How to check if arrays have the same object React Native [duplicate] - reactjs

Question

This question already has answers here:
An efficient way to get the difference between two arrays of objects?
(4 answers)
Closed 3 years ago.
I have two arrays:
const array1 = [
{ id: 1, name: 'John', score: 124 },
{ id: 2, name: 'Angie', score: 80 },
{ id: 3, name: 'Max', score: 56 }
]
const array2 = [
{ id: 5, name: 'Lisa', score: 78 },
{ id: 2, name: 'Angie', score: 80 }
]
JSON.stringify(array1) == JSON.stringify(array2) is not a solution, because arrays have different number of objects.
array1.some(item=> array2.includes(item)) doesnt't work too.
If there a solution?

Answer 1

What i would suggest is since your id is unique , so try the below :
const array1 = [
{ id: 1, name: 'John', score: 124 },
{ id: 2, name: 'Angie', score: 80 },
{ id: 3, name: 'Max', score: 56 }
]
const array2 = [
{ id: 5, name: 'Lisa', score: 78 },
{ id: 2, name: 'Angie', score: 80 }
]
var array2Id = {}
array2.forEach(function(obj){
bIds[obj.id] = obj;
});
// Return all elements in A, unless in B
let check = array1.filter(function(obj){
return !(obj.id in array2Id);
});
console.log(check,'there')
if check is an empty array that means both are same otherwise it will give the different objects.
Hope it helps feel free for doubts

Answer 2

Here is a quick solution, maybe not the most performant.
const array1 = [
{ id: 1, name: 'John', score: 124 },
{ id: 2, name: 'Angie', score: 80 },
{ id: 3, name: 'Max', score: 56 },
];
const array2 = [
{ id: 5, name: 'Lisa', score: 78 },
{ id: 2, name: 'Angie', score: 80 },
];
// Index will have -1 if there is no match, otherwise it'll have
// the index of the first found match in array1.
const index = array1.findIndex(array1Item => {
// This will return the index if found, otherwise -1
const match = array2.findIndex(array2Item => {
// return array1Item.id === array2Item.id;
return JSON.stringify(array1Item) === JSON.stringify(array2Item);
});
return match > -1;
});
Instead of stringifying the entire object, if id is unique, you can just compare id as shown in the commented code.
Be advised this could have a complexity of O(n^2) where n is your array sizes. Big arrays may take a while.
Here is it running on PlayCode. It logs index as 1 because the first match is the second item in array1.