Position of an XML element in SQL Server 2012 - sql-server

Question

Create Table #tmp(ID int IDentity(1,1), XMLData XML)
Insert Into #tmp(XMLData)
Values('<SampleXML>
<Fruit>
<Fruits>Apple</Fruits>
<Fruits>Pineapple</Fruits>
</Fruit>
<Fruit>
<Fruits>Grapes</Fruits>
<Fruits>Melon</Fruits>
</Fruit>
</SampleXML>')
SELECT
ID,
A.x.query('data(.)') as name,
Row_Number() over(order by A.x) as number
FROM #tmp
CROSS APPLY XMLData.nodes('SampleXML/Fruit/Fruits') AS A(x)
This results into the following:
ID name number
1 Apple 1
1 Pineapple 2
1 Grapes 3
1 Melon 4
but I do want it to look like this:
ID name number
1 Apple 1
1 Pineapple 1
1 Grapes 2
1 Melon 2
I want to know in which "Fruit" element the "Fruits" were found.

Answer 1

You can use following SQL, please be aware that using "OVER XML nodes" is an undocumented and unsupported feature:
DECLARE #MyXML XML
SET #MyXML = '<SampleXML>
<Fruit>
<Fruits>Apple</Fruits>
<Fruits>Pineapple</Fruits>
</Fruit>
<Fruit>
<Fruits>Grapes</Fruits>
<Fruits>Melon</Fruits>
</Fruit>
</SampleXML>'
SELECT
Friuts.col.query('data(.)') as name,
DENSE_RANK() over(order by Friut.col) as number
FROM #MyXML.nodes('SampleXML/Fruit') AS Friut(col)
CROSS APPLY Friut.col.nodes('./Fruits') AS Friuts(col)

Answer 2

Here is another method by using a Node Order Comparison operator. Here is the link: Node Order Comparison Operators
SQL
-- DDL and sample data population, start
DECLARE #tbl TABLE(ID INT IDENTITY PRIMARY KEY, XMLData XML);
INSERT INTO #tbl (XMLData)
VALUES (N'<SampleXML>
<Fruit>
<Fruits>Apple</Fruits>
<Fruits>Pineapple</Fruits>
</Fruit>
<Fruit>
<Fruits>Grapes</Fruits>
<Fruits>Melon</Fruits>
</Fruit>
</SampleXML>');
-- DDL and sample data population, end
-- Method #1
-- by Piotr, adjusted for a table and optimized
SELECT Friuts.col.value('(./text())[1]', 'VARCHAR(30)') as [name],
DENSE_RANK() OVER(ORDER BY Friut.col) as number
FROM #tbl AS tbl
CROSS APPLY tbl.XMLData.nodes('/SampleXML/Fruit') AS Friut(col)
CROSS APPLY Friut.col.nodes('./Fruits') AS Friuts(col);
-- Method #2
-- by using a Node Order Comparison operator
SELECT ID
, col.value('let $n := . return count(../../*[. << $n])', 'INT') AS pos
, col.value('(./text())[1]', 'VARCHAR(30)') as [name]
FROM #tbl AS tbl
CROSS APPLY tbl.XMLData.nodes('/SampleXML/Fruit/Fruits') AS tab(col);
Output
+----+-----+-----------+
| ID | pos | name |
+----+-----+-----------+
| 1 | 1 | Apple |
| 1 | 1 | Pineapple |
| 1 | 2 | Grapes |
| 1 | 2 | Melon |
+----+-----+-----------+