How do I properly utilize fgets() and strncmp() functions? - c

I am trying to secure some C code by utilizing the fgets() and strncmp() functions. The program runs fine, however, if I enter the correct password ("password") more than once it still indicates a correct password. Also, even when using fgets() the results (if longer than the 9 indicated in the buffer) still appear in the output. Any help would be greatly appreciated.
#include <stdio.h>
#include <string.h>
int main(void)
{
char buffer[9];
int pass = 0;
char password[] = "password";
printf("\n Enter your password : \n");
fgets(buffer, 9, stdin);
if(strcmp(buffer, password))
{
printf ("\n Incorrect Password \n");
}
else
{
printf ("\n Correct Password \n");
pass = 1;
}
if(pass)
{
printf ("\n Root privileges authorized \n");
}
return 0;
}

The problem with your code is that fgets is taking the first 8 characters off the input and ignoring the rest. Obviously, if you are inviting a password you don't want to ignore any input! You might want to do something a little more fancy to ensure that you capture the full input.
My first two tries at answering this were wrong. Thanks to wildplasser for holding my feet to the fire.
So, the hack answer is: use a really big buffer. fgets is probably your easier solution there.
Alternatively, you could allocate memory dynamically as your input string exceeds your buffer.
But, just for fun, here is an implementation that breaks us out of the "line buffer" trap that I wasn't aware getchar was in.
For this, I leveraged a very beautiful comment here: getchar() and stdin
PS: Ok, Ok, I tested it this time. It works. On my Mac.
#include <stdio.h>
#include <string.h>
#include <unistd.h>
#include <termios.h>
int main(void)
{
int c, i;
char buffer[9];
struct termios tty_opts_default, tty_opts_raw;
if (!isatty(STDIN_FILENO)) {
printf("Error: stdin is not a TTY\n");
return 1;
}
/* save tty settings for later. */
tcgetattr(STDIN_FILENO, &tty_opts_default);
/* put tty settings into raw mode. */
cfmakeraw(&tty_opts_raw);
tcsetattr(STDIN_FILENO, TCSANOW, &tty_opts_raw);
/* NOW we can grab the input one character at a time. */
c = getchar();
while (i < 8 && c != EOF && c != '\n' && c != '\r') {
/* Since we are collecting a pwd, we might want to enforce other
password logic here, such as no control characters! */
putchar('*');
buffer[i++] = c;
c = getchar();
}
buffer[i] = '\0';
/* Restore default TTY settings */
tcsetattr(STDIN_FILENO, TCSANOW, &tty_opts_default);
/* Report results to user. */
printf("\nPassword received.\n");
printf("(It was '%s' -- don't tell anyone! Quick! Hide the terminal!)\n", buffer);
return 0;
}

fgets()reads the (CR+)LF too, and stores it into the buffer.
But only if there is sufficient place!
Otherwise, your buffer will contain the first n-1 characters, plus a NUL character.
So: allocate a large-enough buffer, and strip the CR/LF:
#include <stdio.h>
#include <string.h>
int main(void)
{
int pass = 0;
char password[] = "password";
char buffer[3+ sizeof password];
printf("\n Enter your password : \n");
fgets(buffer, sizeof buffer, stdin);
buffer[strcspn(buffer,"\r\n")]=0;
if(strcmp(buffer, password))
{
printf ("\n Incorrect Password \n");
}
else
{
printf ("\n Correct Password \n");
pass = 1;
}
if(pass)
{
printf ("\n Root privileges authorized \n");
}
return 0;
}

Related

Why does my Caesar cipher program doesnt return the parts of the output after space? [duplicate]

