Freeing the temp node when adding to a linkedlist - c

I have a function called addMod that, when called, adds a node to a certain index of an array of Module struct LinkedLists called modules contained within a System struct. A Module struct has a string field, two int fields, and a pointer to the next Module, the first three fields being initialized according to arguments provided in addMod. addMod roughly looks like this:
int addMod(System *system, const char *text, int num1, int num2, int index) {
Module *temp = malloc(sizeof(Module));
Module *current;
temp->next = NULL;
if ([any of the constructors are invalid]) return 0;
temp->text = malloc(strlen(text)+1);
strcpy(temp->text, text);
temp->num1 = num1; temp->num2 = num2;
if (!system->modules[index]) {
system->modules[index] = temp; //If there are no modules in the LinkedList at the given index, makes the head = temp.
}
else {
if (system->compare(temp, system->modules[index]) <= 0) { //compare is a func pointer field of system that compares two Modules to see in what order they should be. Here, we check if temp should become the head of modules[index].
temp->next = system->modules[index]; //Assigns the current head as the module following temp.
system->modules[index] = temp; //Makes temp the current head.
}
else {
current = system->modules[index];
while (current->next && system->compare(temp, current->next) > 0) { //While current isn't the last node in the LinkedList and temp comes after the node after current
current = current->next;
}
temp->next = current->next; //Adds temp in between current and current->next.
current->next = temp;
}
}
return 1;
}
All of the above works as expected, except when printing the contents of system, the console indicates there's a memory leak that I'm assuming is because I fail to properly free temp based on what valgrind tells me. My problem is not knowing where to free it- it seems anywhere I put it causes a segfault after printing the contents. From my understanding, I have to make sure that no other variables are depending upon the value being held by temp, but I can't seem to find a way to do that considering every possible ending of my if statement leads to assigning temp to a node within modules. Putting free(temp) between the logic and return 1 also yields a segfault, I'm assuming because I often malloc temp again when calling addMod multiple times in succession.
In summary, to add a new node to a LinkedList that may or may not be populated, in which this new node may be inserted in any arbitrary position in the LinkedList, I have to allocate memory to a temporary node so that I can insert it later. Where do I free this allocated memory once I have successfully inserted the node?

Assuming your management of a System instance is sound (a big assumption, since I cannot see that code), you have giant hole in the memory allocation of temp with a subsequent hard return 0 in the condition where the "constructor" check fails. More to the point:
Module *temp = malloc(sizeof(Module)); // memory allocated here...
Module *current;
temp->next = NULL;
if ([any of the constructors are invalid])
return 0; // and leaked here.
It may be as simple as swapping the check around. Obviously other code that is supposed to free the dynamic allocations should be considered and evaluated as well.
A Simpler Approach
The node addition code is complicated and it need not be. In the end all you should really care about is finding the place where your new node resides.
If the slot in the table is empty, its the first node in that list.
IF the slot in the table is NOT empty, find the sorted location and insert it there.
Both of those can be accomplished with a single while-loop by using a pointer-to-pointer, where said entity hold the address of the pointer that will hold the new node in either of the cases above, and as a bonus, surgical insertion is literally two assignments.
It's done like this. Note that most of this code is just making the Module object safely. The actual insertion is only a single while-loop and some pointer assignments. It assumes the table in System initially contains NULL entries:
int addMod(System *system, const char *text, int num1, int num2, int index)
{
// allocate new node here
Module *temp = malloc(sizeof *temp);
if (temp == NULL)
{
perror("Failed to allocate new Module");
return 0;
}
size_t len = strlen(text);
temp->text = malloc(len + 1);
if (temp->text == NULL)
{
perror("Failed to allocate module name");
free(temp);
return 0;
}
// finish copying member data
memcpy(temp->text, text, len);
temp->text[len] = 0;
temp->num1 = num1;
temp->num2 = num2;
// now find where it belongs, and set next appropriately
Module **pp = system->modules + index;
while (*pp && system->compare(temp, *pp) <= 0)
pp = &(*pp)->next;
temp->next = *pp;
*pp = temp;
return 1;
}
Understand this is from deriving what I think your System type looks like, as it was never presented:
typedef struct System
{
Module *modules[MAX_MODULES];
int (*compare)(const Module* lhs, const Module *rhs);
} System;
I'm fairly confident it is similar to this. Of course, you'll have to adapt if it isn't. I suggest you review this and step through it in a debugger. There is no substitute for watching it live.
Best of luck.

