How to print a row/column/diagonal from matrix - c

Question

I am trying to get my program print out the rows, columns or diagonals if they don't equal the magic square rule, for example,
if the matrix is
1 9 5
2 4 3
6 8 7
Row 1 [2, 4, 3] doesn't work
Row 2 [6, 8, 7] doesn't work
Column 0 [1, 2, 6] doesn't work
Diagonal 1 [1, 4, 7] doesn't work
I've tried print("%d", matrix[row])
#include <stdio.h>
#include <stdbool.h>
#include <unistd.h>
int main()
{
//declared variables
int size = 3;
int matrix[3][3];
int row, column = 0;
int sum0, sum1, sum2;
int flag = 0;
//ask user to input 1-9 and scans it
printf("Enter in the values: \n");
for (row = 0; row < size; row++){
for (column = 0; column < size; column++)
scanf("%d", &matrix[row][column]);
}
//enters number into magic square format
printf("You entered: \n");
for (row = 0; row < size; row++) {
printf("\n");
for (column = 0; column < size; column++) {
printf("%d ", matrix[row][column]);
}
}
//diagonal calculations
sum0 = 0;
for (row = 0; row < size; row++) {
for (column = 0; column < size; column++) {
if (row == column)
sum0 = sum0 + matrix[row][column];
}
}
//row calculations
for (row = 0; row < size; row++) {
sum1 = 0;
for (column = 0; column < size; column++) {
sum1 = sum1 + matrix[row][column];
}
if (sum0 == sum1)
flag = 1;
else {
flag = 0;
break;
}
}
//column calculations
for (row = 0; row < size; row++) {
sum1 = 0;
for (column = 0; column < size; column++) {
sum2 = sum2 + matrix[row][column];
}
if (sum1 == sum2)
flag = 1;
else {
flag = 0;
break;
}
}
printf("\nAnalyzing...\n");
if (flag == 1) {
sleep(2);
printf("This is a magic square!\n");
}
else {
sleep(2);
printf("This is not a magic square!\n");
}
return 0;
}

Answer 1

You have to use loops to print each character separately.
printf(3) offers no way to print an array of integers.

Answer 2

it seems weired that initailzied sum1 in colum calculations
//column calculations
for (row = 0; row < size; row++) {
sum1 = 0; // <= sum2 = 0; maybe
for (column = 0; column < size; column++) {
sum2 = sum2 + matrix[row][column];
}
if (sum1 == sum2)
flag = 1;
else {
flag = 0;
break;
}
}
and if row calcuations used loop as below
for(row = 0; row < size; row++){
for(column = 0; column < size; column++){
// access to matrix[row][column]
}
}
column calculations loop will be revised
for(column = 0; column < size; column++){
for(row = 0; row < size; row++){
// access to matrix[row][column]
}
}
plus, you can write the diagonal calculations simply
//diagonal calculations
sum0 = 0;
for (int diag = 0; diag < size; diag++) {
sum0 += matrix[diag][diag];
}

Answer 3

I think you get the logic:
const int x = 5;
const int y = 7;
int matrix[x][y];
for (int j = 0; j < x; ++j)
{
for (int i = 0; i < y; ++i)
{
matrix[j][i] = j + i;
printf("%3d ", matrix[j][i]);
}
putchar('\n');
}
puts("\nPrint a column: ");
for(int i = 0; i < x; i++)
{
printf("%3d ", matrix[i][0 /*constant*/]);
}
puts("\nPrint a row: ");
for (int k = 0; k < 7; ++k)
{
printf("%3d ", matrix[0/*constant*/][k]);
}
puts("\nPrint a diagonal");
for (int l = 0, m = 0; l < x && m < y; ++l, ++m)
{
printf("%3d ", matrix[l][m]);
}