C program using pipes hangs when trying to terminate - c

#include <stdio.h>
#include <unistd.h>
#include <stdlib.h>
#include <sys/types.h>
#include <string.h>
#include <sys/wait.h>
#include <fcntl.h>
#define MSGSIZE 64
char msgbuf[MSGSIZE];
int main() {
int p1[2];
int p2[2];
int nread;
int choice = 0;
pid_t child_a, child_b;
if (pipe(p1) == -1) {
printf("error in creating pipe\n");
exit(-1);
}
if (pipe(p2) == -1) {
printf("error in creating pipe\n");
exit(-1);
}
child_a = fork();
if (child_a == 0) {
while (1) {
dup2(p1[0], STDIN_FILENO);
read(STDIN_FILENO, msgbuf, MSGSIZE);
printf("%d receives message: %s\n", getpid(), msgbuf);
close(p1[0]);
close(p1[1]);
}
} else {
child_b = fork();
if (child_b == 0) {
while (1) {
dup2(p2[0], STDIN_FILENO);
read(STDIN_FILENO, msgbuf, MSGSIZE);
printf("%d receives message: %s\n", getpid(), msgbuf);
close(p2[0]);
close(p2[1]);
}
} else {
while (1) {
printf("<child_to_receive_msg> <message>\n");
scanf("%d %s", &choice, msgbuf);
switch (choice) {
case 1:
usleep(250);
write(p1[1], msgbuf, MSGSIZE);
break;
case 2:
usleep(250);
write(p2[1], msgbuf, MSGSIZE);
break;
default:
printf("Process does not exist");
break;
case -1:
close(p1[0]);
close(p2[0]);
printf("parent waiting");
wait(NULL);
exit(0);
}
}
}
}
return 0;
}
In the above program I have a parent making two child processes belonging to that same parent. The user writes to the parent process which pipes the message to be read by either child 1 or child 2. It keeps doing this continuously unless the user inputs -1.
The problem is that case in my switch statement doesn't get executed and instead the program hangs. I think I have my pipes closed at the correct places.

You need to send some signal to your child process to inform then to terminate before waiting for them to exit. You should define some pre-defined message which means its time for child to terminate. Check below code. Here pre-defined message is "-1". You should choose your own which doesn't conflict with your application's real data.
#include <fcntl.h>
#include <stdio.h>
#include <stdlib.h>
#include <string.h>
#include <sys/types.h>
#include <sys/wait.h>
#include <unistd.h>
#define MSGSIZE 64
char msgbuf[MSGSIZE];
int main() {
int p1[2];
int p2[2];
int nread;
int choice = 0;
pid_t child_a, child_b;
if (pipe(p1) == -1) {
printf("error in creating pipe\n");
exit(-1);
}
if (pipe(p2) == -1) {
printf("error in creating pipe\n");
exit(-1);
}
child_a = fork();
if (child_a == 0) {
while (1) {
dup2(p1[0], STDIN_FILENO);
read(STDIN_FILENO, msgbuf, MSGSIZE);
printf("%d receives message: %s\n", getpid(), msgbuf);
close(p1[0]);
close(p1[1]);
if (strcmp(msgbuf, "-1") == 0) { // check if time to end
break;
}
}
} else {
child_b = fork();
if (child_b == 0) {
while (1) {
dup2(p2[0], STDIN_FILENO);
read(STDIN_FILENO, msgbuf, MSGSIZE);
printf("%d receives message: %s\n", getpid(), msgbuf);
close(p2[0]);
close(p2[1]);
if (strcmp(msgbuf, "-1") == 0) { // check if time to end
break;
}
}
} else {
while (1) {
printf("<child_to_receive_msg> <message>\n");
scanf("%d %s", &choice, msgbuf);
switch (choice) {
case 1:
usleep(250);
write(p1[1], msgbuf, MSGSIZE);
break;
case 2:
usleep(250);
write(p2[1], msgbuf, MSGSIZE);
break;
default:
printf("Process does not exist\n");
break;
case -1:
strcpy(msgbuf, "-1");
write(p1[1], msgbuf, MSGSIZE); // send message to end
close(p1[0]);
close(p2[0]);
printf("parent waiting\n");
wait(NULL);
exit(0);
}
}
}
}
return 0;
}

