I’m making a puzzle level generator (sokoban) using Clingo and got stuck trying to create levels with a specific move limit. The idea is to use the move limit to control difficulty of a level. This is how I’ve created the generator:
Specify rules for a valid looking level (all walkable tiles are connected, correct ampunt of pushable barrels and target platforms, etc.)
Specify rules for moving around and pushing barrels.
Specify winning conditions.
My first iteration was to simply require that a level is solvable in N moves by requiring that winning conditions are met in 0..N moves. This resulted in valid levels but there was no control over the difficulty.
My second iteration was to minimize the moves required for a winning condition to be met. This resulted in levels that are completed in a single move.
My third iteration was to state that a level could not be completed in less than M moves. This resulted in the logic doing unnecessary moves just to reach the minimum, there was still no meaningful control over difficulty.
My fourth iteration was to prevent the same game state from reoccurring to avoid unnecessary ”filler” moves, but this still resulted in the logic solving the levels in very unoptimally just to reach the minimum requirement.
Now I don’t really know what to do. I think what I want to do is maximize the minimum required amount of moves (up to a limit), but I’m not sure if that makes any sense. Preferrably I’d like to be able to state that the minimum amount of moves for completing this level should be M.
How should this problem be approached?
So to put it in other terms: you are searching for a puzzle that can be solved in N moves but solving it in N-1 would return unsatisfiable. Those two parts state complimentary problems ("Find at least one" vs. "Find none/all") and are difficult to put in one program and the combination raises the problem complexity (see polynomial hierarchy). Here three suggestions to solve it via enumeration:
Enumeration and difference: For N and N-1 enumerate all answers. A puzzle is solvable in exactly N steps, when it appears for N but not for N-1. This requires some sort of post processing, like a script or neat text editing.
Enumeration and unsatisfiable: In a script enumerate all answer sets one by one for the current N. For the current puzzle, try to solve it for N-1: if it returns 0 answers, you have your puzzle. This requires data-handling of some form, I would suggest using python.
Enumeration avoiding doubles: In a script, for N-1 generate all answer sets. Transform each answer set into a constraint and add it to the program. Example: the tiles m(1..4,l). m(1..4,r) define your puzzle in general, your current answer set is m(1,l). m(2,l). m(3,r)., add the following constraint to avoid generating this puzzle again. Afterwards solve the updated program for N.
:- m(1,l), m(2,l), m(3,r), not m(1,r), not m(2,r), not m(3,l), not m(4,l), not m(4,r).
As you might see all three methods would solve your problem but require additional effort outside of clingo.
I'm working on a minimax tic-tac-toe algorithm. I got it working fine, caching each state in the tree.
Then I implemented alpha-beta pruning, which seemed to affect the game. I think the problem is that nodes cannot be "trusted" if any of their descendants (children, grandchildren, etc.) were pruned. Is this true?
For now, I'm only caching states if they don't have pruned descendants. This image shows my point (not tic tac toe). The max player is the upwards triangle, which should choose the move on the left. However, if the move on the right is cached during alpha-beta pruning, the red triangle will have a false value of 4, so the move on the right would be wrongly chosen.
If by a "cache" you mean a transposition table, then you can't always trust the value in the transposition table. That is, when you store a value in a transposition table, you need to also store the alpha and beta values (perhaps the depth as well) used for the search below that state. If the alpha and beta values are not the same*, then you can't use the value from the transposition table.
*In practice they don't have to be identical, the table just needs to have values that include a superset of the values used at the current node you want to replace with the cached values.
Edit: Additional info for those dealing with this in larger games. When you search at a node you have a lower bound (alpha) and upper bound (beta) on the final value. If the returned value is between alpha and beta, then you know it is the true value of the state. If it is equal to alpha or beta, then you know it is only a bound on the final value. But, you can still use this information to help the search.
