Use a base struct to extract values from void* - c

Question

I have many types of structs in my project, and another struct that holds a pointer to one of these structs. Such as,
struct one{int num = 1;};
struct two{int num = 2;};
struct three{int num = 3;};
// These structs hold many other values as well, but the first value is always `int num`.
And I have another struct that holds references to these structs. I had to use void* because I do not know which of these structs is going to be referenced.
struct Holder{void* any_struct};
My question is, I need the values inside these structs, but I have a void pointer, could I declare a base struct that the first variable is an int, cast it, and use it to extract the num variable from these structs, such as:
struct Base{int num};
((Base*) Holder->any_struct)->num
// Gives 1, 2 or 3

Answer 1

If the only thing you need is to extract the num, you can use memcpy.
Assuming it's always int and always first and always present.
int num = 0;
memcpy(&num, Holder->any_struct, sizeof(int));
// Gives 1, 2 or 3 in num.
C99 standard section 6.7.2.1 bullet point 13:
A pointer to a structure object, suitably converted, points to its
initial member. There may be unnamed padding within a structure
object, but not at its beginning.
More info about the standard in this answer.

Answer 2

I think this is acceptable, and I've seen this pattern in other C projects. E.g., in libuv. They define a type uv_handle_t and refer to it as a "Base handle" ... here's info from their page (http://docs.libuv.org/en/v1.x/handle.html)
uv_handle_t is the base type for all libuv handle types.
Structures are aligned so that any libuv handle can be cast to
uv_handle_t. All API functions defined here work with any handle type.
And how they implement is pattern you could adopt. They define a macro for the common fields:
#define UV_HANDLE_FIELDS \
/* public */ \
void* data; \
/* read-only */ \
uv_loop_t* loop; \
uv_handle_type type; \
/* private */ \
uv_close_cb close_cb; \
void* handle_queue[2]; \
union { \
int fd; \
void* reserved[4]; \
} u; \
UV_HANDLE_PRIVATE_FIELDS \
/* The abstract base class of all handles. */
struct uv_handle_s {
UV_HANDLE_FIELDS
};
... and then they use this macro to define "derived" types:
/*
* uv_stream_t is a subclass of uv_handle_t.
*
* uv_stream is an abstract class.
*
* uv_stream_t is the parent class of uv_tcp_t, uv_pipe_t and uv_tty_t.
*/
struct uv_stream_s {
UV_HANDLE_FIELDS
UV_STREAM_FIELDS
};
The advantage of this approach is that you can add fields to the "base" class by updating this macro, and then be sure that all "derived" classes get the new fields.

Answer 3

First of all, the various rules of type conversions between different struct types in C are complex and not something one should meddle with unless one knows the rules of what makes two structs compatible, the strict aliasing rule, alignment issues and so on.
That being said, the simplest kind of base class interface is similar to what you have:
typedef struct
{
int num;
} base_t;
typedef struct
{
base_t base;
/* struct-specific stuff here */
} one_t;
one_t one = ...;
...
base_t* ref = (base_t*)&one;
ref->num = 0; // this is well-defined
In this code, the base_t* doesn't point directly at num but at the first object in the struct which is of base_t. It is fine to de-reference it because of that.
However, your original code with the int num spread over 3 structs doesn't necessarily allow you to cast from one struct type to another, even if you only access the initial member num. There's various details regarding strict aliasing and compatible types that may cause problems.

Answer 4

The construct you describe of using a pointer to a "base" structure as an alias to several "derived" structures, while often used with things like struct sockaddr, is not guaranteed to work by the C standard.
While there is some language to suggest is might be supported, particularly 6.7.2.1p15:
Within a structure object, the non-bit-field members and the
units in which bit-fields reside have addresses that increase in
the order in which they are declared. A pointer to a structure
object, suitably converted, points to its initial member (or
if that member is a bit-field, then to the unit in which it
resides), and vice versa. There may be unnamed padding within
a structure object, but not at its beginning.
Other parts suggest it is not, particularly 6.3.2.3 which discusses pointer conversions that are allowed:
1 A pointer to void may be converted to or from a pointer to any object type. A pointer toany object type may be converted to a
pointer to void and back again; the result shall compare equal
to the original pointer.
2 For any qualifier q, a pointer to a non-q-qualified type may be converted to a pointer to the q-qualified version of the type;
the values stored in the original and converted pointers shall compare
equal.
3 An integer constant expression with the value 0, or such an expression cast to type void *, is called anull pointer
constant. If a null pointer constant is converted to a pointer type,
the resulting pointer, called a null pointer, is guaranteed to compare
unequal to a pointer to any object or function.
4 Conversion of a null pointer to another pointer type yields a null pointer of that type.Any two null pointers shall
compare equal.
5 An integer may be converted to any pointer type. Except as previously specified, the result is implementation-defined,
might not be correctly aligned, might not point to an entity
of the referenced type, and might be a trap representation.
6 Any pointer type may be converted to an integer type. Except as previously specified, the result is implementation-defined. If the
result cannot be represented in the integer type,the behavior
is undefined. The result need not be in the range of values
of any integer type.
7 A pointer to an object type may be converted to a pointer to a different object type. If the resulting pointer is not correctly
aligned for the referenced type, the behavior is undefined.
Otherwise, when converted back again, the result shall compare
equal to the original pointer. When a pointer to an object is
converted to a pointer to a character type,the result points to the
lowest addressed byte of the object. Successive increments of the
result, up to the size of the object, yield pointers to the remaining
bytes of the object.
8 A pointer to a function of one type may be converted to a pointer to a function of another type and back again; the result shall compare
equal to the original pointer. If a converted pointer is used to call
a function whose type is not compatible with the referenced type,the
behavior is undefined.
From the above is does not state that casting from one struct to another where the type of the first member is the same is allowed.
What is allowed however is making use of a union to do essentially the same thing. Section 6.5.2.3p6 states:
One special guarantee is made in order to simplify the use of unions:
if a union contains several structures that share a common
initial sequence (see below), and if the union object
currently contains one of these structures, it is permitted
to inspect the common initial part of any of them anywhere that a
declaration of the completed type of the union is visible. Two
structures share a common initial sequence if corresponding
members have compatible types (and, for bit-fields, the same widths)
for a sequence of one or more initial members.
So what you can do is define a union that contains all the possible types as well as the base type:
union various {
struct base { int num; } b;
struct one { int num; int a; } s1;
struct two { int num; double b; } s2;
struct three { int num; char *c; } s3;
};
Then you use this union anyplace you need of of the three subtypes, and you can freely inspect the base member to determine the type. For example:
void foo(union various *u)
{
switch (u->b.num) {
case 1:
printf("s1.a=%d\n", u->s1.a);
break;
case 2:
printf("s2.b=%f\n", u->s2.b);
break;
case 1:
printf("s3.c=%s\n", u->s3.c);
break;
}
}
...
union various u;
u.s1.num = 1;
u.s1.a = 4;
foo(&u);
u.s2.num = 2;
u.s2.b = 2.5;
foo(&u);
u.s3.num = 3;
u.s3.c = "hello";
foo(&u);