Using the following code:
char *name = malloc(sizeof(char) + 256);
printf("What is your name? ");
scanf("%s", name);
printf("Hello %s. Nice to meet you.\n", name);
A user can enter their name but when they enter a name with a space like Lucas Aardvark, scanf() just cuts off everything after Lucas. How do I make scanf() allow spaces
People (and especially beginners) should never use scanf("%s") or gets() or any other functions that do not have buffer overflow protection, unless you know for certain that the input will always be of a specific format (and perhaps not even then).
Remember than scanf stands for "scan formatted" and there's precious little less formatted than user-entered data. It's ideal if you have total control of the input data format but generally unsuitable for user input.
Use fgets() (which has buffer overflow protection) to get your input into a string and sscanf() to evaluate it. Since you just want what the user entered without parsing, you don't really need sscanf() in this case anyway:
#include <stdio.h>
#include <stdlib.h>
#include <string.h>
/* Maximum name size + 1. */
#define MAX_NAME_SZ 256
int main(int argC, char *argV[]) {
/* Allocate memory and check if okay. */
char *name = malloc(MAX_NAME_SZ);
if (name == NULL) {
printf("No memory\n");
return 1;
}
/* Ask user for name. */
printf("What is your name? ");
/* Get the name, with size limit. */
fgets(name, MAX_NAME_SZ, stdin);
/* Remove trailing newline, if there. */
if ((strlen(name) > 0) && (name[strlen (name) - 1] == '\n'))
name[strlen (name) - 1] = '\0';
/* Say hello. */
printf("Hello %s. Nice to meet you.\n", name);
/* Free memory and exit. */
free (name);
return 0;
}
Try
char str[11];
scanf("%10[0-9a-zA-Z ]", str);
This example uses an inverted scanset, so scanf keeps taking in values until it encounters a '\n'-- newline, so spaces get saved as well
#include <stdio.h>
int main (int argc, char const *argv[])
{
char name[20];
// get up to buffer size - 1 characters (to account for NULL terminator)
scanf("%19[^\n]", name);
printf("%s\n", name);
return 0;
}
You can use this
char name[20];
scanf("%20[^\n]", name);
Or this
void getText(char *message, char *variable, int size){
printf("\n %s: ", message);
fgets(variable, sizeof(char) * size, stdin);
sscanf(variable, "%[^\n]", variable);
}
char name[20];
getText("Your name", name, 20);
DEMO
Don't use scanf() to read strings without specifying a field width. You should also check the return values for errors:
#include <stdio.h>
#define NAME_MAX 80
#define NAME_MAX_S "80"
int main(void)
{
static char name[NAME_MAX + 1]; // + 1 because of null
if(scanf("%" NAME_MAX_S "[^\n]", name) != 1)
{
fputs("io error or premature end of line\n", stderr);
return 1;
}
printf("Hello %s. Nice to meet you.\n", name);
}
Alternatively, use fgets():
#include <stdio.h>
#define NAME_MAX 80
int main(void)
{
static char name[NAME_MAX + 2]; // + 2 because of newline and null
if(!fgets(name, sizeof(name), stdin))
{
fputs("io error\n", stderr);
return 1;
}
// don't print newline
printf("Hello %.*s. Nice to meet you.\n", strlen(name) - 1, name);
}
getline()
Now part of POSIX, none-the-less.
It also takes care of the buffer allocation problem that you asked about earlier, though you have to take care of freeing the memory.
You can use the fgets() function to read a string or use scanf("%[^\n]s",name); so string reading will terminate upon encountering a newline character.
If someone is still looking, here's what worked for me - to read an arbitrary length of string including spaces.
Thanks to many posters on the web for sharing this simple & elegant solution.
If it works the credit goes to them but any errors are mine.
char *name;
scanf ("%m[^\n]s",&name);
printf ("%s\n",name);
You may use scanf for this purpose with a little trick. Actually, you should allow user input until user hits Enter (\n). This will consider every character, including space. Here is example:
int main()
{
char string[100], c;
int i;
printf("Enter the string: ");
scanf("%s", string);
i = strlen(string); // length of user input till first space
do
{
scanf("%c", &c);
string[i++] = c; // reading characters after first space (including it)
} while (c != '\n'); // until user hits Enter
string[i - 1] = 0; // string terminating
return 0;
}
How this works? When user inputs characters from standard input, they will be stored in string variable until first blank space. After that, rest of entry will remain in input stream, and wait for next scanf. Next, we have a for loop that takes char by char from input stream (till \n) and apends them to end of string variable, thus forming a complete string same as user input from keyboard.
Hope this will help someone!
While you really shouldn't use scanf() for this sort of thing, because there are much better calls such as gets() or getline(), it can be done:
#include <stdio.h>
char* scan_line(char* buffer, int buffer_size);
char* scan_line(char* buffer, int buffer_size) {
char* p = buffer;
int count = 0;
do {
char c;
scanf("%c", &c); // scan a single character
// break on end of line, string terminating NUL, or end of file
if (c == '\r' || c == '\n' || c == 0 || c == EOF) {
*p = 0;
break;
}
*p++ = c; // add the valid character into the buffer
} while (count < buffer_size - 1); // don't overrun the buffer
// ensure the string is null terminated
buffer[buffer_size - 1] = 0;
return buffer;
}
#define MAX_SCAN_LENGTH 1024
int main()
{
char s[MAX_SCAN_LENGTH];
printf("Enter a string: ");
scan_line(s, MAX_SCAN_LENGTH);
printf("got: \"%s\"\n\n", s);
return 0;
}
/*reading string which contains spaces*/
#include<stdio.h>
int main()
{
char *c,*p;
scanf("%[^\n]s",c);
p=c; /*since after reading then pointer points to another
location iam using a second pointer to store the base
address*/
printf("%s",p);
return 0;
}

