I am trying to code for a tic- tac - toe game - c

Question

I am trying to create a function to enter x and o in my board which has counters to 1 - 9 already. Can someone explain me the algorithm and logic so i can try and code accordingly
If someone can guide me through, i am going through different examples but nothing specifically for shorter functions
//function to initialize board and my main and last is the function with printf commands
#include <stdio.h>
#define MAX 3
void InitializeBoard(int m, int n , char board[][n]){
int c =1;
for(int i =0; i<m; i++){
for(int j=0; j< n; j++){
board[i][j] = c+'0';
c++;
}
}
return;
}
void PrintBoard(int m, int n, char board[][n]){
printf("\n %c | %c | %c \n", board[0][0],
board[0][1], board[0][2]);
printf("\n--------------\n");
printf("\n %c | %c | %c \n", board[1][0],
board[1][1], board[1][2]);
printf("\n--------------\n");
printf("\n %c | %c | %c \n\n", board[2][0],
board[2][1], board[2][2]);
return;
}
int main() {
printf("Let's begin the game ! \n " );
char choice;
int m , n ;
char board [MAX][MAX] ;
do {
printf("Press 'p' to print the tic-tac-toe board.\n");
printf("Press 'c' to create the tic-tac-toe board with some X and O celss.\n");
printf("Press 't' to test is the tic-tac-toe board is valid or invalid.\n");
printf("Press 'w' to predict winning cell for the player X and O.\n\n");
printf("Press 'e' to exit\n");
scanf(" %c", &choice);
switch(choice){
case 'p' :
InitializeBoard(m,n,board);
PrintBoard(m,n, board);
break;
case 'c' :
default:
choice =-1;
}
}while(choice!=-1);
return 0;
}
I expect output
1|2|3
-----
4|5|6
-----
7|8|9

Answer 1

The problem is uninitialized variables which you are using to fill the board.
int m , n ;
......
InitializeBoard(m,n,board);
PrintBoard(m,n, board);
You need to initialize them to number of rows and columns.
int m = MAX , n = MAX;