Reading text file into an array in C - c

Question

I want to parse a .txt file into a 1D array in C. I'm using the fgets function to read the contents of the file into the array("waveform" as the array into which the file contents are to be stored - defined as a "char"). The saved values need to be saved into a new array as integer values. I am not sure where I am going wrong.
P.S: I am new to programming in C, please bear with me :)
Please ignore the indexing issues, done due to pasting
int main(){
int a, win[10];
FILE *filename = fopen("testFile.txt","r");
char waveform[10];
if (filename == NULL)
{
printf("Error opening file.\n");
exit(8);
}
for(int i =0;1;i++){
if(fgets(waveform[i], 10, filename) == NULL);
break;
if(i < 10)
{
a = atoi(waveform[i]);
win[i] = a;
}
}
fclose(filename);
return 0;
}
Compiler errors - image embedded
Data in testFile.txt:
1 to 10 in a row vector.

Answer 1

You are on the right track. Here is my contribution on the topic:
Open the file (fopen)
Count number of lines (getc and rewind)
Read all lines into array (getline)
Free memory and close file (free and fclose)
Code example:
#include <stdlib.h>
#include <stdio.h>
int main(int argc, char *argv[])
{
// Open File
const char fname[] = "testFile.txt";
FILE *fp = fopen(fname, "r");
if( !fp )
goto error_open_file;
printf("Opened file: %s\n", fname);
// Count Lines
char cr;
size_t lines = 0;
while( cr != EOF ) {
if ( cr == '\n' ) {
lines++;
}
cr = getc(fp);
}
printf("Number of lines: %ld\n", lines);
rewind(fp);
// Read data
{// 'goto' + data[lines] causes error, introduce block as a workaround
char *data[lines];
size_t n;
for (size_t i = 0; i < lines; i++) {
data[i] = NULL;
size_t n = 0;
getline(&data[i], &n, fp);
if ( ferror( fp ) )
goto error_read_file;
}
for (size_t i = 0; i < lines; i++) {
printf("%s", data[i]);
free(data[i]);
}
}
// Close File
fclose(fp);
return 0;
error_read_file:
perror("fopen ");
return 1;
error_open_file:
perror("getline ");
return 2;
}

Answer 2

There are several errors in this loop
for(int i =0;1;i++){
if(fgets(waveform[i], 10, filename) == NULL);
break;
if(i < 10)
{
a = atoi(waveform[i]);
win[i] = a;
}
}
For starters there is a semicolon after the if statement
if(fgets(waveform[i], 10, filename) == NULL);
^^^
Secondly the fgets call
fgets(waveform[i], 10, filename)
^^^
is invalid because the type of the expression waveform[i] is char.
And correspondingly this statement
a = atoi(waveform[i]);
is also invalid.
There must be at least
fgets( waveform, 10, filename)
and
a = atoi( waveform );
I suppose that each line of the file contains exactly one number. (Otherwise you should use for example sscanf to extract numbers from a line using an internal additional loop.)
The loop can look like
int i = 0;
for ( ; i < 10 && fgets( waveform, 10, filename) != NULL; i++ )
{
a = atoi( waveform );
win[i] = a;
}
After the loop the variable i will contain the actual number of elements of the array win.
Pay attention to that the name filename is not good for a pointer of the type FILE *. File name is the string "testFile.txt" in your code.

Answer 3

If you want to use the fgets() function you don't have to put it into a loop. Indeed, the second argument of fgets() is the number of elements you want to read.
I would have put the fgets() into a singl-line instruction, and then loop from 0 to 10 to make the conversion from char to int with the atoi() function.
Moreover, you have a ; at the end of your if() statement, so you'll execute it not in the way you want.