How can I get full name in a single scanf/gets in C language? [duplicate]

Using the following code:
char *name = malloc(sizeof(char) + 256);
printf("What is your name? ");
scanf("%s", name);
printf("Hello %s. Nice to meet you.\n", name);
A user can enter their name but when they enter a name with a space like Lucas Aardvark, scanf() just cuts off everything after Lucas. How do I make scanf() allow spaces
People (and especially beginners) should never use scanf("%s") or gets() or any other functions that do not have buffer overflow protection, unless you know for certain that the input will always be of a specific format (and perhaps not even then).
Remember than scanf stands for "scan formatted" and there's precious little less formatted than user-entered data. It's ideal if you have total control of the input data format but generally unsuitable for user input.
Use fgets() (which has buffer overflow protection) to get your input into a string and sscanf() to evaluate it. Since you just want what the user entered without parsing, you don't really need sscanf() in this case anyway:
#include <stdio.h>
#include <stdlib.h>
#include <string.h>
/* Maximum name size + 1. */
#define MAX_NAME_SZ 256
int main(int argC, char *argV[]) {
/* Allocate memory and check if okay. */
char *name = malloc(MAX_NAME_SZ);
if (name == NULL) {
printf("No memory\n");
return 1;
}
/* Ask user for name. */
printf("What is your name? ");
/* Get the name, with size limit. */
fgets(name, MAX_NAME_SZ, stdin);
/* Remove trailing newline, if there. */
if ((strlen(name) > 0) && (name[strlen (name) - 1] == '\n'))
name[strlen (name) - 1] = '\0';
/* Say hello. */
printf("Hello %s. Nice to meet you.\n", name);
/* Free memory and exit. */
free (name);
return 0;
}
Try
char str[11];
scanf("%10[0-9a-zA-Z ]", str);
This example uses an inverted scanset, so scanf keeps taking in values until it encounters a '\n'-- newline, so spaces get saved as well
#include <stdio.h>
int main (int argc, char const *argv[])
{
char name[20];
// get up to buffer size - 1 characters (to account for NULL terminator)
scanf("%19[^\n]", name);
printf("%s\n", name);
return 0;
}
You can use this
char name[20];
scanf("%20[^\n]", name);
Or this
void getText(char *message, char *variable, int size){
printf("\n %s: ", message);
fgets(variable, sizeof(char) * size, stdin);
sscanf(variable, "%[^\n]", variable);
}
char name[20];
getText("Your name", name, 20);
DEMO
Don't use scanf() to read strings without specifying a field width. You should also check the return values for errors:
#include <stdio.h>
#define NAME_MAX 80
#define NAME_MAX_S "80"
int main(void)
{
static char name[NAME_MAX + 1]; // + 1 because of null
if(scanf("%" NAME_MAX_S "[^\n]", name) != 1)
{
fputs("io error or premature end of line\n", stderr);
return 1;
}
printf("Hello %s. Nice to meet you.\n", name);
}
Alternatively, use fgets():
#include <stdio.h>
#define NAME_MAX 80
int main(void)
{
static char name[NAME_MAX + 2]; // + 2 because of newline and null
if(!fgets(name, sizeof(name), stdin))
{
fputs("io error\n", stderr);
return 1;
}
// don't print newline
printf("Hello %.*s. Nice to meet you.\n", strlen(name) - 1, name);
}
getline()
Now part of POSIX, none-the-less.
It also takes care of the buffer allocation problem that you asked about earlier, though you have to take care of freeing the memory.
You can use the fgets() function to read a string or use scanf("%[^\n]s",name); so string reading will terminate upon encountering a newline character.
If someone is still looking, here's what worked for me - to read an arbitrary length of string including spaces.
Thanks to many posters on the web for sharing this simple & elegant solution.
If it works the credit goes to them but any errors are mine.
char *name;
scanf ("%m[^\n]s",&name);
printf ("%s\n",name);
You may use scanf for this purpose with a little trick. Actually, you should allow user input until user hits Enter (\n). This will consider every character, including space. Here is example:
int main()
{
char string[100], c;
int i;
printf("Enter the string: ");
scanf("%s", string);
i = strlen(string); // length of user input till first space
do
{
scanf("%c", &c);
string[i++] = c; // reading characters after first space (including it)
} while (c != '\n'); // until user hits Enter
string[i - 1] = 0; // string terminating
return 0;
}
How this works? When user inputs characters from standard input, they will be stored in string variable until first blank space. After that, rest of entry will remain in input stream, and wait for next scanf. Next, we have a for loop that takes char by char from input stream (till \n) and apends them to end of string variable, thus forming a complete string same as user input from keyboard.
Hope this will help someone!
While you really shouldn't use scanf() for this sort of thing, because there are much better calls such as gets() or getline(), it can be done:
#include <stdio.h>
char* scan_line(char* buffer, int buffer_size);
char* scan_line(char* buffer, int buffer_size) {
char* p = buffer;
int count = 0;
do {
char c;
scanf("%c", &c); // scan a single character
// break on end of line, string terminating NUL, or end of file
if (c == '\r' || c == '\n' || c == 0 || c == EOF) {
*p = 0;
break;
}
*p++ = c; // add the valid character into the buffer
} while (count < buffer_size - 1); // don't overrun the buffer
// ensure the string is null terminated
buffer[buffer_size - 1] = 0;
return buffer;
}
#define MAX_SCAN_LENGTH 1024
int main()
{
char s[MAX_SCAN_LENGTH];
printf("Enter a string: ");
scan_line(s, MAX_SCAN_LENGTH);
printf("got: \"%s\"\n\n", s);
return 0;
}
/*reading string which contains spaces*/
#include<stdio.h>
int main()
{
char *c,*p;
scanf("%[^\n]s",c);
p=c; /*since after reading then pointer points to another
location iam using a second pointer to store the base
address*/
printf("%s",p);
return 0;
}

