I'm trying to add an array to an array mainly using ARRAYLIB. Nothing I have done so far has worked
INSTALL #lib$ + "ARRAYLIB"
DIM ARRAY1(0)
DIM ARRAY2(3)
LET ARRAY2() = 1, 2, 3, 4
ARRAY1 is the main array with ARRAY2 being the array I want to append to ARRAY1. This is where I got stuck as everything I've tried didn't work.
PROC_add(ARRAY1(), ARRAY2())
PROC_add(ARRAY1(), (ARRAY2(0), ARRAY2(1), ARRAY2(2), ARRAY2(3))
PROC_add(ARRAY1(), ARRAY2(0), ARRAY2(1), ARRAY2(2), ARRAY2(3)
Proc_add doesn't append arrays as you expect. It adds a scalar value to all elements of an array.
INSTALL #lib$ + "ARRAYLIB"
DIM ARRAY(3)
LET ARRAY() = 1, 2, 3, 4
PROC_add(ARRAY(), 1)
DIM N% 0
FOR N%=0 TO 3
PRINT ARRAY(N%)
NEXT
will produce an output like
2
3
4
5
In order to append two arrays you need to create a third one and to copy both arrays into that.
DIM ARRAY1(0) ; 1 element
DIM ARRAY2(3) ; 4 elements
LET ARRAY2() = 1, 2, 3, 4
N1% = DIM(ARRAY1(),1) ; N1% = 0
N2% = DIM(ARRAY2(),1) ; N2% = 3
DIM ARRAY3(N1%+N2%+1) ; 5 elements
FOR N% = 0 TO N1% ; FOR N% = 0 TO 0
ARRAY3(N%) = ARRAY1(N%)
NEXT
FOR N% = N1% TO N1%+N2% ; FOR N% = 0 TO 3
ARRAY3(N%+1) = ARRAY2(N%)
NEXT
FOR N%=0 TO N1%+N2%+1
PRINT ARRAY3(N%) ; Prints 0,1,2,3,4
NEXT
Or you can write your own concatenate procedure as below:
DIM ARRAY1(0)
DIM ARRAY2(3)
LET ARRAY2() = 1, 2, 3, 4
PROC_Concat(ARRAY1(), ARRAY2(), ARRAY3())
FOR N% = 0 TO 4
PRINT ARRAY3(N%)
NEXT
END
DEF PROC_Concat(A1(), A2(), RETURN A3())
LOCAL N1%, N2%
N1% = DIM(A1(), 1)
N2% = DIM(A2(), 1)
DIM A3(N1%+N2%+1)
SYS "RtlMoveMemory", ^A3(0), ^A1(0), 10*(N1%+1)
SYS "RtlMoveMemory", ^A3(N1%+1), ^A2(0), 10*(N2%+1)
ENDPROC
Related
I have a dictionary and which also storing array. Here is the code and I am trying to assign some value to the array. But it always fails to assign value to the array. How can I solve this? Thanks
Code:
Dim dict As Dictionary
Set dict = New Dictionary
For i = 1 To fruitList.count
dict .Add fruitList(i), Array(0, 0, 0, 0, 0)
next
dict(apple)(0) = 100 //however, the first index in the array always equals to 0
Update:
Or I should ask in this way. Isn't the way I add array as value in dictionary wrong?
Give this a try:
Sub addArray2Dict()
Dim a: a = Array(1, 2, 3, 4, 5, 6, 7, 8, 9, 0) 'Here declare and store the array,
'you can do it any other way
'there is no difference if you do it here or
'in the loop
Dim b 'Just for testing porpuse
Dim oDict As Object 'Because I use “Microsoft Scripting Runtime” can use earle binding
Set oDict = CreateObject("Scripting.Dictionary")
Dim i 'iterator
'Store numbers and letters inside the dictionary
'BUT in the index number 5 I will store the array
For i = 1 To 20
If i = 5 Then
oDict.Add i, a
'oDict.Add i, Array(1, 2, 3, 4, 5, 6, 7, 8, 9, 0) 'As I said, this is the same as the line above.
