Add name to specific style control wpf - wpf

Question

I have a custom contextmenu:
<Window.Resources>
<ContextMenu x:Key="RowMenu" DataContext="{Binding PlacementTarget.DataContext, RelativeSource={RelativeSource Self}}">
<ContextMenu.Style>
<Style TargetType="ContextMenu">
<Setter Property="Template">
<Setter.Value>
<ControlTemplate>
<Grid Background="Transparent">
<Border Background="#1c1c1c" Height="70" Width="170" CornerRadius="10">
<StackPanel Orientation="Vertical">
<Button x:Name="openinBrowser" Click="Button_Click_1">
<Grid Width="170">
<materialDesign:PackIcon Kind="OpenInApp" VerticalAlignment="Center" Foreground="{StaticResource PrimaryHueMidBrush}" HorizontalAlignment="Left"/>
<Label FontFamily="Champagne & Limousines" Content="Action 1" FontSize="7" HorizontalAlignment="Center" Foreground="LightGray" VerticalAlignment="Center"/>
</Grid>
<Button.Style>
<Style BasedOn="{StaticResource MaterialDesignRaisedAccentButton}" TargetType="Button">
<Setter Property="Background" Value="Transparent"/>
<Setter Property="BorderBrush" Value="{StaticResource PrimaryHueMidBrush}"/>
<Setter Property="BorderThickness" Value="0"/>
</Style>
</Button.Style>
</Button>
</StackPanel>
</Border>
</Grid>
</ControlTemplate>
</Setter.Value>
</Setter>
</Style>
</ContextMenu.Style>
</ContextMenu>
</Window.Resources>
How would I be able to add a name to the Button so I can enable and disable it in my c# (without using binding), I have tried putting x:Name="" but it doesn't work, but if I add a button click it works? I am quite confused, any help would be appreciated!

Answer 1

I still say you should be doing this properly with data-binding, but if you insist...there are a couple of different ways to go about this.
Context menus aren't part of the regular visual tree, so you have to access them directly. Give your context menu a name, and then find the button by traversing its template's visual tree:
// button has to be templated in order for this to work,
// so don't try it in the parent window's constructor
// (add a this.contextMenu.Loaded handler instead if you have to)
var button = this.contextMenu.Template.FindName("openinBrowser", this.contextMenu) as Button;
If your visual tree is particularly complex then a faster option would be to create a boolean resource in your window's resources block:
xmlns:sys="clr-namespace:System;assembly=mscorlib"
<Window.Resources>
<sys:Boolean x:Key="ButtonEnabled">True</sys:Boolean>
</Window.Resources>
...and then bind your button to that dynamically:
<Button x:Name="openinBrowser" IsEnabled="{DynamicResource ButtonEnabled}">
This breaks your "no binding" rule though, which is why I was asking why you're so adamant about not using data-binding...you can still use it, even if you're not binding to the data context. In this scenario you set the value of that resource in your code instead:
this.Resources["ButtonEnabled"] = false;