First, you need to start performing error checking. Check the man page of the calls you make. Add checks in your code to detect errors. When they return an error, use perror and exit(EXIT_FAILURE);.
Second, you need to start paying attention to the values returned by read and write since they could be less than expected. These need to be called in a loop.
For example, for read, you'd use the following:
#include <errno.h>
#include <limits.h>
// Returns the number of bytes read.
// EOF was reached if the number of bytes read is less than requested.
// On error, returns -1 and sets errno.
ssize_t read_fixed_amount(int fd, char *buf, size_t size) {
if (size > SSIZE_MAX) {
errno = EINVAL;
return -1;
}
ssize_t bytes_read = 0;
while (size > 0) {
ssize_t rv = read(fd, buf, size);
if (rv < 0)
return -1;
if (rv == 0)
return bytes_read;
size -= rv;
bytes_read += rv;
buf += rv;
}
return bytes_read;
}
It would be used something like this:
ssize_t bytes_read = read_fixed_amount(fd, buf, size);
if (bytes_read < 0) {
perror("read");
exit(EXIT_FAILURE);
}
if (bytes_read == 0) {
printf("EOF reached\n");
exit(EXIT_SUCCESS);
}
if (bytes_read != size) {
fprintf(stderr, "read: Premature EOF.\n");
exit(EXIT_FAILURE);
}
Third, reading from the pipe will only return EOF once all file descriptors of the write end of the pipes have been closed.
Right after the fork, the parent should do
close(p1[0]);
close(p2[0]);
Right after the fork, child 1 should do
close(p1[1]);
close(p2[0]);
close(p2[1]);
Right after the fork, child 2 should do
close(p1[0]);
close(p1[1]);
close(p2[1]);
Fourth, there's this monstrosity:
while (1) {
dup2(p1[0], STDIN_FILENO);
read(STDIN_FILENO, msgbuf, MSGSIZE);
...
close(p1[0]);
close(p1[1]);
}
Really? Infinite loop. Attempt to repeatedly make STDIN a dup of p1[0]. Duping of a closed descriptor.
This should appear before the loop:
dup2(p1[0], STDIN_FILENO);
close(p1[0]);
Or you could skip those two call and simply read from p1[0] instead of STDIN_FILENO.
As for the infinite loop, it goes back to the second point. Check the value returned by read.
Fifth, you only wait for one child to finish, but there are two children to wait for. You need to call wait twice.

Related

C - Send input from Parent to Child and return it back

So, I'm pretty new to C programming language and I'm having some difficulty completing this exercise.
Basically, I have to fork(), then send an input string from Parent process to Child, do an uppercase function in the Child process and return it to Parent so it can print.
The pipes are still really "gibberish" but disregarding the uppercase function, I've got this:
#include <errno.h>
#include <stdio.h>
#include <stdlib.h>
#include <string.h>
#include <unistd.h>
#define READ_END 0
#define WRITE_END 1
#define BUF_SIZE 256
int main(int argc, char* argv[]) {
int fd[2];
pid_t pid;
if (pipe(fd) < 0) {
perror("pipe error");
exit(EXIT_FAILURE);
}
if ((pid = fork()) < 0) {
perror("fork error");
exit(EXIT_FAILURE);
}
else
if (pid > 0) {
int nbytes;
char line[BUF_SIZE];
/* parent writes to pipe */
close(fd[READ_END]);
snprintf(line, BUF_SIZE,
"Hello child (%d)! I'm your parent pid (%d).\n",
pid, getpid());
if ((nbytes = write(fd[WRITE_END], line, strlen(line))) < 0) {
fprintf(stderr, "Unable to write to pipe: %s\n", strerror(errno));
exit(EXIT_FAILURE);
}
close(fd[WRITE_END]);
/* wait for child and exit */
if ( waitpid(pid, NULL, 0) < 0) {
fprintf(stderr, "Unable to catch child exiting: %s\n", strerror(errno)); exit(EXIT_FAILURE);
}
/* return gracefully */
exit(EXIT_SUCCESS);
}
else {
int nbytes;
char line[BUF_SIZE];
/* child reads from pipe */
close(fd[WRITE_END]);
if ((nbytes = read(fd[READ_END], line, BUF_SIZE)) < 0 ) {
fprintf(stderr, "Unable to read from pipe: %s\n", strerror(errno));
exit(EXIT_FAILURE);
}
close(fd[READ_END]);
/* write message from parent */
write(STDOUT_FILENO, line, nbytes);
/* return gracefully */
exit(EXIT_SUCCESS);
}
}```