Else
oDict.Add i, Chr(66 + i) 'Storing just letters in every key(integer)
End If
Next i
b = oDict(5) 'Here I take the array from the Dictionary, and store it inside b,
Debug.Print b(3) 'Here just print the 3th (number 4) elemente of the array
'remember the array is:
'
' array( 1 2 3 4 5 6 7 8 9 0 ) right!
' 0 1 2 3 4 5 6 7 8 9 <<< with that index
'
' if i want the 3th value i will get the number 4 in my example.
End Sub
Use this as a reference
“Microsoft Scripting Runtime” (Add using Tools->References from the VB
menu)
As I understand your code could be this:
Sub Test()
Dim fruitList(1 To 5) As String
Dim i
Dim B
fruitList(1) = "apple"
fruitList(2) = "banana"
fruitList(3) = "melon"
fruitList(4) = "orange" 'Love oranges!
fruitList(5) = "kiwi" 'Love Kiwi too!!!!
Dim dict As Dictionary
Set dict = New Dictionary
For i = LBound(fruitList) To UBound(fruitList) 'here you use the bounds of the array,
'instead .count, here won't work
dict.Add fruitList(i), Array(0, 0, 0, 0, 0)
Next
B = dict("apple") '(0) = 100 'however, the first index in the array always equals to 0
B(0) = 100 'Here! You take the array FROM the dictionary and store it inside B
'Just do it!
B(1) = 200
B(2) = 300
B(3) = 500
B(4) = 1000000
Debug.Print B(0) 'Testing! This will print in the console your value (100).
dict.Remove "apple" 'Remove the array
dict.Add "apple", B 'Return the new array!
End Sub
You can't change the values of an array stored inside an Dictionary (in VBA). It is better to take away de array and change the values, and after that, if you need it to, stored back in the dict.
Check this answer If Tim Williams says you can't it is because nobody can!
This can all be found here: https://learn.microsoft.com/en-us/dotnet/visual-basic/programming-guide/language-features/arrays/
Dim myArray(arraySize) As ArrayType
or
Dim myArray = New ArrayType() {Item1, Item2, ...}
So, in practice, it should look like this:
Dim companies(3) as String
companies(0) = "Microsoft"
companies(1) = "Google"
companies(2) = "Amazon"
or:
Dim companies = New String() {"Microsoft", "Google", "Amazon"}
I am currently trying to combine 46 arrays in to a single array. I have scoured the internet, to no prevail and am hoping someone here can help. I did find the below page, but I need to be able to look through each element of the new array in a nested for loop, so using the method below doesn't quite get me to my end goal.
Excel vba - combine multiple arrays into one
Basically, I need to combine my set of 46 arrays in such a way that I can then loop through each element using a nested for loop. ie.
Set of arrays:
myArray1 = (1, 2, 3, 4)
myArray2 = (5, 6, 7)
myArray3 = (8, 9)
myArray4 = (10, 11, 12, 13, 14)
.
.
.
myArray46 = (101, 102, 103)
Combine them to form new array:
myNewArray = (1, 2, 3, 4, 5, 6, 7, 8, 9, 10, 11, 12, 13, 14... 101, 102, 103)
Loop through in nested for loop to check each element against my main array:
For i = LBound(mainArray) to UBound(mainArray)
For j = LBound(myArray) to UBound(myArray)
If mainArray(i) = myArray(j) Then
'do something
End If
Next j
Next i
Any help and/ or guidance with this is greatly appreciated!