In particular, suppose that you have alpha=10 and beta=20 in the current search and the value in the transposition table is [alpha = 12, beta = 30, value = 12]. Then, when you (re-)search below the branch, you can search with bounds of alpha=10 and beta=12.
This is because you've already proven that the value is <= 12 in the previous search. When you get the final result, you can then update the transposition table entry to reflect the additional information from this search.
My game AI makes use of an algorithm that searches all possible future states based on the moves I can make (minimax / monte carlo esque). It evaluates these states using a scoring system, picks the highest scored final state and follows it.
This works well in most situations, but awfully when rewards are sparse. For example: there's a desirable collectable object that's 3 tiles to the right of me. The natural solution would be to go right->right->right.
But, my algorithm searches 6 turns deep. And it will will find many paths that eventually collect the object, including ones that take longer than 3 turns. It might for example find a path that's: up->right->down->right->right->down, collecting the object on turn 5 instead.
Since in both cases, the final leaf nodes detect the object as collected, it doesn't naturally prefer one or the other. So, instead of going right on turn 1, it might go up, or down, or left. This behavior will be repeated exactly on the next turn, so that it basically ends up dancing randomly in front of the collectable object, only luck will make it step on it.
That's clearly suboptimal and I want to fix it, but have run out of ideas how to handle this appropriately. Are there any solutions for this issue or is there any theoretical work that deals with handling this issue?
Solutions I've tried:
Make it value object collection more on earlier turns. While this works, to beat evaluator 'noise', the difference between turns must be quite high. Turn 1 must be rated higher than 2, turn 2 rated higher than 3, etc. The difference between turn 1 and 6 needs to be so high that it ends up making the behavior extremely greedy, which is not desirable in most situations. In an environment with multiple objects, it might end up choosing the path that grabs an object on turn 1, instead of the much better path that can grab objects on turn 5 and 6.
Assign the object as a target and value distance to it. If not done on a turn to turn basis, the original problem persists. If done on a turn to turn basis, the difference in importance required per turn once again makes it too greedy. This method also decreases flexibility and causes other issues. Target selection is not trivial and kind of ruins the point of a minimax style algorithm
Going much deeper in my searches so that it can always find a second object. This would cost so much computing power that I'd have to make concessions, like pruning paths much more aggressively. If I do so, I'll be back at the same problem since I won't know how to get it to prefer pruning the 5 turn version over the 3 turn version.
Give extra value to the plans laid out last turn. If it can at least follow the suboptimal path, there wouldn't be as much of an issue. Unfortunately, this once again has to be a pretty strong effect for it to work reliably, making it follow sub-optimal paths in all scenarios, hurting overall performance.
When weighting the outcome of the last step of your move, are you calculating in the number of moves needed to pick up an object?
I presume, you are quantifying each step of your move actions, giving a +1 if the step results in the picking up of an object. This means that in 3 steps, I can pick up the object with your above example, and get a +1 state of the play field, but I can also do this with 4-5-6-x steps, getting the same +1 state. If only a single object is reachable in the depth you are searching, your algorithm will likely select one of the random +1 states, giving you the above behaviour.
This could be solved, by quantifying with a negative score, each of the moves the AI must make. Thus, getting the object in 3 moves, will result in a -2, but getting the object in 6 moves, will result in -5. This way, the AI will clearly know, that it is preferable to get the object in the least amount of moves, ie, 3.
This is a very difficult problem about how to maneuver a spaceship that can both translate and rotate in 3D, for a space game.
The spaceship has n jets placing in various positions and directions.
Transformation of i-th jet relative to the CM of spaceship is constant = Ti.
Transformation is a tuple of position and orientation (quaternion or matrix 3x3 or, less preferable, Euler angles).
A transformation can also be denoted by a single matrix 4x4.
In other words, all jet are glued to the ship and cannot rotate.
A jet can exert force to the spaceship only in direction of its axis (green).
As a result of glue, the axis rotated along with the spaceship.
