Meaning of "labeling output" - exercise from "C Programming - A Modern Approach 2" - c

Question

I'm practicing with this book "C programming - a modern approach 2" and the programming project 11 of chapter 8 says as follows:
Modify Programming Project 4 from chapter 7 (I'm going to attach the
code below) so that the program labels its output:
Enter phone number: 1-800-COL-LECT
In numeric form: 1-800-265-5328
The program will need to store the number (either in its original form
or in its numeric form) in an array of character until it can be
printed. You may assume that the phone number is no more than 15
characters long
The thing that i don't get is the meaning of the part in bold ("so that the program labels its output"). What it means? I can understand English quite well but in this case I really don't get what the Author is talking about.
I already googled the meaning of "labeling" in CS and it talk about goto ect... This chapter is about Arrays so i guess the second part is important and is actually the answer and in fact is not a problem for me to modify the program as requested, I just would like to really understand the whole request and what I'm doing.
The code of the program to modify:
#include <stdio.h>
int main(void)
{
char ch;
printf("Enter phone number: ");
while ((ch = getchar()) != '\n') {
switch (ch) {
case 'A': case 'a': case 'B': case 'b': case 'C': case 'c':
printf("2");
break;
case 'D': case 'd': case 'E': case 'e': case 'F': case 'f':
printf("3");
break;
case 'G': case 'g': case 'H': case 'h': case 'I': case 'i':
printf("4");
break;
case 'J': case 'j': case 'K': case 'k': case 'L': case 'l':
printf("5");
break;
case 'M': case 'm': case 'N': case 'n': case 'O': case 'o':
printf("6");
break;
case 'P': case 'p': case 'R': case 'r': case 'S': case 's':
printf("7");
break;
case 'T': case 't': case 'U': case 'u': case 'V': case 'v':
printf("8");
break;
case 'W': case 'w': case 'X': case 'x': case 'Y': case 'y':
printf("9");
break;
default:
putchar(ch);
}
}
return 0;
}