I use Autohotkey to replace some of the broken buttons on my mouse and to have an auto clicker and other quality of life hotkys and such, I have them in a folder with a batch file. I would like the bat file to open them all without having to type the names of the scripts one by one, sort of having an 'all' character like *.ahk. Is this possible?
I'm not completely sure I got the question , but if you want to run all .ahk files you can use something like this:
for %%a in (*.ahk) do start "" "%%~fa"
Related
I'm a first-day user of IrfanView and have a question. I have a bunch of multi-page tiff files and I want to split all of them individually. So I write a batch file with the command like this:
C:\Program Files\IrfanView>i_view64.exe D:\originaldirectory\filename1.tif /extract=(D:\newdirectory,tif)
C:\Program Files\IrfanView>i_view64.exe D:\originaldirectory\filename2.tif /extract=(D:\newdirectory,tif)
...and so on...
I put the batch file on D drive, let's say in folder "batchfolder". But it can't do the job, this message shows up for each unsuccessful case (all of them were unsuccessful):
D:\batchfolder>C:\Program Files\IrfanView D:\originaldirectory\filename1.tif /extract=(D:\newdirectory,tif) 1>i_view64.exe
'C:\Program' is not recognized as an internal or external command, operable program or batch file.
I guess that has something to do with the batch file location, so I bring it to C drive. But still it can't run properly, this time a different message shows up:
C:\>C:\Program Files\IrfanView D:\originaldirectory\filename1.tif /extract=(D:\newdirectory,tif) 1>i_view64.exe
Access is denied.
This C:\>C:\ makes me think maybe the C:\ part on the batch file was redundant. So I take it out to make it look like this:
Program Files\IrfanView>i_view64.exe D:\originaldirectory\filename1.tif /extract=(D:\newdirectory,tif)
...
But it doesn't work, either with the batch file on D or C drive.
I then try to type it directly in the CMD window and it works normally, like this:
C:\Program Files\IrfanView>i_view64.exe D:\originaldirectory\filename1.tif /extract=(D:\newdirectory,tif)
Can you tell where my batch file goes wrong?
This is another question. Typing (or copy and paste) the batch file contents into the CMD works OK. But upon successful splitting, the original, multi-image file automatically opens. How can I deactivate this feature?
Note: Cross-post here: https://irfanview-forum.de/showthread.php?t=11150&p=47111#post47111. Hope it doesn't violate policy.
enclose paths/filenames with spaces into quotes to tell the interpreter, it's not two words, but one string (or even better: get used to always enclose path/filenames):
"C:\Program Files\IrfanView\i_view64.exe" "D:\originaldirectory\filename1.tif" /extract=("D:\newdirectory",tif)`
Before you build a batchfile with dozends or hundreds of nearly identical lines, use a for loop to process all .tif files in the folder:
#echo off
for %%a in ("D:\originaldirectory\*.tif") do (
"C:\Program Files\IrfanView\i_view64.exe" "%%~fa" /extract=("D:\newdirectory",tif)
)
see for /? for more information.
You need to call the executable with quotes in the batch. Also, the > in the path will not work either. Also consider using a for loop instead of creating single batch lines.
Please try this:
"C:\Program Files\IrfanView\i_view64.exe" "D:\originaldirectory\filename1.tif" /extract=("D:\newdirectory",tif)
So what i'm trying to do is get a selected file from File explorer, and copy it then paste it into a new folder via a batch file upon clicking it....is there a way?
One way I can think about you doing that is by creating a some sort of data base thing
For Example
#echo off
:fileSelect
echo Which folder do you want?
set /p folderName=
goto %folderName%
You can do it that way. Then you will have to manually put in the locations the files like so
:"Files Name here"
copy C:\"Files location" C:\"Designated location to paste file"
goto fileSelect
That's one simple way of doing it. If that's not exactly what you want or if its unclear let me know and I will attempt to help you find another way to do it.
I am writing a batch file on my Windows 8.1 machine. In one section of my batch file I need to start a command prompt in the "current working directory".
