Implement stack with pointers in c - c

Question

I try to implement a simple stack in c with pointers and struct but I think I have a problem with push or print. My program prints only the first Node.
If someone could help me to solve this
Here is my code
stack.h
/***********************************************************************
* stack.h
***********************************************************************/
#include <stdbool.h>
#ifndef _STACK_H_
#define _STACK_H_
typedef struct Stack{
int value;
struct Stack* next;
}Stack;
Stack initStack();
bool push (Stack* s, int n);
int pop (Stack* s);
bool stackEmpty (Stack s);
void printStack (Stack s);
#endif
stack.c
#include <stdlib.h>
#include <stdio.h>
#include <string.h>
#include <stdbool.h>
#include "stack.h"
Stack initStack(){
Stack s = {0, NULL};
return s;
}
bool push (Stack* s, int n){
if (stackEmpty(*s)){
s->value = n;
return true;
}else{
Stack stack = {n, s};
s = &stack;
return true;
}
return false;
}
int pop (Stack* s){
int value = s->value;
s = s->next;
return value;
}
bool stackEmpty (Stack s){
if (s.value == 0 && s.next == NULL)
return true;
return false;
}
void printStack (Stack s){
Stack* b = &s;
printf("Stack : \n");
while(b != NULL){
printf("%d\n", b->value);
b = b->value;
}
main
#include <stdlib.h>
#include <stdio.h>
#include <string.h>
#include <stdbool.h>
#include "stack.h"
int main (int argc, char** argv) {
Stack stack1 = initStack();
push(&stack1, 5);
printStack(stack1);
}

Answer 1

You're taking the address of a local variable here:
Stack stack = {n, s};
s = &stack;
You need to dynamically allocate it:
Stack *stack = malloc(sizeof(*stack));
stack->value = n;
stack->next = s;
s = stack;
For consistency, I would recommend to take and return Stack * instead of Stack, and possibly rename initStack to newStack.