C - scanf doesn't handle space as I expected [duplicate]

Using the following code:
char *name = malloc(sizeof(char) + 256);
printf("What is your name? ");
scanf("%s", name);
printf("Hello %s. Nice to meet you.\n", name);
A user can enter their name but when they enter a name with a space like Lucas Aardvark, scanf() just cuts off everything after Lucas. How do I make scanf() allow spaces
People (and especially beginners) should never use scanf("%s") or gets() or any other functions that do not have buffer overflow protection, unless you know for certain that the input will always be of a specific format (and perhaps not even then).
Remember than scanf stands for "scan formatted" and there's precious little less formatted than user-entered data. It's ideal if you have total control of the input data format but generally unsuitable for user input.
Use fgets() (which has buffer overflow protection) to get your input into a string and sscanf() to evaluate it. Since you just want what the user entered without parsing, you don't really need sscanf() in this case anyway:
#include <stdio.h>
#include <stdlib.h>
#include <string.h>
/* Maximum name size + 1. */
#define MAX_NAME_SZ 256
int main(int argC, char *argV[]) {
/* Allocate memory and check if okay. */
char *name = malloc(MAX_NAME_SZ);
if (name == NULL) {
printf("No memory\n");
return 1;
}
/* Ask user for name. */
printf("What is your name? ");
/* Get the name, with size limit. */
fgets(name, MAX_NAME_SZ, stdin);
/* Remove trailing newline, if there. */
if ((strlen(name) > 0) && (name[strlen (name) - 1] == '\n'))
name[strlen (name) - 1] = '\0';
/* Say hello. */
printf("Hello %s. Nice to meet you.\n", name);
/* Free memory and exit. */
free (name);
return 0;
}
Try
char str[11];
scanf("%10[0-9a-zA-Z ]", str);
This example uses an inverted scanset, so scanf keeps taking in values until it encounters a '\n'-- newline, so spaces get saved as well
#include <stdio.h>
int main (int argc, char const *argv[])
{
char name[20];
// get up to buffer size - 1 characters (to account for NULL terminator)
scanf("%19[^\n]", name);
printf("%s\n", name);
return 0;
}
You can use this
char name[20];
scanf("%20[^\n]", name);
Or this
void getText(char *message, char *variable, int size){
printf("\n %s: ", message);
fgets(variable, sizeof(char) * size, stdin);
sscanf(variable, "%[^\n]", variable);
}
char name[20];
getText("Your name", name, 20);
DEMO
Don't use scanf() to read strings without specifying a field width. You should also check the return values for errors:
#include <stdio.h>
#define NAME_MAX 80
#define NAME_MAX_S "80"
int main(void)
{
static char name[NAME_MAX + 1]; // + 1 because of null
if(scanf("%" NAME_MAX_S "[^\n]", name) != 1)
{
fputs("io error or premature end of line\n", stderr);
return 1;
}
printf("Hello %s. Nice to meet you.\n", name);
}
Alternatively, use fgets():
#include <stdio.h>
#define NAME_MAX 80
int main(void)
{
static char name[NAME_MAX + 2]; // + 2 because of newline and null