Since you write in your comments that your end goal is to create an array of unique elements, you might be best served using a dictionary, where you can test for uniqueness as you add each element to dictionary. Something like:
Option Explicit
Function uniqueArr(ParamArray myArr() As Variant) As Variant()
Dim dict As Object
Dim V As Variant, W As Variant
Dim I As Long
Set dict = CreateObject("Scripting.Dictionary")
For Each V In myArr 'loop through each myArr
For Each W In V 'loop through the contents of each myArr
If Not dict.exists(W) Then dict.Add W, W
Next W
Next V
uniqueArr = dict.keys
End Function
Sub tester()
Dim myArray1, myArray2, myArray3, myArray4, myArray5
myArray1 = Array(1, 2, 3, 4)
myArray2 = Array(5, 6, 7, 8)
myArray3 = Array(9, 10, 11, 12, 13, 14)
myArray4 = Array(15, 16)
myArray5 = Array(1, 3, 25, 100)
Dim mainArray
mainArray = uniqueArr(myArray1, myArray2, myArray3, myArray4, myArray5)
End Sub
If you run Tester, you will see mainArray contains:
1
2
3
4
5
6
7
8
9
10
11
12
13
14
15
16
25
100
Using your data this is how to create one array out of many:
Public Sub TestMe()
Dim myA, myB, myC, myD, myE
myA = Array(1, 2, 3, 4)
myB = Array(5, 6, 7)
myC = Array(8, 9)
myD = Array(10, 11, 12, 13, 14)
myE = Array(101, 102, 103)
Dim myCombine As Variant
Dim myNew() As Variant
Dim myElement As Variant
Dim myArr As Variant
Dim cnt As Long
myCombine = Array(myA, myB, myC, myD, myE)
For Each myArr In myCombine
For Each myElement In myArr
ReDim Preserve myNew(cnt)
myNew(cnt) = myElement
cnt = cnt + 1
Next
Next
For cnt = LBound(myNew) To UBound(myNew)
Debug.Print myNew(cnt)
Next cnt
End Sub
The "building" of the new array is facilitated through ReDim Preserve, which keeps the old values in the array whenver the dimension of the array changes. And if you want to do something with these arrays, you may use 3 nested loops (a bit slow) and have some check:
Dim cnt2 As Long
For cnt = LBound(myNew) To UBound(myNew)
For cnt2 = LBound(myCombine) To UBound(myCombine)
For Each myElement In myCombine(cnt2)
If myElement = myNew(cnt) Then
Debug.Print myElement & vbTab & " from " & vbTab & cnt2
End If
Next myElement
Next cnt2
Next cnt
This is what you get on the immediate window:
1 from 0
2 from 0
3 from 0
4 from 0
5 from 1
6 from 1
7 from 1
8 from 2
9 from 2
10 from 3
11 from 3
12 from 3
13 from 3
14 from 3
101 from 4
102 from 4
103 from 4
Alternate 'brick-by-brick' approach.
Option Explicit
Sub combineArrays()
Dim myArray1 As Variant, myArray2 As Variant, myArray3 As Variant
Dim myArray4 As Variant, myArray46 As Variant
ReDim mainArray(0) As Variant
myArray1 = Array(1, 2, 3, 4)
myArray2 = Array(5, 6, 7)
myArray3 = Array(8, 9)
myArray4 = Array(10, 11, 12, 13, 14)
'...
myArray46 = Array(101, 102, 103)
mainArray = buildMainArray(myArray1, mainArray)
mainArray = buildMainArray(myArray2, mainArray)
mainArray = buildMainArray(myArray3, mainArray)
mainArray = buildMainArray(myArray4, mainArray)
mainArray = buildMainArray(myArray46, mainArray)
ReDim Preserve mainArray(UBound(mainArray) - 1)
Debug.Print Join(mainArray, ",")
End Sub
Function buildMainArray(arr As Variant, marr As Variant)
Dim i As Long
For i = LBound(arr) To UBound(arr)
marr(UBound(marr)) = arr(i)
ReDim Preserve marr(UBound(marr) + 1)
Next i
buildMainArray = marr
End Function
The issue with using Redim Preserve to combine arrays is it can be an expensive operation, since you're basically re-creating the array everytime it's called. Since you have 46 arrays you're combining, you may very well be waiting a while.
