SQL Server trigger does not recognize inserted row - sql-server

Question

I have simple SQL Server trigger and for some reason it does not recognize INSERTED row.
Here is code:
-- code
DROP TABLE a;
GO
CREATE TABLE a
(
id INT IDENTITY(1,1) PRIMARY KEY,
v INT
)
GO
DROP TABLE a_audit;
CREATE TABLE a_audit
(
id INT,
v INT,
[updated_at] [DATETIME] NOT NULL DEFAULT GETDATE()
)
GO
CREATE TRIGGER [dbo].[trg_a]
ON [dbo].[a]
AFTER INSERT, UPDATE, DELETE
NOT FOR REPLICATION
AS
BEGIN
SET NOCOUNT ON;
PRINT 'start';
DECLARE #xmltmp xml = (SELECT * FROM inserted FOR XML AUTO);
PRINT CONVERT(NVARCHAR(MAX), #xmltmp);
-- INSERT INTO a_audit (id, v) VALUES (inserted.id, inserted.v);
END;
GO
INSERT INTO a (v)
VALUES (1);
WAITFOR DELAY '00:00:01.11';
INSERT INTO a (v)
VALUES (2);
GO
SELECT * FROM a;
PRINT 'done'
It produces this output
start
<inserted id="1" v="1"/>
(1 row affected)
start
<inserted id="2" v="2"/>
(1 row affected)
(2 rows affected)
done
So I see that INSERTED row does exist.
However, if I remove comment on insert statements the output is this:
Msg 4104, Level 16, State 1, Procedure trg_a, Line 14 [Batch Start Line 16]
The multi-part identifier "inserted.id" could not be bound.
Msg 4104, Level 16, State 1, Procedure trg_a, Line 14 [Batch Start Line 16]
The multi-part identifier "inserted.v" could not be bound.
What is wrong?

Answer 1

inserted is a table, not a function. To INSERT from another table you need to use a INSERT INTO... SELECT ... FROM statement:
INSERT INTO a_audit (id,v)
SELECT id,
v
FROM inserted;
You can't reference a table's columns unless you use a FROM. For example just running the below would give the error below:
SELECT a_audit.id, a.audit.v;
The multi-part identifier "a_audit.id" could not be bound.
You would have to a SELECT...FROM:
SELECT id, v
FROM a_audit;