All jets can exert force (vector,Fi) at a certain magnitude (scalar,fi) :
i-th jet can exert force (Fi= axis x fi) only within range min_i<= fi <=max_i.
Both min_i and max_i are constant with known value.
To be clear, unit of min_i,fi,max_i is Newton.
Ex. If the range doesn't cover 0, it means that the jet can't be turned off.
The spaceship's mass = m and inertia tensor = I.
The spaceship's current transformation = Tran0, velocity = V0, angularVelocity = W0.
The spaceship physic body follows well-known physic rules :-
Torque=r x F
F=ma
angularAcceleration = I^-1 x Torque
linearAcceleration = m^-1 x F
I is different for each direction, but for the sake of simplicity, it has the same value for every direction (sphere-like). Thus, I can be thought as a scalar instead of matrix 3x3.
Question
How to control all jets (all fi) to land the ship with position=0 and angle=0?
Math-like specification: Find function of fi(time) that take minimum time to reach position=(0,0,0), orient=identity with final angularVelocity and velocity = zero.
More specifically, what are names of technique or related algorithms to solve this problem?
My research (1 dimension)
If the universe is 1D (thus, no rotation), the problem will be easy to solve.
( Thank Gavin Lock, https://stackoverflow.com/a/40359322/3577745 )
First, find the value MIN_BURN=sum{min_i}/m and MAX_BURN=sum{max_i}/m.
Second, think in opposite way, assume that x=0 (position) and v=0 at t=0,
then create two parabolas with x''=MIN_BURN and x''=MAX_BURN.
(The 2nd derivative is assumed to be constant for a period of time, so it is parabola.)
The only remaining work is to join two parabolas together.
The red dash line is where them join.
In the period of time that x''=MAX_BURN, all fi=max_i.
In the period of time that x''=MIN_BURN, all fi=min_i.
It works really well for 1D, but in 3D, the problem is far more harder.
Note:
Just a rough guide pointing me to a correct direction is really appreciated.
I don't need a perfect AI, e.g. it can take a little more time than optimum.
I think about it for more than 1 week, still find no clue.
Other attempts / opinions
I don't think machine learning like neural network is appropriate for this case.
Boundary-constrained-least-square-optimisation may be useful but I don't know how to fit my two hyper-parabola to that form of problem.
This may be solved by using many iterations, but how?
I have searched NASA's website, but not find anything useful.
The feature may exist in "Space Engineer" game.
Commented by Logman: Knowledge in mechanical engineering may help.
Commented by AndyG: It is a motion planning problem with nonholonomic constraints. It could be solved by Rapidly exploring random tree (RRTs), theory around Lyapunov equation, and Linear quadratic regulator.
Commented by John Coleman: This seems more like optimal control than AI.
Edit: "Near-0 assumption" (optional)
In most case, AI (to be designed) run continuously (i.e. called every time-step).
Thus, with the AI's tuning, Tran0 is usually near-identity, V0 and W0 are usually not so different from 0, e.g. |Seta0|<30 degree,|W0|<5 degree per time-step .
I think that AI based on this assumption would work OK in most case. Although not perfect, it can be considered as a correct solution (I started to think that without this assumption, this question might be too hard).
I faintly feel that this assumption may enable some tricks that use some "linear"-approximation.
The 2nd Alternative Question - "Tune 12 Variables" (easier)
The above question might also be viewed as followed :-
I want to tune all six values and six values' (1st-derivative) to be 0, using lowest amount of time-steps.
Here is a table show a possible situation that AI can face:-
The Multiplier table stores inertia^-1 * r and mass^-1 from the original question.
The Multiplier and Range are constant.
Each timestep, the AI will be asked to pick a tuple of values fi that must be in the range [min_i,max_i] for every i+1-th jet.
Ex. From the table, AI can pick (f0=1,f1=0.1,f2=-1).
Then, the caller will use fi to multiply with the Multiplier table to get values''.
Px'' = f0*0.2+f1*0.0+f2*0.7
Py'' = f0*0.3-f1*0.9-f2*0.6
Pz'' = ....................
