problem about using a dynamically allocated 2d array in a c program - c

Question

I'm having a problem on making a move on my 9 x 9 tic tac toe program.
When I enter a coordinate such as (5,5), The x is displayed correctly on the grid.
MY PROBLEM IS THAT when I enter a coordinate which has the number 7 in it such as (4,7), TWO X's ARE DISPLAYED ON THE GRID.
I previously did the program declaring my array as a global variable. All was working fine. The issue started when I switched to a dynamically allocated array and passed the array using a double-pointer.
So I'm guessing that my problem is because of my array.
Can someone tell me where does this issue occur and how to fix it please.
I have declared the array in my main
//previously the array was declared here
//char grid[ROW][COLUMN];
int main()
{
//dynamically create an array of pointers os size ROW
char **grid = (char **)malloc(ROW * sizeof(char *));
// dynamically allocate memory of size ROW*COLUMN and let *grid point to it
*grid = (char *)malloc(sizeof(char) * ROW * COLUMN);
make move method
int make_move(char **grid, int x, int y,int row, int col, char letter)
{
if (x < 0 || x >= row || y < 0 || y >= col || grid[x][y] != ' ' )
{
// checks to see if the input is valid
return 1;
}
if( grid[x][y] == ' ')
grid[x][y] = letter;
// sets the coordinates in the grid to the letter
return 0;
}
update grid method
// Updates the grid accordingly every time a move is made
void update_grid(char **grid,int x, int y, int row, int col)
{
// int counter = 1;
//checks the input
while (x < 0 || x >= row || y < 0 || y >= col || grid[x][y] != ' ')
{
fputs("Error, Move not valid! Please reenter: ", stderr);
scanf("%d,%d", &x, &y);
}
++counter;
{
//Acts as an increment for the turns of the players
if(counter % 2 == 0)
{
//checks to see if it is player X's turn
grid[x][y] = 'X';
}
if(counter % 2 != 0)
{
//checks to see if it is player O's turn
grid[x][y] = 'O';
}
//prints grid
printf(" ");
for (int c = 0; c < col; c++)
{
printf(" ");
printf(" %d", c);
}
printf("\n");
for (int r = 0; r < row; ++r)
{
printf("%d", r);
printf("|");
for (int dot = 0; dot < (col*row); ++dot)
{
printf("|");
printf("%c", grid[r][dot]);
printf(" ");
if (dot == col - 1)
{
// stops j from over printing
printf("|| \n");
break;
}
}
}
}
}

Answer 1

As B. Go said your malloc is wrong, here's how it should look.
//dynamically create an array of pointers os size ROW
char **grid = malloc(ROW * sizeof(char *));
for(size_t i = 0; i < ROW; i++){
grid[i] = malloc(COLUMN);
}
you allocated ROW pointers but you only filled the first one, you need to give them each COLUMN bytes of data.