using letters in a Switch statement - c

Question

I try to use Y and N in a switch statement but when I try to compile it I got an error what say " error: statement requires expression of integer type ('char [0]' invalid)
switch (xx) {
"
i also got a warning " warning: incompatible pointer to integer conversion passing 'char [1]' to parameter of type 'char' [-Wint-conversion]
sucheZeichen(name, imya); "
int main() {
char name[200];
printf("Please tell me your name:");
fflush(stdin);
scanf("%s", name);
printf("%s has %i letters\n", name, langeZeichne(name));
// frage
int end = 0;
char xx[0];
char imya[1];
do {
fflush(stdin);
printf("would you like to count a letter in %s (Y / N)?\n", name);
scanf("%c", xx);
switch (xx) {
case "Y":
printf("Please enter a letter\n");
scanf("%s", imya);
sucheZeichen(name, imya);
break;
case "N":
printf("Have a nice Day!");
end = 0;
break;
default:
printf("Wrong input\n");
break;
}
}while (end==0);
}

Answer 1

First of all, if you want to read a letter into xx don't use an array, and definitly not an array of size 0.
Second, your switch receive an char[] instead of a char.
Next, in the cases use chars instead of strings.
Moreover, according to the information in the question, sucheZeichen gets a char as a second parameter (or an int) so the same problem with xx as an array apply for imya as well.
Also, I added \n to the scanf so it won't read the newline character.
Your code should like like:
int main() {
char name[200];
printf("Please tell me your name:");
fflush(stdin);
scanf("%s", name);
printf("%s has %i letters\n", name, langeZeichne(name));
// frage
int end = 0;
char xx;
char imya;
do {
fflush(stdin);
printf("would you like to count a letter in %s (Y / N)?\n", name);
scanf("%c\n", &xx);
switch (xx) {
case 'Y':
printf("Please enter a letter\n");
scanf("%c\n", &imya);
sucheZeichen(name, imya);
break;
case 'N':
printf("Have a nice Day!");
end = 0;
break;
default:
printf("Wrong input\n");
break;
}
}while (end==0);
}