SetaX''= ....................
SetaY''= ....................
SetaZ''= f0*0.0+f1*0.0+f2*5.0
After that, the caller will update all values' with formula values' += values''.
Px' += Px''
.................
SetaZ' += SetaZ''
Finally, the caller will update all values with formula values += values'.
Px += Px'
.................
SetaZ += SetaZ'
AI will be asked only once for each time-step.
The objective of AI is to return tuples of fi (can be different for different time-step), to make Px,Py,Pz,SetaX,SetaY,SetaZ,Px',Py',Pz',SetaX',SetaY',SetaZ' = 0 (or very near),
by using least amount of time-steps as possible.
I hope providing another view of the problem will make it easier.
It is not the exact same problem, but I feel that a solution that can solve this version can bring me very close to the answer of the original question.
An answer for this alternate question can be very useful.
The 3rd Alternative Question - "Tune 6 Variables" (easiest)
This is a lossy simplified version of the previous alternative.
The only difference is that the world is now 2D, Fi is also 2D (x,y).
Thus I have to tune only Px,Py,SetaZ,Px',Py',SetaZ'=0, by using least amount of time-steps as possible.
An answer to this easiest alternative question can be considered useful.
I'll try to keep this short and sweet.
One approach that is often used to solve these problems in simulation is a Rapidly-Exploring Random Tree. To give at least a little credibility to my post, I'll admit I studied these, and motion planning was my research lab's area of expertise (probabilistic motion planning).
The canonical paper to read on these is Steven LaValle's Rapidly-exploring random trees: A new tool for path planning, and there have been a million papers published since that all improve on it in some way.
First I'll cover the most basic description of an RRT, and then I'll describe how it changes when you have dynamical constraints. I'll leave fiddling with it afterwards up to you:
Terminology
"Spaces"
The state of your spaceship can be described by its 3-dimension position (x, y, z) and its 3-dimensional rotation (alpha, beta, gamma) (I use those greek names because those are the Euler angles).
state space is all possible positions and rotations your spaceship can inhabit. Of course this is infinite.
collision space are all of the "invalid" states. i.e. realistically impossible positions. These are states where your spaceship is in collision with some obstacle (With other bodies this would also include collision with itself, for example planning for a length of chain). Abbreviated as C-Space.
free space is anything that is not collision space.
General Approach (no dynamics constraints)
For a body without dynamical constraints the approach is fairly straightforward:
Sample a state
Find nearest neighbors to that state
Attempt to plan a route between the neighbors and the state
I'll briefly discuss each step
Sampling a state
Sampling a state in the most basic case means choosing at random values for each entry in your state space. If we did this with your space ship, we'd randomly sample for x, y, z, alpha, beta, gamma across all of their possible values (uniform random sampling).
Of course way more of your space is obstacle space than free space typically (because you usually confine your object in question to some "environment" you want to move about inside of). So what is very common to do is to take the bounding cube of your environment and sample positions within it (x, y, z), and now we have a lot higher chance to sample in the free space.
In an RRT, you'll sample randomly most of the time. But with some probability you will actually choose your next sample to be your goal state (play with it, start with 0.05). This is because you need to periodically test to see if a path from start to goal is available.
Finding nearest neighbors to a sampled state
You chose some fixed integer > 0. Let's call that integer k. Your k nearest neighbors are nearby in state space. That means you have some distance metric that can tell you how far away states are from each other. The most basic distance metric is Euclidean distance, which only accounts for physical distance and doesn't care about rotational angles (because in the simplest case you can rotate 360 degrees in a single timestep).
Initially you'll only have your starting position, so it will be the only candidate in the nearest neighbor list.
Planning a route between states
This is called local planning. In a real-world scenario you know where you're going, and along the way you need to dodge other people and moving objects. We won't worry about those things here. In our planning world we assume the universe is static but for us.