Writing and reading messages continuously in ipc with pipes in C

I have written a program where the parent process creates two child processes.
The parent process writes to either the first or the second child and the child reads the message.
#include <stdio.h>
#include <unistd.h>
#include <stdlib.h>
#include <sys/types.h>
#include <string.h>
#include <sys/wait.h>
#define MSGSIZE 64
char msgbuf[MSGSIZE];
int main(){
int p1[2];
int p2[2];
int nread;
int choice = 0;
pid_t child_a,child_b;
if(pipe(p1) == -1){
printf("error in creating pipe\n");
exit(-1);
}
if(pipe(p2) == -1){
printf("error in creating pipe\n");
exit(-1);
}
child_a = fork();
if (child_a == 0) {
dup2(p1[0], STDIN_FILENO);
read(STDIN_FILENO,msgbuf,MSGSIZE);
printf("%d receives message: %s\n",getpid(),msgbuf);
close(p1[0]);
close(p1[1]);
} else {
child_b = fork();
if (child_b == 0) {
dup2(p2[0], STDIN_FILENO);
read(STDIN_FILENO,msgbuf,MSGSIZE);
printf("%d receives message: %s\n",getpid(),msgbuf);
close(p2[0]);
close(p2[1]);
} else {
/* Parent Code */
// Write something to child A
while(1){
printf("<child_to_receive_msg> <message>\n");
scanf("%d %s",&choice,msgbuf);
switch(choice){
case 1:
usleep(250);
write(p1[1], msgbuf, MSGSIZE);
break;
// Write something to child B
case 2:
usleep(250);
write(p2[1], msgbuf, MSGSIZE);
break;
case -1:
usleep(250);
printf("parent waiting");
wait(NULL);
exit(-1);
break;
}
}
}
}
return 0;
}
My issue is that I want the parent to keep writing to the child process. With the above code, once it writes to child or child 2 it wont write again or at least the child process wont read it again. I don't know if it is possible to do this.
I tried putting the while loop at the beginning of the program but this causes another child process to be created every time.
Here my solution, followed by some explanation:
#include <stdio.h>
#include <stdlib.h>
#include <string.h>
#include <sys/types.h>
#include <sys/wait.h>
#include <unistd.h>
#include <assert.h>
#define MSGSIZE 64
void read_process(int fh) {
assert(-1 < fh);
char msgbuf[MSGSIZE];
ssize_t retval = 0;
while (-1 < retval) {
retval = read(fh, msgbuf, MSGSIZE);
printf("%d receives message: %s\n", getpid(), msgbuf);
close(fh);
}
}
void write_process(int fh_child_1, int fh_child_2) {
assert(-1 < fh_child_1);
assert(-1 < fh_child_2);
char msgbuf[MSGSIZE];
int choice = -1;
while (1) {
printf("<child_to_receive_msg> <message>\n");
scanf("%d %64s", &choice, msgbuf);
switch (choice) {
case 1:
write(fh_child_1, msgbuf, MSGSIZE);
break;
// Write something to child B
case 2:
write(fh_child_2, msgbuf, MSGSIZE);
break;
case -1:
printf("parent waiting");
wait(NULL);
exit(-1);
break;
}
}
}
int main() {
/* 0 will be for reading, 1 for writing */
int p1[2];
int p2[2];
pid_t pid;
if (pipe(p1) == -1) {
printf("error in creating pipe\n");
exit(-1);
}
/* Don't create 2nd pipe yet, we don't require it here and save us to
* tear it down in child 1 */
pid = fork();
if (pid == 0) {
close(p1[1]); /* not needed here */
p1[1] = -1;
read_process(p1[0]);
exit(EXIT_SUCCESS);
} else {
/* Nobody is going to read from pipe 1 here again */
close(p1[0]);
p1[0] = -1; /* Mark fh as invalid */
if (pipe(p2) == -1) {
printf("error in creating pipe\n");
exit(-1);
}
pid = fork();
if (pid == 0) {
close(p1[1]);
p1[1] = -1;
close(p2[1]);
p2[1] = -1;
/* Ensure we did not forget an fh */
assert(-1 == p1[0]);
assert(-1 == p1[1]);
assert(-1 == p2[1]);
read_process(p2[0]);
exit(EXIT_SUCCESS);
} else {
/* Parent Code */
close(p2[0]);
p2[0] = -1;
assert(-1 == p1[0]);
assert(-1 == p2[0]);
write_process(p1[1], p2[1]);
exit(EXIT_SUCCESS);
}
}
return 0;
}
As noted before, your main problem was that your children processes don't loop but read just once.
There are a few notes, I will first talk about the general ones, and then the more system programming specific ones afterwards.
Your main problem, the missing loops, was hidden below your code being a bit spaghetti.
C provides means for structuring your code, like functions.
Functions are not only there for re-using code, but can also be used to summarize your code: Instead of pasting the code for your child processes directly where you require it, shift the code to a dedicated function and just call the function. This aids greatly in understanding the basic structure of the code:
close(p1[1]); /* not needed here */
p1[1] = -1;
read_process(p1[0]);
exit(EXIT_SUCCESS);
is pretty obvious what is the basic idea, isn't it? And if you want the gory details of the read process, inspect the read_process function.
Be careful about your resources.
Allocate as few as possible, only when you need them. Free them as soon as possible and mark them as freed - see the pipe file handles.
Lastly, if you fork, the process is basically copied. You create a second process, and it is given copies/ clones of all (well, most) of the parent processes resources.
The file handles in your case, are cloned.
E.g. closing p1[0] in your child does not affect p1[0] in your parent, because they are not the same.
That also means, that immediately after forking, you should consider all the resources available and get rid of every resource you wont require immediately, like
pid = fork();
if(0 == pid) {
close(p1[1]); /* not needed here */
p1[1] = -1;
read_process(p1[0]);
exit(EXIT_SUCCESS);
}
Your first child does not require p1[1], thus close it and mark it as closed and invalid.
There is probably much more to say, but these are the points that come to my mind immediately.
Some of it might not seem clumsy, but as you get more and more experienced, and your code bases grow, you will appreciate these things, at least I do more and more every day.
As for the code, there are certainly many bugs still hiding in there, you get the basic idea though I hope ;)

