putting '0' before ID number that the user input [closed] - c

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I'm a new c programmer.
I was asked to get an ID number as an input and if the ID length < 9 I need to put '0' before the number.
example:
input: 12345
output: 000012345
I can use the libraries: stdio, stdlib, string, math and time.

Answer 1

You can use printf for this:
#include <stdio.h>
int main () {
printf("%09d\n", 12345);
return(0);
}
Documentation

Answer 2

There is an easy solution in here.
But if you want a hard solution, where you juggle around with strings and such, you can do the following:
convert your id into a string (if it isn't already one, but argv should a string by default)
calculate the number of zeros you need, by doing 9-idString Length
create a "buffer" string variable
for loop from 0 to 9-idString and use strcat to add "0"s to your buffer string.
add your id to your buffer string using strcat
Example code would be something like this:
int id = 12345;
char idstring[10];
char buffer[10];
sprintf(idstring, "%d", id);
int missingZerosCount = 9 - strlen(idstring);
strcpy(buffer, "");
while (missingZerosCount > 0) {
strcat(buffer, "0");
missingZerosCount--;
}
strcat(buffer, idstring);
argv variant:
char idstring[10];
char buffer[10];
sprintf(idstring, "%s", argv[1]);
int missingZerosCount = 9 - strlen(idstring);
strcpy(buffer, "");
while (missingZerosCount > 0) {
strcat(buffer, "0");
missingZerosCount--;
}
strcat(buffer, idstring);