What's most common is to assume some linear interpolation between the sampled state and its nearest neighbor. The neighbor (i.e. a node already in the tree) is moved along this linear interpolation bit by bit until it either reaches the sampled configuration, or it travels some maximum distance (recall your distance metric).
What's going on here is that your tree is growing towards the sample. When I say that you step "bit by bit" I mean you define some "delta" (a really small value) and move along the linear interpolation that much each timestep. At each point you check to see if you the new state is in collision with some obstacle. If you hit an obstacle, you keep the last valid configuration as part of the tree (don't forget to store the edge somehow!) So what you'll need for a local planner is:
Collision checking
how to "interpolate" between two states (for your problem you don't need to worry about this because we'll do something different).
A physics simulation for timestepping (Euler integration is quite common, but less stable than something like Runge-Kutta. Fortunately you already have a physics model!
Modification for dynamical constraints
Of course if we assume you can linearly interpolate between states, we'll violate the physics you've defined for your spaceship. So we modify the RRT as follows:
Instead of sampling random states, we sample random controls and apply said controls for a fixed time period (or until collision).
Before, when we sampled random states, what we were really doing was choosing a direction (in state space) to move. Now that we have constraints, we randomly sample our controls, which is effectively the same thing, except we're guaranteed not to violate our constraints.
After you apply your control for a fixed time interval (or until collision), you add a node to the tree, with the control stored on the edge. Your tree will grow very fast to explore the space. This control application replaces linear interpolation between tree states and sampled states.
Sampling the controls
You have n jets that individually have some min and max force they can apply. Sample within that min and max force for each jet.
Which node(s) do I apply my controls to?
Well you can choose at random, or your can bias the selection to choose nodes that are nearest to your goal state (need the distance metric). This biasing will try to grow nodes closer to the goal over time.
Now, with this approach, you're unlikely to exactly reach your goal, so you need to define some definition of "close enough". That is, you will use your distance metric to find nearest neighbors to your goal state, and then test them for "close enough". This "close enough" metric can be different than your distance metric, or not. If you're using Euclidean distance, but it's very important that you goal configuration is also rotated properly, then you may want to modify the "close enough" metric to look at angle differences.
What is "close enough" is entirely up to you. Also something for you to tune, and there are a million papers that try to get you a lot closer in the first place.
Conclusion
This random sampling may sound ridiculous, but your tree will grow to explore your free space very quickly. See some youtube videos on RRT for path planning. We can't guarantee something called "probabilistic completeness" with dynamical constraints, but it's usually "good enough". Sometimes it'll be possible that a solution does not exist, so you'll need to put some logic in there to stop growing the tree after a while (20,000 samples for example)
More Resources:
Start with these, and then start looking into their citations, and then start looking into who is citing them.
Kinodynamic RRT*
RRT-Connect
This is not an answer, but it's too long to place as a comment.
First of all, a real solution will involve both linear programming (for multivariate optimization with constraints that will be used in many of the substeps) as well as techniques used in trajectory optimization and/or control theory. This is a very complex problem and if you can solve it, you could have a job at any company of your choosing. The only thing that could make this problem worse would be friction (drag) effects or external body gravitation effects. A real solution would also ideally use Verlet integration or 4th order Runge Kutta, which offer improvements over the Euler integration you've implemented here.
Secondly, I believe your "2nd Alternative Version" of your question above has omitted the rotational influence on the positional displacement vector you add into the position at each timestep. While the jet axes all remain fixed relative to the frame of reference of the ship, they do not remain fixed relative to the global coordinate system you are using to land the ship (at global coordinate [0, 0, 0]). Therefore the [Px', Py', Pz'] vector (calculated from the ship's frame of reference) must undergo appropriate rotation in all 3 dimensions prior to being applied to the global position coordinates.