Fork and Pipe program not working properly

I'm trying to code a simple fork() and pipe() program which gets input from the user and outputs it through the pipe in the childprocess. But somehow I'm not getting the result I wished to get.
The first input works fine, for example I type in "Hi" and get the result "Prozessmanager: Hi", but as soon as I try to input the next string, it crashes or somehow stops working until I input a "Q" which exits my Program.
I tried to debug it and got the result, that I'm trying to write into a broken pipe.
#include <stdio.h>
#include <stdlib.h>
#include <unistd.h>
#include <sys/types.h>
#include <sys/wait.h>
//#include <signal.h>
#define BUFSIZE 512
//int clock = 0;
//void handler(int signum) {
//clock++;
//printf("Clock: 00:00:%d\n", clock);
//}
int main(int argc, char** argv) {
pid_t prozessmanager;
pid_t reporter;
int pipefd[2];
int status;
char str[BUFSIZE];
char buf[BUFSIZE];
if ((pipe(pipefd)) == -1) {
perror("pipe() error");
exit(1);
}
if ((prozessmanager = fork()) == -1) {
perror("fork() error");
exit(1);
} else if (prozessmanager == 0) { //Prozessmanager prozess
while (1) {
//signal(SIGALRM, handler);
//while(1){
//alarm(1);
//}
close(pipefd[1]);
read(pipefd[0], buf, sizeof (buf));
/*if (*buf == 'S') {
//handler(clock);
} else {*/
if (*buf == 'P') {
if ((reporter = fork()) == -1) {
perror("fork() error");
exit(1);
} else if (reporter == 0) { //Reporter prozess
printf("Im a Report Prozess, PID: %d\n", getpid());
exit(0);
} else { //Prozessmanager waits for Reporter
wait(&status);
printf("Report terminated, PID: %d\n", reporter);
break;
}
} else if (*buf == 'Q') {
printf("Exit Prozessmanager, PID: %d\n", getpid());
exit(0);
} else {
printf("Prozessmanager: %s", buf);
break;
}
//}
}
} else { //Kommandant prozess
while (1) {
close(pipefd[0]);
fgets(str, 80, stdin);
write(pipefd[1], str, sizeof (str));
if (*str == 'Q') {
break;
}
}
wait(&status);
printf("Exit Kommandant, PID: %d\n", getpid());
exit(0);
}
return (0);
}