Related

linked list traversal goes infinitely

I'm trying to implement my own version of malloc() function in c.
I decided to keep track of my allocated blocks using a linked list of meta-data objects that would store some information about the allocated chunk and and place it right before the chunk.
Now long story short while debugging I came across the fact that my linked list is behaving very strangely.
here's a piece of the code to help understanding the problem.
typedef struct meta_data
{
size_t size;
int free;
struct meta_data* next;
}meta_data;
meta_data* global_base;
void *mymalloc(size_t size)
{
if(size > 0)
{
meta_data block_meta;
void* pointer = sbrk(size + block_size);
block_meta.size = size;
block_meta.next = NULL;
block_meta.free = 0;
if(!global_base) //first allocation
{
global_base = &block_meta;
}
else
{
block_meta.next = global_base;
}
return pointer;
}
else
{
return NULL;
}
}
I wrote this code which I assume will append a new item to the tail of my global_base (linked list) every time I call mymalloc(<some_size>);
however when I tried to debug and make sure that my linked list is in order by calling mymalloc() couple of times and check is my linked list is being populated properly
void printList()
{
meta_data * node = global_base;
while (node->next != NULL)
{
printf("%zu", node->size);
printf(" -> ");
node = node->next;
}
printf(" \n ");
}
int main()
{
mymalloc(10);
mymalloc(8);
mymalloc(4);
printList();
return 0;
}
I expected my output to be
10 -> 8 -> 4 however it was 4 -> 4 -> 4 -> 4 -> 4 ..... and goes into an infinite loop
any idea where am I going wrong with this code.
I'm a little new to programming with C so my only guess is that I'm making use of reference & and pointer * improperly.
furthermore I have seen tones of code where the assignment of struct's attribute is happening with the use of -> but I could only use . to make it (could this be the problem anyhow)?
help is appreciated thanks guys
There are multiple problems with your approach:
the meta_data block_meta; is a local variable. You cannot use that to link the blocks. Local variables are reclaimed when the function exits. You should use global memory retrieved from the system with sbrk, pointed to by pointer.
the print loop is incorrect: you should write while (node != NULL) to print all blocks.
Your code has dozens of issues which I will address.
Now the problem with your code, in fact the biggest issue with it is that the myalloc function doesn't create a new block_meta node. It just declares a block_meta variable (which will end up on the stack and even worse is a recipe for disastrous bugs I believe the infinite loop is a result of this). You should you use the sbrk function to create a meta_data node before doing anything like so:
...
meta_data *block_meta = sbrk(sizeof(meta_data));
block_meta->size = size;
block_meta->next = NULL;
block_meta->free = 0;
if(!global_base)
{
global_base = block_meta;
}
The myalloc function checks to see if global_base has been assigned, that is if there is a root node in the linked list. If there is one it should simply tell the current variable to link itself to the global_base that is point it's next variable at global_base, this is a big error. Firstly, the global_base is the root node and it makes no sense to tell the current node to link itself to the root of the linked list, it's supposed to link itself to the next node not the root. Secondly, the reference to the previous node is lost which means it's not a linked list anymore. A proper solution would be saving the current node in a variable using a static variable which prevents it from getting lost when the myalloc function exits:
...
static meta_data *curr;
then right before returning the pointer to the newly allocated block you add this line to hold the node that had been newly created:
...
curr = block_meta;
return pointer;
now return to the erring else statement and change that to to ensure that the previous node points to the current node:
...
else
{
curr->next = block_meta;
}