Thirdly, there are some implicit assumptions you failed to specify. For example, one dimension should be defined as the "landing depth" dimension and negative coordinate values should be prohibited (unless you accept a fiery crash). I developed a mockup model for this in which I assumed z dimension to be the landing dimension. This problem is very sensitive to initial state and the constraints placed on the jets. All of my attempts using your example initial conditions above failed to land. For example, in my mockup (without the 3d displacement vector rotation noted above), the jet constraints only allow for rotation in one direction on the z-axis. So if aZ becomes negative at any time (which is often the case) the ship is actually forced to complete another full rotation on that axis before it can even try to approach zero degrees again. Also, without the 3d displacement vector rotation, you will find that Px will only go negative using your example initial conditions and constraints, and the ship is forced to either crash or diverge farther and farther onto the negative x-axis as it attempts to maneuver. The only way to solve this is to truly incorporate rotation or allow for sufficient positive and negative jet forces.
However, even when I relaxed your min/max force constraints, I was unable to get my mockup to land successfully, demonstrating how complex planning will probably be required here. Unless it is possible to completely formulate this problem in linear programming space, I believe you will need to incorporate advanced planning or stochastic decision trees that are "smart" enough to continually use rotational methods to reorient the most flexible jets onto the currently most necessary axes.
Lastly, as I noted in the comments section, "On May 14, 2015, the source code for Space Engineers was made freely available on GitHub to the public." If you believe that game already contains this logic, that should be your starting place. However, I suspect you are bound to be disappointed. Most space game landing sequences simply take control of the ship and do not simulate "real" force vectors. Once you take control of a 3-d model, it is very easy to predetermine a 3d spline with rotation that will allow the ship to land softly and with perfect bearing at the predetermined time. Why would any game programmer go through this level of work for a landing sequence? This sort of logic could control ICBM missiles or planetary rover re-entry vehicles and it is simply overkill IMHO for a game (unless the very purpose of the game is to see if you can land a damaged spaceship with arbitrary jets and constraints without crashing).
I can introduce another technique into the mix of (awesome) answers proposed.
It lies more in AI, and provides close-to-optimal solutions. It's called Machine Learning, more specifically Q-Learning. It's surprisingly easy to implement but hard to get right.
The advantage is that the learning can be done offline, so the algorithm can then be super fast when used.
You could do the learning when the ship is built or when something happens to it (thruster destruction, large chunks torn away...).
Optimality
I observed you're looking for near-optimal solutions. Your method with parabolas is good for optimal control. What you did is this:
Observe the state of the system.
For every state (coming in too fast, too slow, heading away, closing in etc.) you devised an action (apply a strategy) that will bring the system into a state closer to the goal.
Repeat
This is pretty much intractable for a human in 3D (too many cases, will drive you nuts) however a machine may learn where to split the parabolas in every dimensions, and devise an optimal strategy by itself.
THe Q-learning works very similarly to us:
Observe the (secretized) state of the system
Select an action based on a strategy
If this action brought the system into a desirable state (closer to the goal), mark the action/initial state as more desirable
Repeat
Discretize your system's state.
For each state, have a map intialized quasi-randomly, which maps every state to an Action (this is the strategy). Also assign a desirability to each state (initially, zero everywhere and 1000000 to the target state (X=0, V=0).
Your state would be your 3 positions, 3 angles, 3translation speed, and three rotation speed.
Your actions can be any combination of thrusters
Training
Train the AI (offline phase):
Generate many diverse situations
Apply the strategy
Evaluate the new state
Let the algo (see links above) reinforce the selected strategies' desirability value.
Live usage in the game
After some time, a global strategy for navigation emerges. You then store it, and during your game loop you simply sample your strategy and apply it to each situation as they come up.
The strategy may still learn during this phase, but probably more slowly (because it happens real-time). (Btw, I dream of a game where the AI would learn from every user's feedback so we could collectively train it ^^)
Try this in a simple 1D problem, it devises a strategy remarkably quickly (a few seconds).
In 2D I believe excellent results could be obtained in an hour.