Pipe to sort and back to main

So i am trying to understand how pipes work in UNIX and i am trying to pipe a text into sort, sort them and pipe them back to main to doo. But when the execution reaches:
Note: The program takes the text file as an argument.
execlp("sort", "sort",(char *)0);
The program stops and stays still there like its waiting from the pipe something. I know that there must be something with my understanding of UNIX piping.
#include <stdio.h>
#include <stdlib.h>
#include <unistd.h>
#include <fcntl.h>
#include <string.h>
#include <sys/types.h>
#include <sys/wait.h>
int main (int argc, char **argv){
int pipe1[2];
int pipe2[2];
pid_t childpid;
FILE *fdin;
long fsize;
pipe(pipe1);
pipe(pipe2);
// error handling
if ((childpid = fork()) == -1){
perror("fork");
exit(1);
}
// parent load file, write to pipe1
if (childpid != 0){
char buf[1024];
close(pipe1[0]);
close(pipe2[1]);
fdin = fopen(argv[1], "r");
//fseek(fdin, 0, SEEK_END);
//fsize = ftell(fdin);
//fseek(fdin, 0, SEEK_SET);
fread(buf, sizeof(buf), 1, fdin);
fclose(fdin);
dup2(pipe1[1],STDOUT_FILENO);
write(pipe1[1], buf, sizeof(buf));
close(pipe1[1]);
}
else if (childpid == 0){
char buf[1024];
close(pipe1[1]);
close(pipe2[0]);
//dup2(pipe2[1], STDOUT_FILENO);
//dup2(pipe1[0], STDIN_FILENO);
read(pipe1[0], buf, sizeof(buf));
close(pipe1[0]);
printf("%s\n\n", buf);
dup2(pipe2[1], STDOUT_FILENO);
close(pipe2[1]);
execlp("sort", "sort",(char *)0);
printf("%s\n", buf);
exit(0);
}
// wait child
wait(NULL);
// parent read pipe 2 and print
if (childpid != 0){
// DOOOO
//read(pipe2[0], buf, 1024);
//printf("%s\n", buf);
}
return 0;
}
Dead Locked
Updated
UPDATE: 1
#include <stdio.h>
#include <stdlib.h>
#include <unistd.h>
#include <fcntl.h>
#include <string.h>
#include <sys/types.h>
#include <sys/wait.h>
//char *message = "This is a message!!!";
int main (int argc, char **argv){
int pipe1[2];
int pipe2[2];
pid_t childpid[2];
FILE *fdin;
char buf[1024];
//long fsize;
pipe(pipe1);
pipe(pipe2);
// error handling
if ((childpid[0] = fork()) == -1)
{
perror("fork");
exit(1);
}
// parent load file, write to pipe1
if (childpid[0] != 0){
close(pipe1[0]);
close(pipe2[1]);
fdin = fopen(argv[1], "r");
//fseek(fdin, 0, SEEK_END);
//fsize = ftell(fdin);
//fseek(fdin, 0, SEEK_SET);
fread(buf, sizeof(buf), 1, fdin);
fclose(fdin);
dup2(pipe1[1],STDOUT_FILENO);
write(pipe1[1], buf, sizeof(buf));
close(pipe1[1]);
}
else if (childpid[0] == 0){
buf[0] = '\0';
int pipe3[2];
pipe(pipe3);
close(pipe1[1]);
close(pipe2[0]);
//dup2(pipe2[1], STDOUT_FILENO);
dup2(pipe1[0], STDIN_FILENO);
//dup2(pipe3[1],STDOUT_FILENO);
read(pipe1[0], buf, sizeof(buf));
close(pipe1[0]);
write(pipe3[1], buf, sizeof(buf));
printf("-PIPED BUFF-\n%s\n\n", buf);
if ((childpid[1] = fork()) == -1){
perror("fork second child");
exit(1);
}
// Child of child (sort call)
if (childpid[1] != 0){
close(pipe2[1]);
close(pipe3[0]);
printf("I AM YOUR FATHER LOOK\n");
}else{
printf("a\n");
buf[0] = '\0';
printf("b\n");
close(pipe3[1]);
printf("c\n\n");
dup2(pipe3[0], STDIN_FILENO);
read(pipe3[0], buf, sizeof(buf));
close(pipe3[0]);
printf("-SORT BUFF-\n%s\n\n", buf);
//dup2(pipe2[1], STDOUT_FILENO);
close(pipe2[1]);
execlp("sort","sort",(char *)0);
printf("-SORTED BUFF-\n%s\n\n", buf);
exit(0);
}
// wait second child exec
wait(NULL);
//printf("%s\n", buf);
exit(0);
}
// wait child exec
//wait(NULL);
int status;
pid_t pid;
int n = 2;
while (n > 0){
pid = wait(&status);
printf("-SORTED BUFF-\n%s\n\n", buf);
--n;
}
// parent read pipe 2 and print
if (childpid[0] != 0){
printf("asd\n");
buf[0] = '\0';
dup2(pipe2[0], STDIN_FILENO);
read(pipe2[0], buf, sizeof(buf));
close(pipe2[0]);
