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Whats the meaning of [i] in the following example?
#include <stdio.h>
int main()
{
int values[5];
printf("Enter 5 integers: ");
for (int i = 0; i < 5; ++i)
{
scanf("%d", &values[i]); // HERE
}
printf("Displaying integers: ");
for(int i = 0; i < 5; ++i) {
printf("%d\n", values[i]);
}
return 0;
}
i here is a variable.
In your code, [i] acts as the index of values and is used to access the element in array values.
Edit:
Since there is a //HERE comment in your code, im going to assume you would also want what [i] does there. The expression &value[i] basically gives the address of value[i] ,i.e, the "ith" element of the array.
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#include <stdio.h>
#include <stdlib.h>
#include <array.h>
int col, str;
int *point;
void setArr()
{
printf("Input columns="); scanf("%d", &col);
printf("Input strings="); scanf("%d", &str);
int num[str][col];
for(int i = 0; i < str; ++i)
{
for(int j = 0; j < col; ++j)
{
scanf("%d", &num[i][j];
}
}
point = num;
}
int main(void)
{
setArr();
printf("First=%d\n", *point);
printf("Number=%d", *point);
}
Output:
Input columns=2
Input strings=2
1
2
3
4
First=1
Number=1740639104
Here we have code in C, that have to get exact number from array using pointer, but during many attempts I understand that there is something I do not understand or just do not know.So there is a problem(or it have to be like this), namely, I refer to pointer ,which points on first element two times and I get different results in each case. Why it happened and in which way I could solve it? Thanks,everyone.
With
point = num;
you are setting point to an address of a function local variable. All further access of that will be undefined behaviour.
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I know that was a lot of questions and answers about "loading matrix from file in C". But I have one problem and question.
My piece of code looks like this:
for(int i=0; fgets(buffer_char, 256, file); i++) {
tmp_char = strtok(buffer_char, " \t");
for(int j=0; tmp_char != NULL; j++) {
printf("%s ", tmp_char);
strtod(tmp_char, array[i][j]);
tmp_char = strtok(NULL, " \t");
}
}
I have input file with matrix like:
3
1 2 3
4 5 6
5 6 7
I'm trying to load it into array, but I have to check if input values are correct. And my question is, How I can do it better? Which solution will be more correct?
#edit:
I modified code to this:
for(int i=0; fgets(buffer_char, 256, file); i++) {
array[i][0] = strtod(buffer_char, &tmp_char);
for(int j=1; tmp_char == NULL; j++) {
array[i][j] = strtod(tmp_char, &tmp_char);
}
}
And it works, How I want, but only for first elements of new line. I know, the problem is with "array[i][j] = strtod(tmp_char, &tmp_char);", but I have no idea what to do.
You can simply use fscanf for validating and storing your input into an array.
Code:
if((check=fscanf(fp,"%d",&n))==1)
{
int Arr[n][n];
for(int i=0; i<n; i++) {
for(int j=0;j<n;j++){
fscanf(fp,"%d",&Arr[i][j]);
printf("%d ",Arr[i][j]);
}
printf("\n");
}
}
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I have a string array of 10 words and I want to display them.
However, I want the user to press a key and the next values are displayed.
I.e, it should display a, then the user presses a key and it displays b.
How can I achieve this?
char destination[10][10]
for (i=0; i<10; i++){
printf(Enter a name: );
scanf( "%s", name[i])
}
for (i=0; i<10; i++){
printf(" Name %d: %s", i, name[i]);
getch();
}
I'm not sure what you want, nor what your actual problem is, but this works fine here:
#include <stdio.h>
#include <conio.h>
int main() {
char name[10][10];
int i;
for (i = 0; i<10; i++) {
printf("Enter a name : ");
scanf("%s", name[i]);
}
for (i = 0; i<10; i++) {
printf(" Name %d: %s", i, name[i]);
getch();
}
}
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I need to create a program that gives the sum of the all the numbers between the constants of a and b given by the user. b needs to be greater than a.
#include <stdio.h>
void main()
{
int index, begno, endno, sum = 0;
printf("Program for sum of all numbers in the given range\n");
printf("Enter Beg. No.: ");
scanf("%d", &begno);
printf("Enter End. No.: ");
scanf("%d", &endno);
index = begno;
for(; index <= endno; index ++)
sum = sum + index;
printf("The sum of even numbers between %d and %d is: %d", begno, endno, sum);
}
The code given looks OK, but if you want the sum without including the last number, as is generally the case you should change the for loop like this
for(; index < endno; index ++)
I would start by implementing a loop to compute:
$$\sum_{n=a}^{b}
n$$
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The number of spaces in each line will change as per the number that is given in the for loop. So if the number changes to 2 as per the for loop, it will have 2 spaces in that line and the number will go on increasing in every line in an ascendinfg order.
int i, j;
for(i = 0; i < 10; i++){
for(j = 0; j < i; j++) printf(" ");
printf("\n");
}
int i,j;
for (i=1; i<5; i++){
for (j=1; j<=i; j++){ // it will print i spaces whenever i increases.
printf(" ");
}
}