Printing two pyramids side by side (ASCII graphics) - c

Question

I am able to crack it up till #symbol but not after that.
I am not aware of logic for implementing two pyramids side by side.
int main()
{
int i, space, n, j, l, k=0;
printf("Enter number excluding 1 and -ve numbers: ");
scanf("%d",&n);
for(i=1; i<=n-1; ++i, k=0)
{
for(j=0;j<(n/2);j++)
{
printf("\t");
}
for(space=1; space<=n-i; ++space)
{
printf(" ");
}
while(k != 2*i-1)
{
printf("* ");
++k;
}//End of upper star pyramid
printf("\n");
}
//logic for #
for(j=1;j<=(n-1);j++)
{
for(l=0;l<(n/2);l++)
{
printf("\t");
}
for(l=1; l<space; ++l)
{
printf(" ");
}
printf("#");
for(l=1; l<=n; l++)
{
printf(" ");
}
printf("#\n");
}
//after that I dont know how to work with two different pyramids side by side
return 0;
}

Answer 1

Here's an attempt...
Have used "#define"s for the characters to be printed.
Have utilized three do-while loops to break the task of printing the top pyramid, the "#"s and the bottom pyramid.
The solution would work for the examples provided or any "Odd" number, provided by the user.
For even numbers,the solution needs to be worked upon(either ways the top of the pyramid would not align at the center for even numbers).
Hope this is helpful.....feel free to play around with the code....
#include <stdio.h>
#define SPACE ' '
#define STAR '*'
#define AT '#'
int main(){
int num = 7;//input from the user, have used 7 as an example
int total_hor_length = num * 3;//# of characters to be printed on each line
int i = num;
int j = 0;
while(i > 0){//calculate the iterations
j++; //required for top and bottom
i -= 2; //Pyramids
}
int first_print = j; //# first loop iteration
int last_print = first_print; //# last loop iteration
int center_print = (num * 2 - 1)-(first_print + last_print);//# center loop
int pos = total_hor_length/2; //position of top of center pyramid
int count = 0;
int k;
i = 0;//re-initialize i for the first loop
//Logic for the Top Pyramid(first loop)
do{
for(k = 0;k < total_hor_length;++k){ //for input "n"
if((k < pos || k > pos+count)) //by the time this loop finishes
printf("%c",SPACE); //pos will be "n-1"
else //and count will be "n+1"
printf("%c",STAR);
}
putchar('\n');
pos--;
count+=2;
i++;
}while( first_print > i);
i = 0;//re-initialize i for the center loop
//Logic for the "#"s (second loop)
do{
for(k = 0;k < total_hor_length;++k){ //utilizing the values of "count"
if((k == count-1 || k == (count-1)+pos)) //and pos procured from the previous
printf("%c",AT); //loop to print the "#"s
else
printf("%c",SPACE);
}
putchar('\n');
i++;
}while(center_print > i);
i = 0;//re-initialize i for the center loop
//Logic for the Bottom Pyramids (Last loop)
do{
for(k = 0;k < total_hor_length;++k){
if(i == 0){
if((k <= pos-i) || (k > pos + num + i && k < total_hor_length - i))
printf("%c",STAR);
else if(k == pos+1||k == pos+num) //printing the line containing
printf("%c",AT); // asterisk and "#" symbols
else
printf("%c",SPACE);
}
else{
if((k >= i && k <= pos-i) || (k > pos + num + i && k < total_hor_length - i))
printf("%c",STAR); //printing the last lines
else
printf("%c",SPACE);
}
}
putchar('\n');
i++;
}while(i < last_print);
}