React Hooks - Passing ref to child to use ScrollIntoView - reactjs

Question

I have two components. A parent and a child.
Inside the parent component I have a button. If the user clicks on that button I want to do a ScrollIntoView to another button inside the child component.
I guess I want to define a reference to the childs button a so that I inside the parent button onClick can do a:
ref.scrollIntoView({block: 'end', behavior: 'smooth'});
that will scroll to the button in the child component.
Here is a minified example:
ParentComponent.jsx
import React, {useRef} from 'react';
import ChildComponent from './ChildComponent';
const ParentComponent = props => {
const childReference = useRef(null);
const onClick = () => {
childReference.scrollIntoView({block: 'end', behavior: 'smooth'});
}
return (
<>
<...some other components>
<Button onClick={onClick}>Click me to be forwarded</Button>
<ChildComponent ref={childReference}/>
</>
);
};
ChildComponent.jsx
import React from 'react';
const ChildComponent = (props, ref) => {
const { name, value, description } = props;
return (
<...some other components>
<Button ref={ref}>You should be forwarded to me</Button>
);
};
ChildComponent.propTypes = {
name: PropTypes.string.isRequired,
value: PropTypes.number,
description: PropTypes.string,
};
ChildComponent.defaultProps = {
value: 0,
description: '',
};
export default React.forwardRef(ChildComponent);
I know the above code doesn't work, it was just to illustrate what I am trying to achieve.
I have really tried every other solution I have been able to find by Googling and they all seem so easy, but none of them seem to work for my use case. I have tried using forwardRef as well, but that also doesn't fix it for me.
UPDATE
I guess I was a little vague on what's not working. I've been getting a lot of different error messages with the implementation.
The following is one of them:
Function components cannot be given refs. Attempts to access this ref will fail. Did you mean to use React.forwardRef()?
Solution
Okay. I thought I'd assemble the pieces here with the solution provided by #Vencovsky.
This is the full implementation with the two example components seen in the question:
ParentComponent.jsx
import React, { useRef } from 'react';
import ChildComponent from './ChildComponent';
const ParentComponent = props => {
const childReference = useRef(null);
const scrollIntoView = () => {
childReference.current.scrollIntoView({block: 'center', inline: 'center', behavior: 'smooth'});
}
return (
<>
<...some other component>
<Button onClick={scrollIntoView}>Click me to be forwarded</Button>
<ChildComponent ref={childReference}
</>
);
};
export default ParentComponent;
ChildComponent.jsx
import React, {forwardRef} from 'react';
import PropTypes from 'prop-types';
const ChildComponent = forwardRef((props, ref) => {
const { name, value, description } = props;
return(
<>
<...some other components>
<Button ref={ref}>You should be forwarded to me</Button>
</>
);
});
ChildComponent.propTypes = {
name: PropTypes.string.isRequired,
value: PropTypes.number,
description: PropTypes.string,
};
ChildComponent.defaultProps = {
value: 0,
description: '',
};
export default ChildComponent;

Answer 1

Edit 2:
I guess you are doing something like
const ChildComponent = (props, ref) => { ... }
ChildComponent.propTypes = { ... }
export default React.forwardRef(ChildComponent)
But what you need to do is pass propTypes after React.forwardRef, like so:
const ChildComponent = (props, ref) => { ... }
const ForwardComponent = React.forwardRef(ChildComponent)
ForwardComponent.propTypes = { ... }
export default ForwardComponent
A better way to do it would be like
// using forwarRef
const ChildComponent = React.forwarRef((props, ref) => {
const { name, value, description } = props;
return (
<...some other components>
<Button ref={ref}>You should be forwarded to me</Button>
);
});
Then you wouldn't need to change propTypes and create another component.
Edit:
As your Edit, I can see that you forgot to use React.forwardRef.
You should add
export default React.forwardRef(ChildComponent)
To your ChildComponent file (export it with forwardRef).
What is not working? Are you getting an error? You should explain better what is going on, but I will try to guess.
There is somethings that can make it not work.
You need to use ref.current.foo instead of ref.foo
As #JeroenWienk said:
It seems that your button is also a custom component. Are you sure the ref is being passed to the html button element inside there?
To use the second parameter of an functional component, you should be using React.forwardRef. e.g. export default React.forwardRef(ChildComponent)