C LinkedList storing the last value only

I am having problem storing all the values into the Generic LinkedList, my linkedlist works totally works on a normal user Keyboard input but when I try to store values(strings) from a file, there is something weird happening, it only store the last value of the file.
I have checked my addToList() function but theres nothing wrong with it.
P.s But I am feeling its either I am printing wrong or my reading from the file into the linkedlist is wrong.
Thank you.
#include<stdio.h>
#include <stdlib.h>
#include<string.h>
#include "LinkedListItems.h"
#define MAX 10000
int main()
{
printf("Testing MissileFIle.txt");
void* secondStr;
//Had to malloc the thing
secondStr = (void*)malloc(1*sizeof(char));
FILE* missileFile;
missileFile = fopen("missiles.txt", "r");
if(missileFile == NULL)
{
printf("The file is empty");
}
number_list_t* missileList = calloc(1, sizeof(number_list_t));
void* input;
//Have to allocate the input
input = malloc(1*sizeof(void*));
//this is to read the data into the second Str
while(fgets(secondStr,MAX,missileFile) != NULL)
{
//Let just print out first just to test my memory
printf("%s\n",secondStr);
//Right now its only reading one string so far which is really weird AFFFFF
addTolist(missileList,secondStr);
}
//Gotta declare another list just to print out the list
number_node_t* current = missileList->head;
while(current != NULL)
{
//There is something wrong with this line
printf("%s\n",current-> number);
current = current-> next;
}
fclose(missileFile);
}
OUTPUT:
Testing MissileFile.txt
splash
single
V-line
h-line
Single
Single
Single
Single
Single
Single
typedef struct NumberNode
{
//It can store any data type
void* number;
struct NumberNode* next;
}number_node_t;
//List of Nodes
typedef struct NumberList
{
number_node_t* head;
int count; //This is not nesssary but it can be useful for counting how many variables
}number_list_t;
void addTolist(number_list_t* list, void* newNumber)
{
//tem[ = newNode]
number_node_t* newNode = calloc(1,sizeof(number_node_t));
newNode->number = newNumber;
newNode->next = list->head;
list->head = newNode;
}
INPUT DATA:
single
splash
single
V-Line
h-line
Single
The way you have implemented this, it cannot work.
The main problem, among many, is related to the void* pointers which cannot be dereferenced.
The size of elements should be given, either on creating the list in which case all elements are of the same type, or separately for each individual element. You can check out this question for an example of something that could work.
As far as the buffer thing is concerned, addToList should allocate new memory for each newNumber. What you are currently doing results in all data of the list pointing to a specific space in memory (the one allocated to secondStr). Each time you change the content of that memory space, all elements in the list are affected. This is why you print the same value for all elements and more specifically the last value in your file.
The way you allocate memory is also not really ok, same goes for the way you open your file, there is memory leaking etc. I am not going into details.
At least this issue:
Copy the string
OP's goal includes the need to copy the string from the read buffer to the list, not just copy the buffer pointer.
// void addTolist(number_list_t* list, void* newNumber) {
void addStringTolist(number_list_t* list, const char *s) {
// number_node_t* newNode = calloc(1,sizeof(number_node_t));
number_node_t* newNode = calloc(1, sizeof *newNode); // todo: add error check
size_t sz = strlen(s) + 1;
newNode->number = malloc(sz); // todo: add error check
strpy(newNode->number, s);
newNode->next = list->head;
list->head = newNode;
}
Note: When freeing the list, newNode->number also needs to be free'd.
regarding:
while(fgets(secondStr,MAX,missileFile) != NULL)
MAX is defined as 10000 but secondStr is defined as pointer to one byte. so when this is executed, a buffer overflow occurs.
This is undefined behavior and probably the root of the problem with reading from a file

How can a Linked List be implemented using only pointers (w/o structures)?