if(!fgets(name, sizeof(name), stdin))
{
fputs("io error\n", stderr);
return 1;
}
// don't print newline
printf("Hello %.*s. Nice to meet you.\n", strlen(name) - 1, name);
}
getline()
Now part of POSIX, none-the-less.
It also takes care of the buffer allocation problem that you asked about earlier, though you have to take care of freeing the memory.
You can use the fgets() function to read a string or use scanf("%[^\n]s",name); so string reading will terminate upon encountering a newline character.
If someone is still looking, here's what worked for me - to read an arbitrary length of string including spaces.
Thanks to many posters on the web for sharing this simple & elegant solution.
If it works the credit goes to them but any errors are mine.
char *name;
scanf ("%m[^\n]s",&name);
printf ("%s\n",name);
You may use scanf for this purpose with a little trick. Actually, you should allow user input until user hits Enter (\n). This will consider every character, including space. Here is example:
int main()
{
char string[100], c;
int i;
printf("Enter the string: ");
scanf("%s", string);
i = strlen(string); // length of user input till first space
do
{
scanf("%c", &c);
string[i++] = c; // reading characters after first space (including it)
} while (c != '\n'); // until user hits Enter
string[i - 1] = 0; // string terminating
return 0;
}
How this works? When user inputs characters from standard input, they will be stored in string variable until first blank space. After that, rest of entry will remain in input stream, and wait for next scanf. Next, we have a for loop that takes char by char from input stream (till \n) and apends them to end of string variable, thus forming a complete string same as user input from keyboard.
Hope this will help someone!
While you really shouldn't use scanf() for this sort of thing, because there are much better calls such as gets() or getline(), it can be done:
#include <stdio.h>
char* scan_line(char* buffer, int buffer_size);
char* scan_line(char* buffer, int buffer_size) {
char* p = buffer;
int count = 0;
do {
char c;
scanf("%c", &c); // scan a single character
// break on end of line, string terminating NUL, or end of file
if (c == '\r' || c == '\n' || c == 0 || c == EOF) {
*p = 0;
break;
}
*p++ = c; // add the valid character into the buffer
} while (count < buffer_size - 1); // don't overrun the buffer
// ensure the string is null terminated
buffer[buffer_size - 1] = 0;
return buffer;
}
#define MAX_SCAN_LENGTH 1024
int main()
{
char s[MAX_SCAN_LENGTH];
printf("Enter a string: ");
scan_line(s, MAX_SCAN_LENGTH);
printf("got: \"%s\"\n\n", s);
return 0;
}
/*reading string which contains spaces*/
#include<stdio.h>
int main()
{
char *c,*p;
scanf("%[^\n]s",c);
p=c; /*since after reading then pointer points to another
location iam using a second pointer to store the base
address*/
printf("%s",p);
return 0;
}

C - Is there a way to terminate string input with a key other than 'Enter'?