So far, this is what my batch file looks like:
#echo OFF
set WORKING=%cwd%
start cmd.exe /K pushd %WORKING%
exit
Let's say the batch file is located in the folder C:\Temp\Utilities. If I open an explorer window and double click the batch file to run it everything works great. A new command prompt is created in the directory C:\Temp\Utilities. However, if I right-click the batch file and select Run as administrator the working directory is no longer the location of the batch file, it's C:\Windows\System32.
Similarly, if I create a shortcut to the batch file in a different folder (for example. C:\Temp) and repeat the two steps above the results are the same. If I double click the shortcut and run it as a normal user the working directory is what I would expect. (Note, the working directory for the shortcut it's whatever is set for "Start in" of the shortcut properties, not the location of the batch file.) If I right click the shortcut and run it as administrator I again get a command prompt opened to the folder C:\Windows\System32.
I assume this is a "bug" or "feature" (if you want to call it that) in Windows 8.1 and it probably happens because execution environments for programs run as administrator are forced to run in the System32 folder? (I remember with Windows 7 this did not happen so it must be a new feature to Windows 8.)
I found one way to fix the issue and stop the command prompt from starting in C:\Windows\System32. I did this by modifying the following line in the batch file:
set WORKING=%~dp0
Doing it this way sets the working directory to the location of the batch file. With this change, no matter how I run the batch file or the shortcut (administrator or normal) the working directory ends up being the same, C:\Temp\Utilities.
The problem with this solution is I don't want the working directory to always be the location of the batch file. If the batch file is run directly then it's okay but if I run it from a shortcut I need the working directory to be whatever is set in the "Start in" property of that shortcut. For example, if the batch file is located in the folder D:\Temp\Utilities this is what I need to happen regardless of whether I run as administrator or not:
Shortcut Location Start In Property Command Prompt Working Directory
-------------------- ------------------- ------------------------------------------
C:\Temp <undefined> D:\Temp\Utilities
C:\Data\bin C:\Data\bin C:\Data\bin
C:\Data\bin D:\Temp\Utilities D:\Temp\Utilities
What this means is I can't always use %~dp0 to set the working directory in my batch file. What I need is some way for the batch file to know if it was run either directly or by a shortcut. If the batch file is run directly then the working directory is easy to get, it's just the value of %cwd%. If the batch file is run by using a shortcut, I don't know how to get the "Start in" property inside the batch file.
Does anyone know how I can do these two things inside my batch file:
1. Check whether it was run directly or by a shortcut.
2. If run by a shortcut, get the "Start in" property of the shortcut that started it.
Thank you,
Orangu
UPDATE
I found sort-of a "hackish" way to fix the issue. For the shortcut I edited the "Target" field and changed it to the following:
cmd.exe /k pushd "C:\Temp" && "D:\Temp\Utilities\batchfile.bat"
Now the working directory can be obtained by calling %CD% in the batch file and this works for both administrator and normal users. It does not, however, work for the case when I run the batch file directly. I still need to use %~dp0 in that case.
I don't like this solution, however, because it requires me to manually change all shortcuts I make and it also makes the icon look like a cmd prompt icon rather than a batch file.
Have you already considered to not use shortcuts at all?
You could e.g. create a batchfile_exec.bat containing your call
REM optionally do
REM cd /D working_directory
REM if you want to force a special working directory
D:\Temp\Utilities\batchfile.bat
and replace all the shortcuts with batchfile_exec.bat. If you double-click batchfile_exec.bat, the working directory will be the one containing batchfile_exec.bat.
I personally don't like Windows shortcuts that much, because they are hard to handle within a revision control system. As you also noticed, it is very time consuming if you want to modify a lot of them.
By the way: If batchfile.bat was designed/written to be always run from the direcory where it is located, you might also consider to modify batchfile.bat to force that behaviour:
setlocal
cd /D %0\..
REM your original content
endlocal
In %0 the path to the batchfile is stored.
The trick is to assume that %0 is a directory and then to change one level lower based on that directory. With /D also the drive letter is changed correctly.
