awk split string on commas ignore if inside double quotes - arrays

Question

I know it may sounds that there are 2000 answer to this question online but I found none for this specific case (ex. -vFPAT of this and other answers) cause I need to be with split. I have to split a CSV file with awk in which there may be some values inside double quotes. I need to tell the split function to ignore , if inside "" in order to get an array of the elements.
Here what I tried based on other answers as example
cat try.txt
Hi,I,"am,your",father
maybe,you,knew,it
but,"I,wanted",to,"be,sure"
cat tst.awk
BEGIN {}
{
n_a = split($0,a,/([^,]*)|("[^"]+")/);
for (i=1; i<=n_a; i++) {
collecter[NR][i]=a[i];
}
}
END {
for (i=1; i<=length(collecter); i++)
{
for (z=1; z<=length(collecter[i]);z++)
{
printf "%s\n", collecter[i][z];
}
}
}
but no luck:
awk -f tst.awk try.txt
,
,
,
,
,
,
,
,
,
I tried other regex expression based on other similar answer but none works for this particular case.
Please note: double quoted fields mat and may not be present, may be more than one, and without fixed position/length!
Thanks in advance for any help!

Answer 1

gnu awk has a function called patsplit that lets you do a split using an FPAT pattern:
$ awk '{ print "RECORD " NR ":"; n=patsplit($0, a, "([^,]*)|(\"[^\"]+\")"); for (i=1;i<=n;++i) {print i, "|" a[i] "|"}}' file
RECORD 1:
1 |Hi|
2 |I|
3 |"am,your"|
4 |father|
RECORD 2:
1 |maybe|
2 |you|
3 |knew|
4 |it|
RECORD 3:
1 |but|
2 |"I,wanted"|
3 |to|
4 |"be,sure"|

Answer 2

If Python is an alternative, here is a solution:
try.txt:
Hi,I,"am,your",father
maybe,you,knew,it
but,"I,wanted",to,"be,sure"
Python snippet:
import csv
with open('try.txt') as f:
reader = csv.reader(f, quoting=csv.QUOTE_ALL)
for row in reader:
print(row)
The code snippet above will result in:
['Hi', 'I', 'am,your', 'father']
['maybe', 'you', 'knew', 'it']
['but', 'I,wanted', 'to', 'be,sure']