Hangman game - C - c

Question

Im doing a hangman game as a school project but Im facing an issue:
do{
system("cls");
// Header of the game
printf("\n HANGMAN GAME\n\n\n");
// Present letters found
for (i=0; word[i]!='\0'; i++)
printf (" %c ", word_2[i]);
printf("\n");
// Present positions to the letters
for (i=0; word[i]!='\0'; i++)
printf("___ ");
printf("\n");
// ****PLAYER'S ANSWERS*****
// Read player's answers
printf("\n\n Whats your guess + <enter>: ");
scanf("%c", &letter);
scanf("%c", &c);
// Verify if the letter is in the word
found=0;
for(i=0; word[i]!='\0'; i++)
if (word[i] == letter){
word_2[i] = letter;
corrects++;
max_attemps--;
found = 1;
printf("\nWell done, %s. You have now %d attempts\n\n", name, max_attemps);
system("pause");
}
if(found == 0){
max_attemps--;
printf("\nOh no, %s. You have now %d attempts\n\n", name, max_attemps);
system("pause");
}
if (max_attemps <= 0 || corrects == lenght) {
end = 1;
}
} while (end == 0);
When I got a right letter that have two or more position in the word it takes from me two or more attempts because of the system("pause") when in fact just had to takes me one. But if I don't put the system("pause") the board will be cleared before I can see the message. Anyone knows what can I do to solve this? I'll be very grateful.

Answer 1

Check your found flag only after you have scanned the whole word:
// Verify if the letter is in the word
found=0;
for(i=0; word[i]!='\0'; i++)
if (word[i] == letter){
word_2[i] = letter;
corrects++;
max_attemps--;
found = 1;
// comment out
// printf("\nWell done, %s. You have now %d attempts\n\n", name, max_attemps);
// system("pause");
}
if(found == 1)
{
printf("\nWell done, %s. You have now %d attempts\n\n", name, max_attemps);
system("pause");
}
else{
max_attemps--;
printf("\nOh no, %s. You have now %d attempts\n\n", name, max_attemps);
system("pause");
}
if (max_attemps <= 0 || corrects == lenght) {
end = 1;
}