Instead, you can loop over the arrays to figure out the total number of elements you need, dimension out your master array, then loop over the arrays again to do the actual assignment/merging. Something like this:
' encapsulates code to determine length of an individual array
' note that because arrays can have different LBounds in VBA, we can't simply use
' Ubound to determine array length
Public Function GetArrayLength(anArray As Variant) As Integer
If Not IsArray(anArray) Then
GetArrayLength = -1
Else
GetArrayLength = UBound(anArray) - LBound(anArray) + 1
End If
End Function
Public Function CombineArrays(ParamArray arraysToMerge() As Variant) As Variant
' index for looping over the arraysToMerge array of arrays,
' and then each item in each array
Dim i As Integer, j As Integer
' variable to store where we are in the combined array
Dim combinedArrayIndex As Integer
' variable to hold the number of elements in the final combined array
Dim CombinedArrayLength As Integer
' we don't initialize the array with an array-length until later,
' when we know how long it needs to be.
Dim combinedArray() As Variant
' we have to loop over the arrays twice:
' First, to figure out the total number of elements in the combined array
' second, to actually assign the values
' otherwise, we'd be using Redim Preserve, which can get quite expensive
' because we're creating a new array everytime we use it.
CombinedArrayLength = 0
For i = LBound(arraysToMerge) To UBound(arraysToMerge)
CombinedArrayLength = CombinedArrayLength + GetArrayLength(arraysToMerge(i))
Next i
' now that we know how long the combined array has to be,
' we can properly initialize it.
' you can also use the commented code instead, if you prefer 1-based arrays.
ReDim combinedArray(0 To CombinedArrayLength - 1)
' Redim combinedArray(1 to CombinedArrayLength)
' now that the combinedarray is set up to store all the values in the arrays,
' we can begin actual assignment
combinedArrayIndex = LBound(combinedArray)
For i = LBound(arraysToMerge) To UBound(arraysToMerge)
For j = LBound(arraysToMerge(i)) To UBound(arraysToMerge(i))
combinedArray(combinedArrayIndex) = arraysToMerge(i)(j)
combinedArrayIndex = combinedArrayIndex + 1
Next j
Next i
' assign the function to the master array we've been using
CombineArrays = combinedArray
End Function
To use this function, you'd do something like the following:
Public Sub TestArrayMerge()
Dim myArray1() As Variant
Dim myArray2() As Variant
Dim myArray3() As Variant
Dim myArray4() As Variant
Dim combinedArray As Variant
myArray1 = Array(1, 2, 3, 4)
myArray2 = Array(5, 6, 7)
myArray3 = Array(8, 9)
myArray4 = Array(10, 11, 12, 13, 14)
combinedArray = CombineArrays(myArray1, myArray2, myArray3, myArray4)
If IsArray(combinedArray) Then
Debug.Print Join(combinedArray, ",")
End If
End Sub
Regarding your last bit, that you're using an inner loop to combine the values in your final combined array: Your inner loop doesn't need to start at LBound(myArray). For any value of i, you've already compared it to the elements before it (e.g., when i = 2, it's already been compared to the first element). So you really just need:
For i = LBound(combinedArray) To UBound(combinedArray) - 1
For j = i + 1 To UBound(combinedArray)
' do whatever you need
Next j
Next i
Perhaps this ...