I'm trying to create a linked list without using structures in C.
I want to be able to store an int variable on every node and a pointer to the next node, add unlimited numbers to the list, remove the first item, print all of the elements, etc.
I was thinking that every node of type int** should have 2 pointers of type int*.
the first one will point to an int address and the second will point to NULL.
Then, if I like to add a number to the list, I'll use the last pointer to point to a new allocated node of type int** and so on.
I'm having trouble writing the proper code for this though, and can't seem to reach to the actual int values. See the image below:
You can achieve this by allocating two uintptr_t each time: the first allocated memory space will be responsible for storing the value of the integer and the second one will be pointing to the next memory location.
uintptr_t nodeFirst = malloc(2 * sizeof(uintptr_t));
...
...
uintptr_t nodeNext = malloc(2 * sizeof(uintptr_t));
....
....
*nodeFirst = someIntValue;
*(nodeFirst + 1) = nodeNext;
...
The fact is, my solution above is still using the struct analogy, but w/o the struct keyword.
Here is a complete solution of a LinkedList managed as int ** pointers.
Step 1 - the addNode() function to add one node to the int **head.
int **addNode(int **head, int ival)
{
int **node = malloc(2 * sizeof(int *));
// don't forget to alloc memory to store the int value
node[0] = malloc(sizeof(int));
*(node[0]) = ival;
// next is pointing to NULL
node[1] = NULL;
if (head == NULL) {
// first node to be added
head = node;
}
else {
int **temp;
temp = head;
// temp[1] is the next
while (temp[1]!=NULL) {
// cast needed to go to the next node
temp = (int **)temp[1];
}
// cast needed to store the next node
temp[1] = (int *)node;
}
return (head);
}
Step 2 - a function display() to explore the current linkedlist.
void display(int **head)
{
int **temp;
int i = 0;
temp = head;
printf("display:\n");
while (temp!=NULL) {
// temp[0] is pointing to the ivalue
printf("node[%d]=%d\n",i++,*(temp[0]));
temp = (int **)temp[1];
}
printf("\n");
}
Step 3 - the popNode() function to remove the first node.
int **popNode(int **head)
{
int **temp;
if (head!=NULL) {
temp = (int **)head[1];
// don't forget to free ivalue
free(head[0]);
// then free the next pointer
free(head[1]);
head = temp;
}
return (head);
}
Step 4 - then an example of main() function using the linkedlist.
int main()
{
int **head = NULL;
head = addNode(head,111);
head = addNode(head,222);
head = addNode(head,333);
display(head);
// display:
// node[0]=111
// node[1]=222
// node[2]=333
head = popNode(head);
display(head);
// display:
// node[0]=222
// node[1]=333
while ((head = popNode(head))!=NULL);
display(head);
// display:
return (0);
}
Allocate two arrays, both of which are stored as pointers. In C, they can be the pointers you get back from calloc(). The first holds your node data. We can call it nodes. The second is an array of pointers (or integral offsets). We can call it nexts. Whenever you update the list, update nodes so that each nexts[i] links to the next node after the one that contains nodes[i], or an invalid value such as NULL or -1 if it is the tail. For a double-linked list, you’d need befores or to use the XOR trick. You’ll need a head pointer and some kind of indicator of which elements in your pool are unallocated, which could be something simple like a first free index, or something more complicated like a bitfield.
You would still need to wrap all this in a structure to get more than one linked list in your program, but that does give you one linked list using no data structure other than pointers.
This challenge is crazy, but a structure of arrays isn’t, and you might see a graph or a list of vertices stored in a somewhat similar way. You can allocate or deallocate your node pool all at once instead of in small chunks, it could be more efficient to use 32-bit offsets instead of 64-bit next pointers, and contiguous storage gets you locality of reference.