For 3D... You're looking at overnight computations. There's a few thing to try and accelerate the process:
Try to never 'forget' previous computations, and feed them as an initial 'best guess' strategy. Save it to a file!
You might drop some states (like ship roll maybe?) without losing much navigation optimality but increasing computation speed greatly. Maybe change referentials so the ship is always on the X-axis, this way you'll drop x&y dimensions!
States more frequently encountered will have a reliable and very optimal strategy. Maybe normalize the state to make your ship state always close to a 'standard' state?
Typically rotation speeds intervals may be bounded safely (you don't want a ship tumbling wildely, so the strategy will always be to "un-wind" that speed). Of course rotation angles are additionally bounded.
You can also probably discretize non-linearly the positions because farther away from the objective, precision won't affect the strategy much.
For these kind of problems there are two techniques available: bruteforce search and heuristics. Bruteforce means to recognize the problem as a blackbox with input and output parameters and the aim is to get the right input parameters for winning the game. To program such a bruteforce search, the gamephysics runs in a simulation loop (physics simulation) and via stochastic search (minimax, alpha-beta-prunning) every possibility is tried out. The disadvantage of bruteforce search is the high cpu consumption.
The other techniques utilizes knowledge about the game. Knowledge about motion primitives and about evaluation. This knowledge is programmed with normal computerlanguages like C++ or Java. The disadvantage of this idea is, that it is often difficult to grasp the knowledge.
The best practice for solving spaceship navigation is to combine both ideas into a hybrid system. For programming sourcecode for this concrete problem I estimate that nearly 2000 lines of code are necessary. These kind of problems are normaly done within huge projects with many programmers and takes about 6 months.
I am trying to find the optimal solution to a Sliding Block Puzzle of any length using the A* algorithm.
The Sliding Block Puzzle is a game with white (W) and black tiles (B) arranged on a linear game board with a single empty space(-). Given the initial state of the board, the aim of the game is to arrange the tiles into a target pattern.
For example my current state on the board is BBW-WWB and I have to achieve BBB-WWW state.
Tiles can move in these ways :
1. slide into an adjacent empty space with a cost of 1.
2. hop over another tile into the empty space with a cost of 1.
3. hop over 2 tiles into the empty space with a cost of 2.
I have everything implemented, but I am not sure about the heuristic function. It computes the shortest distance (minimal cost) possible for a misplaced tile in current state to a closest placed same color tile in goal state.
Considering the given problem for the current state BWB-W and goal state BB-WW the heuristic function gives me a result of 3. (according to minimal distance: B=0 + W=2 + B=1 + W=0). But the actual cost of reaching the goal is not 3 (moving the misplaced W => cost 1 then the misplaced B => cost 1) but 2.
My question is: should I compute the minimal distance this way and don't care about the overestimation, or should I divide it by 2? According to the ways tiles can move, one tile can for the same cost overcome twice as much(see moves 1 and 2).
I tried both versions. While the divided distance gives better final path cost to the achieved goal, it visits more nodes => takes more time than the not divided one. What is the proper way to compute it? Which one should I use?
It is not obvious to me what an admissible heuristic function for this problem looks like, so I won't commit to saying, "Use the divided by two function." But I will tell you that the naive function you came up with is not admissible, and therefore will not give you good performance. In order for A* to work properly, the heuristic used must be admissible; in order to be admissible, the heuristic must absolutely always give an optimistic estimate. This one doesn't, for exactly the reason you highlight in your example.
(Although now that I think about it, dividing by two does seem like a reasonable way to force admissibility. I'm just not going to commit to it.)
Your heuristic is not admissible, so your A* is not guaranteed to find the optimal answer every time. An admissible heuristic must never overestimate the cost.
A better heuristic than dividing your heuristic cost by 3, would be: instead of adding the distance D of each letter to its final position, add ceil(D/2). This way, a letter 1 or 2 away, gets a 1 value, 3 or 4 away, gets a 2 value, an so on.