I'm working on an assignment scheduler for my school, the code below is a segment of a module for inputting data for a new assignment and subsequently writing that data to file. Since the assignment description may be a lengthy paragraph, I decided to allow the user to move to a new line upon pressing the Enter key for ease of input. The code I have so far works as desired.
The description is a single string however which is usually terminated with the enter key. Is it possible to terminate the string with another key? For example the Escape Key? If so, how do I go about doing this?
I was thinking of using the escape 'Esc' key to terminate string entry but I'm not sure which code or escape sequence with which to represent the key.
typedef struct {
char title[60];
Time duration;
Date deadline;
char descrptn[10000];
} Project;
void setStudioProject() {
Project newProj;
FILE *fpProj;
system("cls");
printf("-----PROJECT SETUP-----\n\n\n");
//Prompt for project information
printf("Title: ");
fgets(newProj.title, 60, stdin);
fflush(stdin);
printf("\n\nDescription: \n");
printf("(No more than 1000 words)\n");
//loop of concern
while (fgets(newProj.descrptn, 10000, stdin)) {
if (getchar() == '\r') { //Whenever the user presses the enter key
printf("\n"); //...move to a new line
}
}
fflush(stdin);
//...
}
I expect the string to be read upon pressing the escape key so that execution can continue.
Input is line-buffered by default. You can use ncurses (which doesn't do this) or manually disable:
#include <stdio.h>
#include <unistd.h>
#include <termios.h>
...
//ensure stdin is a terminal before modifying
if (isatty(STDIN_FILENO)) {
struct termios t;
tcgetattr(STDOUT_FILENO, &t);//get current params
int linebufd = ((t.c_lflag & ICANON) > 0);//check if line-buffered
if (linebufd) {
t.c_lflag ^= ICANON;//disable canonical line-buffering
tcsetattr(STDOUT_FILENO, TCSANOW, &t);//update attributes and enable immediate feedback
}
}
setvbuf(stdin, NULL, _IONBF, 1);//make stdin stream unbuffered
Read more about:
Terminal Modes
Stream Buffering
In comment, I suggested to the questioner that his problem could possibly be better resolved by using a double newline (blank line) to indicate end-of-input instead of ESC.
He has asked for an implementation, so here's an implementation of that. The fgets_until_blankline function will read multiple lines, returning when Enter is pressed twice.
#include <stdio.h>
#include <string.h>
char *fgets_until_blankline(char *var, int varsize, FILE *file) {
int inlen = 0;
char *rc;
var[0] = 0;
while(rc = fgets(var+inlen, varsize-inlen, file)) {
if(var[inlen] == '\n') {
var[inlen] = 0;
break;
}
inlen = strlen(var);
}
return rc;
}
int main() {
char var[10000];
fgets_until_blankline(var, sizeof(var), stdin);
printf("%s", var);
}

Winsock programming send function via space char [duplicate]

