printf after execl not showing - c

Question

I'm testing the execl() function tho I'm not being able to solve how to make the printf() after the execl() show up when I run the program. I figured out it has something to do with the fflush() function, although I still can't do it.
Heres the code.
#include<sys/types.h>
#include <unistd.h>
#include <stdlib.h>
#include <sys/wait.h>
#include <stdio.h>
void main(){
printf ("Show content from directory /:\n");
execl( "/bin/ls", "ls", "-l", "/", NULL );
fprintf (stdout,"End of command: ls -l /\n");
fflush(stdout);
}

Answer 1

From the man page
https://linux.die.net/man/3/execl
Return Value
The exec() functions only return if an error has occurred. The return value is -1, and errno is set to indicate the error.
If you really want to use execl() instead of system(), then
you should change the code like this.
#include<sys/types.h>
#include <unistd.h>
#include <stdlib.h>
#include <sys/wait.h>
#include <stdio.h>
int main(void){
printf ("Show content from directory /:\n");
pid_t p=fork(); // create a child process
if(p==0) // if we are in the child process
{
execl( "/bin/ls", "ls", "-l", "/", NULL ); // replace it with a new program
perror("execl"); // reaching this line is necessarily a failure
exit(1); // terminate child process in any case
}
waitpid(p, NULL, 0); // wait for child process to terminate
fprintf (stdout,"End of command: ls -l /\n");
fflush(stdout);
return 0;
}