printf("-SORTED BUFF-\n%s\n\n", buf);
}
return 0;
}
Part 1
In your parent code, you have:
dup2(pipe1[1],STDOUT_FILENO);
write(pipe1[1], buf, sizeof(buf));
close(pipe1[1]);
This is problematic on multiple counts:
The parent's standard output is now the write end of the pipe used for sending information to the child. That means the parent will have to open a file or terminal or something to write the results of sort to its original standard output.
When you close(pipe1[1]), there is still an open file descriptor for the pipe (the parent's standard output), so sort never gets EOF on the pipe.
You didn't record how much data you read, so you don't know how much data you should write. You could be writing garbage to the pipe unless you know the file is bigger than 1024 bytes. You should capture the amount of data read from the file and only write that much data to the pipe. You should think about ensuring the information ends with a newline.
Since you wait() for the child to complete, but the child doesn't know its input is complete, you have a deadlock. You then have the code to read the input data, but it isn't clear where you're going to write because of the dup2().
First stage fix: remove the identified dup2().
Fretting about deadlocks
In principle, the whole design only works because sort has to read all its input before it can write any of its output. If you had a command such as awk or sed that can write output before it finishes reading its input, your two-way pipe scheme wouldn't work well on large volumes of data. The child might fill the pipe buffer (and not be able to write any more to it) while the parent is still trying to write and finds its pipe buffer is full. Both processes would be stuck in a write waiting for the other to read. There are ways around that — select(), poll(), multiple threads, etc. — but they're beyond the scope of what you want, or need, to deal with now.
Also, your program limits the input to sort to at most 1024 bytes. That isn't enough to fill any pipe buffer, which means that unless the executed command increases the amount of data it has to write back compared with what it reads in — for example, if you sent URLs to a process that fetched the data from those URLs — then you won't run into deadlocks.
Part 2
The child code seems to read the data from the pipe, then launches sort (but there's nothing left for sort to read), and seems to expect execlp() to return. The code simply needs to connect the correct ends of the pipes to standard input and output, close all the pipe file descriptors, and then execute sort. If execlp() returns, it failed — report the error.
Second stage fix: simplify the child process, and make sort do the reading and writing.
Working code
Lots of commented out bits left behind. Key error checking added. For example, check that the command line is correct before doing anything else. Often, you'd open the file before forking; this time, it is better not to do that. Report errors on standard error.
#include <stdio.h>
#include <stdlib.h>
#include <unistd.h>
#include <fcntl.h>
#include <string.h>
#include <sys/types.h>
#include <sys/wait.h>
int main (int argc, char **argv){
int pipe1[2];
int pipe2[2];
pid_t childpid;
FILE *fdin;
if (argc != 2)
{
fprintf(stderr, "Usage: %s file\n", argv[0]);
exit(1);
}
pipe(pipe1);
pipe(pipe2);
// error handling
if ((childpid = fork()) == -1){
perror("fork");
exit(1);
}
// parent load file, write to pipe1
if (childpid != 0){
//long fsize;
char buf[1024];
close(pipe1[0]);
close(pipe2[1]);
fdin = fopen(argv[1], "r");
if (fdin == 0)
{
fprintf(stderr, "%s: failed to open file '%s'\n", argv[0], argv[1]);