Using the following code:
char *name = malloc(sizeof(char) + 256);
printf("What is your name? ");
scanf("%s", name);
printf("Hello %s. Nice to meet you.\n", name);
A user can enter their name but when they enter a name with a space like Lucas Aardvark, scanf() just cuts off everything after Lucas. How do I make scanf() allow spaces
People (and especially beginners) should never use scanf("%s") or gets() or any other functions that do not have buffer overflow protection, unless you know for certain that the input will always be of a specific format (and perhaps not even then).
Remember than scanf stands for "scan formatted" and there's precious little less formatted than user-entered data. It's ideal if you have total control of the input data format but generally unsuitable for user input.
Use fgets() (which has buffer overflow protection) to get your input into a string and sscanf() to evaluate it. Since you just want what the user entered without parsing, you don't really need sscanf() in this case anyway:
#include <stdio.h>
#include <stdlib.h>
#include <string.h>
/* Maximum name size + 1. */
#define MAX_NAME_SZ 256
int main(int argC, char *argV[]) {
/* Allocate memory and check if okay. */
char *name = malloc(MAX_NAME_SZ);
if (name == NULL) {
printf("No memory\n");
return 1;
}
/* Ask user for name. */
printf("What is your name? ");
/* Get the name, with size limit. */
fgets(name, MAX_NAME_SZ, stdin);
/* Remove trailing newline, if there. */
if ((strlen(name) > 0) && (name[strlen (name) - 1] == '\n'))
name[strlen (name) - 1] = '\0';
/* Say hello. */
printf("Hello %s. Nice to meet you.\n", name);
/* Free memory and exit. */
free (name);
return 0;
}
Try
char str[11];
scanf("%10[0-9a-zA-Z ]", str);
This example uses an inverted scanset, so scanf keeps taking in values until it encounters a '\n'-- newline, so spaces get saved as well
#include <stdio.h>
int main (int argc, char const *argv[])
{
char name[20];
// get up to buffer size - 1 characters (to account for NULL terminator)
scanf("%19[^\n]", name);
printf("%s\n", name);
return 0;
}
You can use this
char name[20];
scanf("%20[^\n]", name);
Or this
void getText(char *message, char *variable, int size){
printf("\n %s: ", message);
fgets(variable, sizeof(char) * size, stdin);
sscanf(variable, "%[^\n]", variable);
}
char name[20];
getText("Your name", name, 20);
DEMO
Don't use scanf() to read strings without specifying a field width. You should also check the return values for errors:
#include <stdio.h>
#define NAME_MAX 80
#define NAME_MAX_S "80"
int main(void)
{
static char name[NAME_MAX + 1]; // + 1 because of null
if(scanf("%" NAME_MAX_S "[^\n]", name) != 1)
{
fputs("io error or premature end of line\n", stderr);
return 1;
}
printf("Hello %s. Nice to meet you.\n", name);
}
Alternatively, use fgets():
#include <stdio.h>
#define NAME_MAX 80
int main(void)
{
static char name[NAME_MAX + 2]; // + 2 because of newline and null
if(!fgets(name, sizeof(name), stdin))
{
fputs("io error\n", stderr);
return 1;
}
// don't print newline
printf("Hello %.*s. Nice to meet you.\n", strlen(name) - 1, name);
}
getline()
Now part of POSIX, none-the-less.
It also takes care of the buffer allocation problem that you asked about earlier, though you have to take care of freeing the memory.
You can use the fgets() function to read a string or use scanf("%[^\n]s",name); so string reading will terminate upon encountering a newline character.
If someone is still looking, here's what worked for me - to read an arbitrary length of string including spaces.
Thanks to many posters on the web for sharing this simple & elegant solution.
If it works the credit goes to them but any errors are mine.
char *name;
scanf ("%m[^\n]s",&name);
printf ("%s\n",name);
You may use scanf for this purpose with a little trick. Actually, you should allow user input until user hits Enter (\n). This will consider every character, including space. Here is example:
int main()
{
char string[100], c;
int i;
printf("Enter the string: ");
scanf("%s", string);
i = strlen(string); // length of user input till first space
do
{
scanf("%c", &c);
string[i++] = c; // reading characters after first space (including it)
} while (c != '\n'); // until user hits Enter
string[i - 1] = 0; // string terminating
return 0;
}
How this works? When user inputs characters from standard input, they will be stored in string variable until first blank space. After that, rest of entry will remain in input stream, and wait for next scanf. Next, we have a for loop that takes char by char from input stream (till \n) and apends them to end of string variable, thus forming a complete string same as user input from keyboard.
Hope this will help someone!
While you really shouldn't use scanf() for this sort of thing, because there are much better calls such as gets() or getline(), it can be done:
#include <stdio.h>
char* scan_line(char* buffer, int buffer_size);
char* scan_line(char* buffer, int buffer_size) {
char* p = buffer;
int count = 0;
do {
char c;
scanf("%c", &c); // scan a single character
// break on end of line, string terminating NUL, or end of file
if (c == '\r' || c == '\n' || c == 0 || c == EOF) {
*p = 0;
break;
}
*p++ = c; // add the valid character into the buffer
} while (count < buffer_size - 1); // don't overrun the buffer
// ensure the string is null terminated
buffer[buffer_size - 1] = 0;
return buffer;
}
#define MAX_SCAN_LENGTH 1024
int main()
{
char s[MAX_SCAN_LENGTH];
printf("Enter a string: ");
scan_line(s, MAX_SCAN_LENGTH);
printf("got: \"%s\"\n\n", s);
return 0;
}
/*reading string which contains spaces*/
#include<stdio.h>
int main()
{
char *c,*p;
scanf("%[^\n]s",c);
p=c; /*since after reading then pointer points to another
location iam using a second pointer to store the base
address*/
printf("%s",p);
return 0;
}

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