How can I get the next element of an array in C? - c

Question

I am new to C, and I have to create a transliterator for my hw assignment at university. In Polish, the sound [tsh] as in chair is represented by two letters: "cz". I have to create a program that will turn every "cz" into 4 (F.e. zaskoczony = zasko4ony). I have a char array(defined at the beginning of the program) and I can get "c" and change it to anything I want, but I'm struggling with getting "z" checked, because I cannot get the +1 element in my string array.
I've tried putting i+1 into the array's brackets, tried using a variable, but nothing seems to work.
while(i<100){
intText[i] = someString[i];
if(intText[i] == 'c'){
int increasedI=i+1;
printf(" %d", increasedI);
if(intText[increasedI] == 'z'){
printf("4");
}
}else{
putchar(intText[i]);
}
i++;
}

Answer 1

How can I get the next element of an array in C?
someString[i + 1]
A problem with OP's code was that it did not advance i an extra 1 nor populated intText[increasedI] before using it.
if(intText[i] == 'c'){
int increasedI=i+1;
printf(" %d", increasedI);
// if(intText[increasedI] == 'z'){
if(someString[increasedI] == 'z'){
printf("4");
}
i++; //add
....
i++;
Also string processing should stop when the null character is reached, not i== 100.
// while(i<100){
while(someString[i]){
Keep separate indexes of reading and writing. Walk down the string, making the desire substation.
As long as the substitution string, example "4", is no longer than the source, "cz", we can do an in-place substitution.
// in-place substitution
size_t in_index = 0;
size_t out_index = 0;
// Loop until end-of-string
while (someString[in_index] != '\0') {
// Test for special combination
if (someString[in_index] == 'c' && someString[in_index + 1] == 'z') {
in_index += 2;
someString[out_index++] = '4';
} else{
someString[out_index++] = someString[in_index++];
}
}
someString[out_index] = '\0';
puts(someString);

Answer 2

Thank everyone for your helpful advice which helped me find my own solution. This is the code which meets my expectations and looks quite simple.
int main()
{
char someString[100] = "cenczetkczacczka";
int i = 0;
while(someString[i] != '\0'){
if(someString[i] == 'c' && someString[i + 1] == 'z'){
printf("4");
i++;
}else{
putchar(someString[i]);
}
i++;
}
return 0;
}