exit(1);
}
//fseek(fdin, 0, SEEK_END);
//fsize = ftell(fdin);
//fseek(fdin, 0, SEEK_SET);
int nbytes = fread(buf, 1, sizeof(buf), fdin);
if (nbytes <= 0)
{
fprintf(stderr, "%s: no data in file '%s'\n", argv[0], argv[1]);
exit(1);
}
fclose(fdin);
//dup2(pipe1[1],STDOUT_FILENO);
write(pipe1[1], buf, nbytes);
close(pipe1[1]);
}
else if (childpid == 0){
//char buf[1024];
close(pipe1[1]);
close(pipe2[0]);
dup2(pipe2[1], STDOUT_FILENO);
dup2(pipe1[0], STDIN_FILENO);
close(pipe2[1]);
close(pipe1[0]);
//read(pipe1[0], buf, sizeof(buf));
//close(pipe1[0]);
//printf("%s\n\n", buf);
//dup2(pipe2[1], STDOUT_FILENO);
//close(pipe2[1]);
execlp("sort", "sort",(char *)0);
fprintf(stderr, "%s: failed to exec 'sort'\n", argv[0]);
exit(1);
}
// wait child
wait(NULL);
// parent read pipe 2 and print
if (childpid != 0){
char buf[1024];
int nbytes;
while ((nbytes = read(pipe2[0], buf, sizeof(buf))) > 0)
printf("%.*s", nbytes, buf);
}
return 0;
}
Note the careful trapping of sizes on both read operations.
Consider an input file:
Harlequin
Preposterous
Animagus
Zealot
Queensbury Rules
Quaternion
Hedwig
Tensor
Tenser
The output I get is:
Animagus
Harlequin
Hedwig
Preposterous
Quaternion
Queensbury Rules
Tenser
Tensor
Zealot
This looks correct to me.
The purpose is to have the parent that open the file and write it to a pipe. In the same time we have a child that create a second pipe and read it. And again in the same time we have a second child that exec sort.
We need 2 child and 2 pipe. The first parent wait the first child and the first child wait the second child.
I don't know if it's perfect because I can't test and this king of thing is very complex:
#include <sys/types.h>
#include <sys/wait.h>
#include <stdio.h>
#include <unistd.h>
#include <limits.h>
static int wait_and_return(pid_t pid) {
int status;
if (waitpid(pid, &status, 0) == -1) {
perror("waitpid()");
return 1;
}
return status;
}
static pid_t create_pipe_and_fork(int fd_pipe[2]) {
if (pipe(fd_pipe) == -1) {
perror("pipe()");
return -1;
}
pid_t pid = fork();
if (pid == -1) {
close(fd_pipe[0]);
close(fd_pipe[1]);
perror("fork()");
return -1;
}
return pid;
}
static int exec_sort(int fd_in, int fd_out) {
if (dup2(fd_in, STDIN_FILENO) == -1 || dup2(fd_out, STDOUT_FILENO) == -1) {
close(fd_in);
close(fd_out);
perror("dup2()");
return 1;
}
close(fd_in);
close(fd_out);
execlp("sort", "sort", (char *)NULL);
perror("execlp()");
return 1;
}
static int child(int fd) {
int fd_pipe[2];
pid_t pid = create_pipe_and_fork(fd_pipe);
if (pid == -1) {
close(fd);
return 1;
}
if (pid != 0) {
close(fd);
close(fd_pipe[1]);
char buf[4048];
ssize_t ret;
while ((ret = read(fd_pipe[0], buf, sizeof buf)) > 0) {
if (ret > INT_MAX) {
close(fd_pipe[0]);
wait_and_return(pid);
return 1;
}
printf("%.*s", (int)ret, buf);
}
close(fd_pipe[0]);
return wait_and_return(pid);
} else {
close(fd_pipe[0]);
return exec_sort(fd, fd_pipe[1]);
}
}
int main(int argc, char **argv) {
if (argc != 2) {
fprintf(stderr, "wrong argument\n");
return 1;
}
int fd_pipe[2];
pid_t pid = create_pipe_and_fork(fd_pipe);
if (pid == -1) {
return 1;
}
if (pid != 0) {
close(fd_pipe[0]);
FILE *file = fopen(argv[1], "r");
if (file == NULL) {
perror("fopen():");
close(fd_pipe[1]);
wait_and_return(pid);
return 1;
}
char buf[4048];
size_t ret;
while ((ret = fread(buf, sizeof *buf, sizeof buf / sizeof *buf, file))) {
write(fd_pipe[1], buf, ret);
}
fclose(file);
close(fd_pipe[1]);
return wait_and_return(pid);
} else {
close(fd_pipe[1]);
return child(fd_pipe[0]);
}
}
It possible to inverse the role of main and the last child so the main will read the result and the child will open the file. I let you try.

