(myPeople);
}
I know that reflection is not supported in C. And so, I write these printing functions for each struct I defined.
But, I wonder if it exists any tricks to generate automatically these printing functions. I would understand that I have to modify a little bit these functions. But, if a part of the job is done automatically, it would be great.
(This example is simple, sometimes struct are nested or I have array of structs or some fields are pointers, ...)
You can of-course print structs, but expect a lot of non-readable output:
#include <stdio.h>
#include <ctype.h>
struct example {
int x;
int y;
char c;
};
#define NOT_PRINTABLE "Not Printable"
void print_structure(const char *structure, size_t size) {
for (size_t i = 0; i < size; i++) {
printf("%ld)\t%.2X: %.*s\n", i, structure[i],
(isprint(structure[i]) ? 1 : sizeof(NOT_PRINTABLE) - 1),
(isprint(structure[i]) ? &structure[i] : NOT_PRINTABLE));
}
}
int main(int argc, char **argv) {
struct example a;
a.x = 5;
a.y = 6;
a.c = 'A';
print_structure((char *)&a, sizeof(struct example));
return 0;
}
But the issue is that, it will print the structs as it is represented in memory. So 4 byte (32 bit) integer 1 will be represented with 4 bytes, not the char '1'.
And due to the way pointers work, you cannot make out if a member is a pointer or a non-pointer.
Another issue is that structures have padding to help with alignment, and better/efficent use of memory. So you would see a lot of 0x00 in the middle.
Remember that C is a compiled language.
let's consider to use https://copilot.github.com/. it's great.
this is what i have with copilot
typedef struct {
char name[128];
char address[1024];
int zip;
} myStruct;
//print struct myStruct >> auto generate by codepilot after you type a comment `print struct myStruct`
void printStruct(myStruct *s) {
printf("name: %s\n", s->name);
printf("address: %s\n", s->address);
printf("zip: %d\n", s->zip);
}

C array of struct issues

#include <stdlib.h>
#include <stdio.h>
#include <string.h>
struct individual {
char name[32];
int stats[7];
char role;
};
void create_array(struct individual **array){
*array = malloc(sizeof(struct individual)); //allocate initial memory space
}
void resize_array(struct individual **array, unsigned char num) {
printf("%d\n", *array);
*array = realloc(*array, num * sizeof(struct individual));
printf("%d\n", *array);
printf("resize success\n");
}
void problem(struct individual **f_array, unsigned char *f_num) {
*f_num = 2;
printf("%d\n", *f_array);
resize_array(f_array, *f_num);
printf("%d\n", *f_array);
strcpy(f_array[*f_num - 1]->name, "test value"); //CRASH LINE
}
int main() {
unsigned char f_num = 0;
struct individual *f_array;
create_array(&f_array);
problem(&f_array, &f_num);
}
This code crashes on the line marked "CRASH LINE". While it is not shown here, doing this same code setting (*f_num = 1) does not result in an error. While passing *f_array as itself (with appropriate alterations to the code in problem) does not result in an error, the values given after problem is exited result in nonsense being given, as the pointer reverts to it's pre-resize state. Any help appreciated.
The problem is the line accessing that value.
The line should read like this:
strcpy((*f_array)[*f_num - 1].name, "test value"); // doesn't crash any more :)
To break it down a little bit:
f_array is a pointer to the array of structs, need to dereference it before indexing
[*f_num - 1] accesses element 1 of the array.

How to use structs, pointers and a function in C?

I have learned how to use functions and structs and pointers. I want to combined them all into one. But the code that I write doesn't seem to work. The compiler tells me the test is an undeclared identifier. Here is the code:
#include <stdio.h>
#include <stdlib.h>
struct character
{
int *power;
};
void test (use_power)
int main ()
{
test (use_power)
printf("%d\n",*power);
return 0;
}
void test ()
{
int use_power = 25;
struct character a;
a.power = &use_power;
}
Your code has many mistakes it can't even compile
Multiple missing semicolons.
Implicit declaration of test() here
test (use_power)
with a missing semicolon too.
power is not declared in main().
This line
void test use_power()
does not make sense and is invalid, and also has no semicolon.
The a instance in test() defined at the end is local to test() and as such will be deallocated when test() returns. The use_power int, has exactly the same problem and trying to extract it's address from the function is useless because you can't access it after the function has returned.
I have no idea what you were trying to do, but this might be?
#include <stdio.h>
#include <stdlib.h>
struct character {
int *power;
};
/* Decalre the function here, before calling it
* or perhaps move the definition here
*/
void test(struct character *pointer);
/* ^ please */
int
main(void) /* int main() is not really a valid signature */
{
struct character instance;
test(&instance);
if (instance.power == NULL)
return -1;
printf("%d\n", *instance.power);
free(instance.power);
return 0;
}
void
test(struct character *pointer)
{
pointer->power = malloc(sizeof(*pointer->power));
if (pointer->power != NULL)
*pointer->power = 25;
}
Your code seems to be wrong. Your definition for test contains no arguments as
void test ()
{
int use_power = 25;
struct character a;
a.power = &use_power;
}
but your prototype contains one argument
void test (use_power)
which is wrongly put. First there are no semicolons; at the end of your prototype declaration, secondly by looking at your code, use_power is a variable and not a datatype so it cannot be present solely in a function declaration.
You will get an argument mismatch error.
You have used the line in main()
printf("%d\n",*power);
which is absolutely wrong. you cannot access any member of a structure without a structure variable.
And again, you have not mentioned the; after your call to the incorrect test()before this line
As you have not put your question so properly, I must figure out what you wish to achieve. I bet you want to hold the address of a integer in the pointer member of a structure and then print its value.
Below is a code snippet which will work as you desire.
#include <stdio.h>
#include <stdlib.h>
struct character
{
int *power;
};
struct character a; //define a structure variable
void test ();
int main ()
{
test ();
printf("%d\n",*(a.power)); // print the member of structure variable a
return 0;
}
void test ()
{
int use_power = 25;
a.power = &use_power;
}
example
#include <stdio.h>
struct character {
int *power;
};
void test(struct character *var);
int main (void){
struct character use_power;
int power = 5;
use_power.power = &power;
test(&use_power);
printf("%d\n", power);
return 0;
}
void test(struct character *var){
int use_power = *var->power;
*var->power = use_power * use_power;
}

Sample program using Function Pointer and structures.