'To determine if a multi-dimension array is allocated (or empty)
'Works for any-dimension arrays, even one-dimension arrays
Public Function isArrayAllocated(ByVal aArray As Variant) As Boolean
On Error Resume Next
isArrayAllocated = IsArray(aArray) And Not IsError(LBound(aArray, 1)) And LBound(aArray, 1) <= UBound(aArray, 1)
Err.Clear: On Error GoTo 0
End Function
'To determine the number of items within any-dimension array
'Returns 0 when array is empty, and -1 if there is an error
Public Function itemsInArray(ByVal aArray As Variant) As Long
Dim item As Variant, UBoundCount As Long
UBoundCount = -1
If IsArray(aArray) Then
UBoundCount = 0
If isArrayAllocated(aArray) Then
For Each item In aArray
UBoundCount = UBoundCount + 1
Next item
End If
End If
itemsInArray = UBoundCount
End Function
'To determine the number of dimensions of an array
'Returns -1 if there is an error
Public Function nbrDimensions(ByVal aArray As Variant) As Long
Dim x As Long, tmpVal As Long
If Not IsArray(aArray) Then
nbrDimensions = -1
Exit Function
End If
On Error GoTo finalDimension
For x = 1 To 65536 'Maximum number of dimensions (size limit) for an array that will work with worksheets under Excel VBA
tmpVal = LBound(aArray, x)
Next x
finalDimension:
nbrDimensions = x - 1
Err.Clear: On Error GoTo 0
End Function
'****************************************************************************************************
' To merge an indefinite number of one-dimension arrays together into a single one-dimension array
' Usage: mergeOneDimArrays(arr1, arr2, arr3, ...)
' Returns an empty array if there is an error
' Option Base 0
'****************************************************************************************************
Public Function mergeOneDimArrays(ParamArray infArrays() As Variant) As Variant
Dim x As Long, y As Long, UBoundCount As Long, newUBoundCount As Long
Dim tmpArr As Variant, allArraysOK As Boolean
UBoundCount = 0
allArraysOK = True
For x = LBound(infArrays) To UBound(infArrays)
If Not IsArray(infArrays(x)) Or Not nbrDimensions(infArrays(x)) = 1 Then
allArraysOK = False
Exit For
End If
UBoundCount = UBoundCount + itemsInArray(infArrays(x))
Next x
If allArraysOK Then
ReDim tmpArr(0 To UBoundCount - 1)
UBoundCount = 0
For x = LBound(infArrays) To UBound(infArrays)
For y = LBound(infArrays(x)) To UBound(infArrays(x))
tmpArr(UBoundCount) = infArrays(x)(y)
UBoundCount = UBoundCount + 1
Next y
Next x
newUBoundCount = itemsInArray(tmpArr)
If newUBoundCount = UBoundCount Then
mergeOneDimArrays = tmpArr
Else
mergeOneDimArrays = Array()
End If
Erase tmpArr
Else
mergeOneDimArrays = Array()
End If
End Function
If you are working with one-dimensional arrays you could use a collection instead. It is much better at handling dynamic sizing.
You can declare a collection and then add each of the elements in the arrays to it. Then you will have one large list with all of the values.
Dim coll As New Collection
coll.Add MyArray(j)
Here is a good to collections introduction:
https://excelmacromastery.com/excel-vba-collections/
I have a array which have 1 or more columns and now I want to add one more column (consists only of 1), but I don't know how do do that. The situation looks like that:
My code:
Dim X() As Variant
X = Range("A1:C3").Value2
It's is important to put column with 1 as first. Probably I need to use ReDim Preserve but nothing works for me.
I think you have some options, but instead of extending the index of the array and transposing, trying to move the values etc which seems too much of a hassle, I would rather add 1 to the Excel range and then create the array:
Range("B1:D3").Value2 = Range("A1:C3").Value2
Range("A1:A3").Value2 = 1
X = Range("A1:D3").Value2
Resize the Array adding a column to the last dimension
Shift all the data to the right.
Assign 1 to the first position in each row
Sub AddColumnShiftData()
Dim X As Variant
Dim i As Long, j As Long
X = Range("A1:C3").Value2
ReDim Preserve X(1 To 3, 1 To 4)
For i = 1 To UBound(X)
For j = UBound(X, 2) To 2 Step -1
X(i, j) = X(i, j - 1)
Next
X(i, 1) = 1
Next
End Sub
Try matrix multiplication by the identify matrix....Well almost identity matrix. Then add 1 to every element in of the resulting matrix. You can use the Excel's Worksheet function for matrix multiplication.