Binary Search Tree node insertion not working properly

I have a homework assignment to implement a binary search tree (create, delete, search). I used the example provided by the teacher but I can't make it work.
Here's my code so far:
void insert_node(int k){
struct node *nodnou,*flow,*parent;
nodnou = (struct node*)malloc(sizeof(node));
nodnou->st = NULL;
nodnou->dr = NULL;
nodnou->nr = k;
if (root==NULL)
{
root = (struct node*)malloc(sizeof(node));
root = nodnou;
}
else
{
flow = (struct node*)malloc(sizeof(node));
parent = (struct node*)malloc(sizeof(node));
flow = root;
parent = root;
while (((flow->st!=NULL) || (flow->dr!=NULL)) && flow!=NULL)
{
if (k<flow->nr)
{
parent = flow;
flow = flow->st;
}
else
{
parent = flow;
flow = flow->dr;
}
}
if (k<flow->nr)
{
parent->st = nodnou;
}
else
{
parent->dr = nodnou;
}
}
}
The way of thinking: This function gets the value of the node we want to insert as the k parameter. The function will only insert the root of the tree (root is global variable).
I think my biggest problem is the while loop that sweeps through the tree to find the spot for the new node.
If I use while (flow!=NULL) it won't work because the flow pointer gets an assignment to something that does not exist. Please help me understand where I am wrong (homework).
Your code has several important flaws, not the least of which is a misunderstanding of how dynamic memory allocation works in C. Never follow a pattern like this:
Type *pointer = malloc(sizeof(Type));
pointer = <<something else>>
It literally leaks memory and gains you nothing in two short lines. This isn't an object-reference based language like Java or C#. Pointers are variables that hold memory addresses. Just like an int can hold an integer, a pointer holds an address. And just like the following example:
int n = 6;
n = 5; //Hmm. Where did the 6 go? Oh yeah, We overwrote it with 5.
You will lose your allocation link doing the same thing with pointers:
struct node *root = malloc(sizeof(*root));
root = nodnou; // memory allocated above is gone. forever leaked.
Pointers are variables. Just like any other variable, they hold values. In the case of a pointer, however, its value is an address. You can have pointers to almost anything in C, including pointers to pointers; variables that hold the address of pointer variables. And I bring them up because they proffer a particularly elegant solution to your insertion requirements.
The following is a general implementation for a binary tree insertion that supports no duplicates in the tree (the code gets even shorter if you allow duplicates). Furthermore, it does this using exactly zero local variables beyond the provided function parameters, and I challenge you to dissect this and determine how it works. It even works on an initially NULL tree root pointer, eliminating the need to special casing if (root) {} else {} logic:
void insert_node(struct node **pp, int k)
{
while (*pp)
{
if (k < (*pp)->nr) // move down left side?
pp = &(*pp)->st;
else if ((*pp)->nr < k) // move down right side?
pp = &(*pp)->dr;
else return; // found the key, no dupes. leave
}
// pp contains the address of the pointer we need to set.
*pp = malloc(sizeof(**pp));
(*pp)->st = (*pp)->dr = NULL;
(*pp)->nr = k;
}
If your tree should support duplicates you need to be consistent about which side they are inserted on, but it shortens the above algorithm considerably:
void insert_node(struct node **pp, int k)
{
while (*pp)
pp = (k < (*pp)->nr) ? &(*pp)->st : &(*pp)->dr;
// pp contains the address of the pointer we need to set.
*pp = malloc(sizeof(**pp));
(*pp)->st = (*pp)->dr = NULL;
(*pp)->nr = k;
}
In either case, invoked on the caller side like this:
struct node *root = NULL;
insert(&root, 5);
insert(&root, 10);
insert(&root, 7);
...etc...
I think you should use while(flow != NULL) and insert your element as flow after that. The way it is right now it will stop in cases when it shouldn't and do weird things whenever it stops. Try working through some examples with pen and paper.
You almost got it. Keep Up!
First you need to understand a bit better memory allocation. In reality, you only need the very first malloc() call in your function. That is the memory you allocate for the node you are appending to the tree during each insert_node() call. All remainingr mallocs you are performing are unnecesary. It seems that you intuitively feel you need to allocate memory for the other pointers you are using, but all of them are temporary and don't require any allocation, just assignment to a valid node before attempting to de-reference them. In fact, those unnecesary allocations will create what is known as a memory leak (memory you request and fail to release) in code like this:
root = (struct node*)malloc(sizeof(node));
root = nodnou;
The second assignmet (root = nodnou) overwrites the result of the previous malloc() call and since you didn't save the overwritten pointer value in any other place, you will no longer be able to release that memory, it will be marked as used for the lifetime of your application!
Next, you can simplify the code that is walking the tree looking for the insertion point.
You seem to worry that flow becomes NULL, but it doesn't matter. The important node is parent. After the while loop ends, it will be pointing to the actual node where the inserted node needs to be linked. Here is a modified version of your code.
void insert_node(int k) {
struct node *nodnou, *flow, *parent;
// this is the only memory allocation that should be done
nodnou = (struct node*)malloc(sizeof(node));
nodnou->st = NULL;
nodnou->dr = NULL;
nodnou->nr = k;
parent = NULL;
if( root == NULL ) {
root = nodnou;
} else {
flow = root;
// We will walk the tree in order until we reach the bottom of the
// tree (flow becomes null). What we are trying to do is to find out
// the node that will become the parent of the new node we are inserting
// It doesn't matter if flow becomes NULL, the important value after the
// while loop ends is parent
while( flow != NULL ) {
// update the current potential parent node
parent = flow;
if( k < flow->nr ) {
// the number we are inserting is lower than the flow node, walk to the left
flow = flow->st;
} else {
// the number we are inserting is greater or equal than the flow node,
// walk to the right
flow = flow->dr;
}
}
// We have reached the bottom, now compare number again with the node that
// will become parent, to find out if we need to link this node to the left
// or to the right of the parent node
if( k < parent->nr ) {
parent->st = nodnou;
} else {
parent->dr = nodnou;
}
}
}
That's it. Try to code the rest of the tree operations and don't hesitate to ask if you become confused. =)