I created a structure and wanted to assign the values to a Function Pointer of another structure. The sample code I wrote is like below. Please see what else I've missed.
#include <stdio.h>
#include <string.h>
struct PClass{
void *Funt;
}gpclass;
struct StrFu stringfunc;
struct StrFu{
int a ;
char c;
};
Initialise(){
}
main()
{
stringfunc.a = 5;
stringfunc.c = 'd';
gpclass.Funt = malloc(sizeof(struct StrFu));
gpclass.Funt = &stringfunc;
memcpy(gpclass.Funt,&stringfunc,sizeof(struct StrFu));
printf("%u %u",gpclass.Funt->a,gpclass.Funt->c);
}
There are several problems:
A function pointer is not the same as void *, in fact you cannot rely on being able to convert between them.
You shouldn't cast the return value of malloc() in C.
You shouldn't call malloc(), then overwrite the returned pointer.
You don't need to use malloc() to store a single pointer, just use a pointer.
You shouldn't use memcpy() to copy structures, just use assignment.
There are two valid main() prototypes: int main(void) and int main(int argc, char *argv[]), and you're not using either.
there is lots of problem in your code , I try to correct it ,hope it will help
#include <stdio.h>
#include <string.h>
#include <stdlib.h>
struct PClass{
void *Funt;
}gpclass;
struct StrFu{
int a ;
char c;
};
struct StrFu stringfunc;
int main()
{
stringfunc.a = 5;
stringfunc.c = 'd';
gpclass.Funt = malloc(sizeof(struct StrFu));
gpclass.Funt = &stringfunc;
memcpy(gpclass.Funt,&stringfunc,sizeof(struct StrFu));
printf("%d %c",((struct StrFu*)gpclass.Funt)->a,((struct StrFu*)gpclass.Funt)->c);
return 0;
}
it outputs
5 d

Sending a pointer of a character array to a function in C

Okay, long story short I am having some trouble:
I'm trying to send the starting address of a character array (string) to a function. Once the function gets the pointer, I'd like the function to parse through the characters one by one (in order to modify certain characters). As of right now I just set it up to print each character, but I'm still failing at that really badly.
This is what I have:
#include "system.h"
#include <stdio.h>
typedef unsigned int uint32;
typedef unsigned short uint16;
typedef unsigned char uint8;
void EXCLAIM(char *msg){
char the_char = 0;
the_char = msg;
while (the_char != 0)
{
printf(the_char);
*msg = *(msg++);
the_char = *msg;
}
}
int main(void) {
char *first_str = "This is a test. Will this work. I. am. Not. Sure...";
while (1) {
EXCLAIM(first_str);
}
}
EDIT:
Here is the updated code with what I was trying to do; send the pointer and go through each character replacing all periods with exclamation marks.
#include "system.h"
#include <stdio.h>
typedef unsigned int uint32;
typedef unsigned short uint16;
typedef unsigned char uint8;
void exclaim(char *msg){
int i;
for( i=0; msg[i]; i++ )
{
if (msg[i] == '.') {
msg[i] = '!';
}
}
printf(msg);
}
int main(void) {
char *the_sentences = "This is a test. Will this work. I. am. Not. Sure...";
while (1) {
exclaim(the_sentences);
}
}
Thank you all for your help!
Your main() is fine.
The issue lies in the pointer arithmetics inside EXCLAIM.
I can see two different versions that are useful:
Using pointer arithmetics
while (*msg)
{
printf("%c", *msg);
msg++
}
Using indexing
int i;
char the_char;
for( i=0; msg[i]; i++ )
{
printf( "%c", msg[i] );
}
Try something like this:
#include <stdio.h>
void exclaim(char * s)
{
while (*s != '\0')
{
putc(*s);
++s;
}
}
Notes:
Don't shout. Don't use all caps for anything but preprocessor macros.
Print characters, not strings.
No need to make another copy. The function argument is already a local variable that you can use directly.
You should use:
the_char = *msg;
not:
the_char = msg;
*msg = *(msg++);
What are you trying to do with this line of code? Do you understand what it actually does? First off, you need to know that msg++ changes the value of the pointer. Then you assign whatever it USED to point to to the new location. This means that the whole string will be replaced with copies of the first character in the string.
The moral of the story is to not do too much in a single line of code. You have to be especially careful with the increment operator ++. Even seasoned programmers typically put something like msg++ in its own line because it gets too complicated when you try to mix it in with a complex expression.
Something that was not mentioned but, attemping to modify a string literal is undefined behavior.
You need to change the following line from,
char *the_sentences = "This is a test. Will this work. I. am. Not. Sure...";
to an array.
char the_sentences[] = "This is a test. Will this work. I. am. Not. Sure...";
Then feel free to modify the contents inside your function.
#include <stdio.h>
void foo(char *msg)
{
for (; *msg; msg++)
if (*msg == '?')
*msg = '!';
}
int main(void)
{
char line[] = "Hello, world?? How are you tonight??";
foo(line);
puts(line);
return 0;
}

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