Find frequency of occurrence, minmax without storing input - c

Question

The task is to read N digits within a range from 0 to 9 and find frequency of occurrence for entered digits. In addition to that, I need to find min and max values and also the most common number(s). Using at least 3 functions is required(storing input isn't allowed))
So far I completed finding occurrences and min and max value entered.
I have problems with finding the most common number(s) and creating functions. I have created separate variables for each number to find the frequency.
Also, this code doesn't seem to be very good and in case you have better solutions for this problem, please share.
{
int n=0;
int max=0,min=9;
int freq0=0,freq1=0,freq2=0,freq3=0,freq4=0,freq5=0,freq6=0,freq7=0,freq8=0,freq9=0;
for (;;)
{
printf ("Please enter the number in range from 0 to 9 (to break enter: 11): ");
scanf ("%d",&n);
if (n==11)//to exit the loop 11 is setteled as a stop value
break;
if (n==0)
freq0++;
if (n==1)
freq1++;
if (n==2)
freq2++;
if (n==3)
freq3++;
if (n==4)
freq4++;
if (n==5)
freq5++;
if (n==6)
freq6++;
if (n==7)
freq7++;
if (n==8)
freq8++;
if (n==9)
freq9++;
if (n>max)
max=n;
if (n<min)
min=n;
}
printf ("Number 0 occured %d times\n",freq0);
printf ("Number 1 occured %d times\n",freq1);
printf ("Number 2 occured %d times\n",freq2);
printf ("Number 3 occured %d times\n",freq3);
printf ("Number 4 occured %d times\n",freq4);
printf ("Number 5 occured %d times\n",freq5);
printf ("Number 6 occured %d times\n",freq6);
printf ("Number 7 occured %d times\n",freq7);
printf ("Number 8 occured %d times\n",freq8);
printf ("Number 9 occured %d times\n",freq9);
printf ("highest %d \n", max);
printf ("smallest %d\n",min);
return 0;
}

Answer 1

#include <stdio.h>
#include <limits.h>
#define MIN(a,b) (((a)<(b))?(a):(b))
#define MAX(a,b) (((a)>(b))?(a):(b))
int main(void) {
int n=0;
int value_max=INT_MIN;
int value_min=INT_MAX;
int freq[10] = {0};
for(;;)
{
printf ("Please enter the number in range from 0 to 9 (to break enter: 11): \n");
scanf ("%d",&n);
if (n==11) break;
freq[n]++;
value_max = MAX(n, value_max);
value_min = MIN(n, value_min);
}
for(n=0; n<10; ++n)
{
if (freq[n] == 0) continue;
printf("Frequency of %d : %d\n", n, freq[n]);
}
printf("Maximum value : %d\n", value_max);
printf("Minimum value : %d\n", value_min);
return 0;
}
Test Input
4 5 6 1 2 3 4 5 6 11
Output
Frequency of 1 : 1
Frequency of 2 : 1
Frequency of 3 : 1
Frequency of 4 : 2
Frequency of 5 : 2
Frequency of 6 : 2
Maximum value : 6
Minimum value : 1

Answer 2

Try this.
#include <stdio.h>
int min(int a, int b) { return (a < b) ? a : b; }
int max(int a, int b) { return (a > b) ? a : b; }
int valid(int n) { return (n >= 0 && n <= 9) ? 1 : 0; }
int main() {
int i, n, min_number = 10, max_number = -1, max_frequency = 0;
int freq[10] = {0,0,0,0,0,0,0,0,0,0};
// Read all numbers from input (read until end of file or press Ctrl+Z in console)
while (scanf("%d", &n) > 0) {
if (valid(n) == 0) {
printf("Number %d is invalid and will be ignored\n", n);
continue;
}
freq[n] += 1;
min_number = min(min_number, n);
max_number = max(max_number, n);
max_frequency = max(max_frequency, freq[n]);
}
printf("Occurences of digits:\n");
for (i = 0; i < 10; i++)
printf("Number %d occured %d times\n", i, freq[i]);
printf("\n\nMin value: %d\n", min);
printf("Max value: %d\n", max);
// Print numbers with greatest frequency
printf("\n\nMost common numbers: ");
for (i = 0; i < 10; i++) {
if (freq[i] == max_frequency)
printf("%d\n", i);
}
return 0;
}

Answer 3

#include <stdio.h>
void test(int N){
int arr[] = {0,0,0,0,0,0,0,0,0,0};
for (int i =0; i < N; i++){
int num;
printf ("Please enter the number in range from 0 to 9 (to break enter: 11): ");
scanf ("%d",&num);
if (num==11) break;
if (num>9 || num<0){
printf("Number is not in range 0..9! Try another number..\n");
i--;
continue;
}
arr[num]++;
}
int max = 0, min = 9, max_occurrences = 0, min_occurrences = N;
for (int i = 0; i < 10; i++){
printf ("Number %d occured %d times\n", i, arr[i]);
max_occurrences = arr[max_occurrences] < arr[i] && arr[i]!=0? i : max_occurrences;
min_occurrences = arr[min_occurrences] > arr[i] && arr[i]!=0? i : min_occurrences;
max = max < i && arr[i]!=0? i : max;
min = min > i && arr[i]!=0? i : min;
}
printf("max occurrences : %d \nmin occurrences : %d \nmax common : %d \nmin common : %d \n ", max_occurrences, min_occurrences, max, min);
}
int main()
{
test(6);
return 0;
}