Why read() wont return zero when reading from pipe

I am having a problem with my assignment I have due for class. I have to create a read/write program that will read a text file into it and write the contents to a new text file. The thing is, I have to use parent/child processes and piping. I have to pass the contents into the pipe with one child, and use another child to read the data from the pipe and write it to a new file.
I have three files: parent.c, read.c and write.c. The program works fine for the most part! It even transfers the data from one file to the other perfectly. The problem I am having is that the write.c process will never complete. I think it may have something to do with the reading from pipe(won't return 0 or EOF). Here is my source code:
parent.c
#include <unistd.h>
#include <string.h>
#include <sys/types.h>
#include <sys/wait.h>
#include <fcntl.h>
#include <stdio.h>
#include <stdlib.h>
#define BUFF_SIZE 255
int main(int ac, char* av[])
{
if(ac <3)
{
printf("Please enter all required arguments!\n");
exit(0);
}
int pfd[2];
int pipeCreated;
char readFile[50];
char writePipe[20];
pid_t child_pid_read;
pid_t child_pid_write;
pipeCreated = pipe(pfd);
if(pipeCreated == -1)
{
printf("An error occurred when trying to create a pipe\n");
exit(0);
}
strcpy(readFile, av[1]);
sprintf(writePipe,"%d", pfd[1]);
child_pid_read = fork();
char writeFile[50];
char readPipe[20];
//Handling the read()
switch(child_pid_read)
{
//Error in case forfk() failed
case -1:
perror("fork failed");
return 1;
//Handle child processes
case 0:
if(close(pfd[0]) == -1)
{
printf("An error occurred while closing the pipe\n");
exit(0);
}
if(execle("./read.out", "./read.out", readFile, writePipe, (char*)0, NULL) == -1)
{
printf("Child: Error creating read.\n");
exit(0);
}
default:
wait(&child_pid_read);
strcpy(writeFile, av[2]);
sprintf(readPipe,"%d", pfd[0]);
child_pid_write = fork();
break;
}
//Handling the write
switch(child_pid_write)
{
//Error in case fork() failed
case -1:
perror("fork failed");
return 1;
//Handle child processes
case 0:
if(close(pfd[1]) == -1)
{
printf("An error occurred while closing the pipe\n");
exit(0);
}
if(execle("./write.out", "./write.out", writeFile, readPipe, (char*)0, NULL) == -1)
{
printf("Child: Error creating read.\n");
exit(-1);
}
break;
default:
wait(&child_pid_write);
break;
}
printf("Write completed!");
return 0;
}
read.c:
#include <unistd.h>
#include <stdio.h>
#include <stdlib.h>
#include <fcntl.h>
#define BUFF_SIZE 16
int main(int ac, char* av[])
{
char buffer[BUFF_SIZE];
int fd;
int pid;
if(ac > 1)
{
fd = open(av[1], O_RDONLY);
if(fd == -1)
{
printf("error: Could Not Open File\n");
exit(0);
}
pid = atoi(av[2]);
}
int num_read = 1;
while(1)
{
num_read = read(fd, buffer, BUFF_SIZE);
if(num_read == -1)
{
printf("Error reading file\n");
exit(0);
}
if(num_read == 0)
{
break;
}
if(write(pid, buffer, num_read) != num_read)
{
printf("Error writing to pipe\n");
break;
}
}
close(fd);
return 1;
}
write.c
#include <unistd.h>
#include <stdio.h>
#include <stdlib.h>
#include <fcntl.h>
#define BUFF_SIZE 1
int main(int ac, char* av[])
{
char buffer[BUFF_SIZE];
int fd = open(av[1], O_WRONLY | O_CREAT | O_TRUNC, S_IRUSR | S_IWUSR);
int pid = atoi(av[2]);
int num_read = 1;
while(1)
{
num_read = read(pid, buffer, BUFF_SIZE);
printf("num_read: %d\n", num_read);
if(num_read == -1)
{
printf("Error reading pipe\n");
break;
}
if(write(fd, buffer, num_read) != num_read)
{
printf("Error writing to file\n");
break;
}
if(num_read == EOF)
{
break;
}
}
close(fd);
return 1;
}
Please look over my code and suggest corrections. I am passing in the names of the text files through the terminal (./parent.out, oldFile.txt, newFile.txt).
Two problems:
You're not forking the write process until after wait() for the read process returns. If the read process tries to write more data than will fit in the pipe buffer, it will block and never exit. You need to allow both processes to run concurrently to avoid this deadlock. It will work with a small file, but if the file is bigger than 4KB it will hang.
After forking the write process, the parent process has to close pfd[0]. The reader of a pipe doesn't get EOF until all processes that have the write end open close it. It should be:
default:
if(close(pfd[0]) == -1)
{
printf("An error occurred while closing the pipe\n");
exit(0);
}
wait(&child_pid_write);
break;
Your child want to read data,why you close the fd[0], return from pipe indicating that fd[0] for reading and fd[1] for writing.As i can't add a comment, i have to post the comment here....

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