Failing to build a 'queue-like' structure - problems with struct declarations?

Hey guys. This is a very simple question, I'm sure, but I'm getting myself tangled up in C references/pointers as per usual. I am trying to build a... sort-of-queue, using a sort-of-linked list. Basically, I have a struct which has contents and a pointer to the next element. I also have a pointer to the first and last elements. I then have a loop that will be building the 'sort-of-queue'. My problem is that either my logic is failing and I'm not initialising the queue right, or my knowledge of C structs is failing (which is very probable) and I'm ending up just creating one struct and constantly referring to it.
My test code is as follows:
#include <stdio.h>
struct test {
int contents;
struct test *next;
};
main() {
struct test *first = NULL;
struct test *last = NULL;
int i;
for (i = 0; i < 2; i++) {
struct test tmp;
if (first == NULL) {
first = &tmp;
last = &tmp;
} else {
last->next = &tmp;
last = &tmp;
}
tmp.x = i;
tmp.next = NULL;
}
while (first != NULL) {
printf("%d\n", first->x);
first = first->next;
}
return 0;
}
Running this, I get the output that first seems to point to a test struct that has the value of '1' as it's 'x' variable - so not the initial one like I intended. So, am I failing at logic here, or am I failing at understanding how to declare new separate structs in a loop? Or maybe both? I'm very tired... >_<.
Thanks.
The problem you have is that you are taking the address of a temporary variable, tmp, and assigning it to a pointer which lives much longer than teh temporary, first and last. After every iteration of the loop the temporary is gone and continuing to access it via first and last results in undefined behavior.
You need to create a value on the heap in order to build up the list like so (error checking omitted for brevity)
struct test* tmp = malloc(sizeof(struct test));
Later though you'll need to go through and free all of the allocated nodes.

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