The cd command doesn't care if %0 is really a directory. In fact %d doesn't even have to exist (%0\dummy\..\.. would also work).
The setlocal command is to have the working directory being restored when batchfile.bat has finished (this would be good if batchfile.bat was called form another batch file).
I noticed that the endlocal command is not really necessary in this context since it is applied implicitly when batchfile.bat finishes.
I am trying to install through batch file..
ECHO OFF
ECHO Installing MySoftware . . .
"%~dp0\MySoftware.exe" /S /v/qn"UPGRADEADD=link goes here"
pause
but it fails to install.
Not much info to go on. What you have will not work if executed from a UNC drive and may not work if you 'Run as administrator' because the current directory gets changed. Try this. Of course that may not fix it and further details would be nice.
#ECHO OFF
PUSHD "%~dp0"
ECHO Installing MySoftware . . .
"MySoftware.exe" /S /v/qn"UPGRADEADD=link goes here"
Adding to my answer based on comments provided.
Presumably your bat file is in the same folder as MySoftware.exe. If it takes that long, it sounds like the install is working. Try doing
"MySoftware.exe" /?
That may give you a help screen to tell you more about the arguments beng passed. Also, try what you are now doing without the /S (which probably specifies a "silent" install... which is why you don't see anything.
PART 1 - If you want to create a "Setup" File in batch.
Maybe it works, but this is will be very hard to you for done this program.
Let's call the EXE File "Game1:
I will recommend you to take all the Game1 file's code (Maybe you can use the program Notepad++ for do this) after you taked Game1's code do this like i writing here
Let's say that the code of Game1 is:
ABC
Copy the code, then go to the batch file.
The "Setup" file of Game1 HAVE to come with a empty EXE file.
You can make a empty EXE file with notepad - just save the file as:
Name.exe
Then you doing at the batch file script this thing:
set %something%=ABC
After you done this you adding this to the batch script:
Echo %something% >> Name.exe
Don't forget to name the EXE file at the name of the program / game.
And now, if this message didn't help to you, maybe you need to make a EXE from batch file.
PART 2 - If you want to make an EXE file of batch file.
Open the start menu of Windows and search this:
IExpress
Don't let the computer search for you the full name, its working only if you wtiting the full name.
After you search IExpress, click on "Activate Command".
Click on Next, Don't change the first options.
Click on "Extract files only" and click on Next.
Name the EXE program and click Next.
Stay on "No prompt." and continue.
Now you can display a program License. if you want do a txt file and choose the display option.
Add batch files and click Next.
click on the option you want and click Next.
If you want a finish message, click on display message and write the message.
Here browse where the EXE will be and choose your options, click Next.
click Next.
Wow that's was super-long! Hope I helped you!
I am completely new to this, but I am trying to create a .bat file that will allow me to rename a pair of files within a designated folder and move them into a subfolder. The part I am having trouble with is that I am wanting a prompt to come up to identify/select the files to be renamed and moved.
Example file names are:
A1234, A1235, A1236, B1234, B1235, B1236, etc.
Is there a way to bring up a prompt that allows the user to type the shared name (ex 1234)of the files and rename and move both files to the designated subfolder?
Any and all help would be appreciated!
Suggested approach
for part of problem
part I am having trouble with is that I am wanting a prompt to come
up to identify/select the files to be renamed and moved. Is there a
way to bring up a prompt that allows the user to type the shared name
(ex 1234)of the files and rename and move both files to the designated
subfolder?
Do a search operation using wildcard, like "?1234" for the case highlighted above ( should be made generalized for all acceptable and expected patterns "*1234*" is the generic most )
Now do a RENAME inside a For loop on the results obtained by search.
As you suggest you are a newbie with Batch, following tutorials will help you build your file. Look for elements like Variables, For Loop
Batch Tutorial
Here you go
#echo off
set /p file=Please type shared name:
for %%a in (C:\Folder\?%file%.*) do (
move "%%a" subdir
ren "subdir\%%a" newname.*
)