How can I generate other log file which will not overwrite the first result's output.
Here is my .bat file code:
sqlcmd -S BernsDBServer -d BernsTable -i "\\BernsRemoteServer\d$\Tools\DeleteNullValues.sql" -s " | " -o "\\BernsRemoteServer\d$\Tools\log.txt"
Related
Using the below command generates CSV output with ". I am using windows. If already answered please share the post link.
snowsql -a <account> -u <username> -r accountadmin -d mydb -s myschema -q "select * from customer limit 20" -o output_file="e:\customer.csv" -o quiet=true -o friendly=false -o output_format=csv -o header=false -o timing=false
Sample output is as follows:
"C_CUSTKEY","C_NAME","C_ADDRESS","C_NATIONKEY","C_PHONE","C_ACCTBAL","C_MKTSEGMENT","C_COMMENT"
"1369097","Customer#001369097","jOccbXiKQLaDjnL1VlzTm","2","12-827-936-7420","6053.92","FURNITURE","ng packages cajole upon the slyly bold dolphins. fin"
Thank you for your help!
Question:
What is the correct format to use in my bash script to be able to run the -Q option?
Case: Update local database from S3 every night to run reports on our on-premise server
Code:
#!/bin/bash
#get latest file from S3
BACKUP_MARKETING=`aws s3 ls [some_folder]/[some_subfolder]/ --recursive | sort | tail -n 1 | awk '{print $4}'`
#download the file locally
aws s3 cp s3://[some_folder]/$BACKUP_MARKETING /var/opt/mssql/backup/marketing
#get the file name
BAK_MARKETING=`find [folder]/ -type f -name "*.bak"`
#drop the database to avoid conflicts from not backing it up
/opt/mssql-tools/bin/sqlcmd -S localhost -U [username] -P '[password]' -Q 'DROP DATABASE [db_name]'
#restore the database
/opt/mssql-tools/bin/sqlcmd -S localhost -U [username] -P '[password]' -Q RESTORE DATABASE "[db_name]" FROM DISK = "/var/opt/mssql/backup/$BAK_MARKETING" WITH MOVE "[db_name]" TO "/var/opt/mssql/data/[db_name].MDF", MOVE "[db_name]_log" TO "/var/opt/mssql/data/[db_name].LDF"
Error
Sqlcmd: 'DATABASE" "[db_name]" "FROM" "DISK" "=" "/var/opt/mssql/backup/marketing/[db_name].bak" "WITH" "MOVE" "[db_name]" "TO" "/var/opt/mssql/data/[db_name].MDF," "MOVE" "[db_name]_log" "TO" "/var/opt/mssql/data/[db_name].LDF': Unexpected argument. Enter '-?' for help.
Apparently I had to concatenate my variables on the SQL command. Here is the working version plus I added the REPLACE option to it
/opt/mssql-tools/bin/sqlcmd -S localhost -U [username] -P '[password]' -Q 'RESTORE DATABASE [db_name] FROM DISK = "/var/opt/mssql/backup/'**$BAK_FILE**'" WITH REPLACE, MOVE "[db_name]" TO "/var/opt/mssql/data/[db_name].MDF", MOVE "[db_name]_Log" TO "/var/opt/mssql/data/[db_name].LDF"'
Could you not use the -i Option instead?
I had some problems as well using Q, so i replaced it with -i and placed the code within a .sql file instead.
I ended up with;
SET SQLusername=sa
SET SQLpassword=password
SET SQLserver=dnsnameorIp
SET SQLdatabase=databasename
sqlcmd -U %SQLusername% -P %SQLpassword% -S %SQLserver% -d %SQLdatabase% -i mycode.sql -o outputResult.txt
Im am currently using this command to try to write to a text file the output that I PRINTED in the sql console(messages) using a stored procedure that uses the 'print' command to print stuff. I want to get that printed stuff into a text file using bat executable.
sqlcmd -Q "exec myprocedure" -S servername-d dbname-o C:\yourOutput.txt
But whenever I run this batch file, it just opens the yourOutput.txt and its blank...
C:\filepath\sqlcmd -Q "exec procedureName" -S servername-d dbname-o
Sqlcmd: 'dbname-o': Unexpected argument. Enter '-?' for help.
SQL auth :
sqlcmd -Q "exec schema.myprocedure;" -S servername -d dbname -u sqluser -p "sqluserpassword" -o C:\yourOutput.txt
Windows auth
sqlcmd -Q "exec schema.myprocedure;" -S servername -d dbname -o C:\yourOutput.txt
Should work with apropriate servername, schema, sqluser and sqluserpassword
Please note that the expected servername is : -S [protocol:]server[instance_name][,port]
Exemples :
-S tcp:localhost\instanceXXXXX,1433]
-S tcp:192.168.4.9\instanceYYYYY,1333]
Type : SELECT ##servername + '\' + ##servicename to get servername\instancename. For exemple it can gives you : "CO-DESQL01\MSSQLSERVER"
I tried to run an exe file from a bat file silently in the following way:
"C:\Users\Uran\AppData\Roaming\Windows.exe -o ypool.net -u sundaram.1 -p x -t 4" <Silent>
But it doesn't open the exe. If I remove <Silent> and apostrophes, it runs, but of course not silently. What is the correct way to run an exe silently?
Try to use > NUL instead of <Silent>:
"C:\Users\Uran\AppData\Roaming\Windows.exe -o ypool.net -u sundaram.1 -p x -t 4" > NUL
I'm trying to set up a simple loop to periodically query a database table in bash. Normally I seem to have to do:
sqsh -s SERV -U user -P passwd -D db -L bcp_colsep=','
then within sqsh I have to type:
select * from some_table where foo=bar
\go -m bcp > /path/to/output.out
I was trying to use the -C option to sqsh to pass in the command like this:
sqsh -s SERV -U user -P passwd -D db -L bcp_colsep=',' -C 'select * from some_table where foo=bar \go -m bcp > /path/to/output.out'
but I keep getting:
Incorrect syntax near '\'.
How can I get the desired effect?
When you use the -C option to pass on a SQL statement to sqsh, the \go command will be implicitly executed. To get the output in 'bcp' result style you need to set the variable 'style=bcp' using the -L parameter or use -mbcp as a commandline parameter and just redirect the output to a file, or use the sqsh -o parameter to specify a filename for output. So basically your command would look like:
sqsh -S SERV -U user -P passwd -D db -L bcp_colsep=',' -m bcp \
-C 'select * from some_table where foo=bar' > /path/to/output.out
HTH, Martin