Almost identity matrix
Dim X As Variant
X = Range("A1:C3").Value2
Dim Y As Variant
n = UBound(X, 2)
m = n + 1
Z = UBound(X, 1)
ReDim Y(1 To n, 1 To m)
'Set All values to zero
For i = 1 To n
For j = 1 To m
Y(i, j) = 0
Next j
Next i
' Set offset diagonal to 1
For i = 1 To n
Y(i, i + 1) = 1
Next i
' Matrix MMult
X = Application.WorksheetFunction.MMult(X, Y)
' Add 1 to the first column
For i = 1 To Z
X(i, 1) = 1
Next i
Alternative via Application.Index()
Just for fun (note that the resulting array is a 1-based 2-dim array):
Sub AddFirstIndexColumn()
Const FIXEDVALUE = 1 ' value to replace in new column 1
'[1] get data
Dim v: v = getExampleData()
'[2] define column array inserting first column (0 or 1) and preserving old values (1,2,3)
v = Application.Index(v, _
Application.Evaluate("row(1:" & UBound(v) & ")"), _
Array(1, 1, 2, 3)) ' columns array where 0 reinserts the first column
' [3] add an current number in the first column
Dim i As Long
For i = LBound(v) To UBound(v): v(i, 1) = FIXEDVALUE: Next i
End Sub
Function getExampleData()
' Method: just for fun a rather unusual way to create a 2-dim array
' Caveat: time-consuming for greater data sets; better to assign a range to a datafield array
Dim v
v = Array(Array(2, 3, 5), Array(3, 8, 9), Array(4, 2, 1))
v = Application.Index(v, 0, 0)
getExampleData = v
End Function
Related links
Some pecularities of `Application.Index()
Insert vertical slices into array
I am working on project in vb.net, I have an integer array for example (1,8,9,8), what I need is to generate number of arrays from it by add 1 to each item at a time so that the first array suppose to be (2,8,9,8) and the second (1,9,9,8) and so on, I tried this code:
Function myarray(ByVal arra1() As Integer, ByVal arran() As Integer, ByVal i As Integer) As Integer
For i = 0 To arra1.Length -
arran(i) = arra1(i)
arran(i) = arra1(i) + 1
Next
End Function
As much I understand from the question in current given context this may be your required solution:
Function myarray(ByVal arra1() As Integer, ByVal arran() As Integer, ByVal arrNumber As Integer) As Integer
arran=arra1.Clone()
For i As Integer = 0 To arra1.Length - 1
If i = (arrNumber - 1) Then ' IF arrNumber is 1 then +1 to index 0, If it is 2 then +1 to index 1
arran(i) = arra1(i) + 1
Else
arran(i) = arra1(i)
End If
Next
'Print the array
For i = 0 To arran.Length - 1
Console.Write(arran(i) & " ")
Next
Console.WriteLine()
Return 0
End Function
You can call it as
Dim a3() As Integer={1,8,9,8}
Dim a4() As Integer={}
myarray(a3,a4,1)
myarray(a3,a4,2)
myarray(a3,a4,3)
myarray(a3,a4,4)
When you call this function with arra1 as (1,8,9,8)
and arrNumber as 1 then arran will be (2,8,9,8),
with arrNumber as 2 then arran will be (1,9,9,8),
with arrNumber as 3 then arran will be (1,8,10,8) and
with arrNumber as 4 then arran will be (1,8,9,9)
First declare your initial array.
' declare initial array
Dim arr1 = {1, 8, 9, 8}
Then declare a jagged array for the result. Since the initial array has 4 elements, it will create a 4 arrays.
' declare a jagged array for the result
Dim result(arr1.Length - 1)() As Integer
Then you clone the initial array, and only change one of the value.
For i = 0 To arr1.Length - 1
' clone the initial array
result(i) = arr1.Clone()
' only change the element at index = i
result(i)(i) += 1
Next
Result is:
2 8 9 8
1 9 9 8
1 8 10 8
1 8 9 9
Full source:
Module Module1
Sub Main()
' declare initial array
Dim arr1 = {1, 8, 9, 8}
' declare a jagged array for the result
Dim result(arr1.Length - 1)() As Integer
For i = 0 To arr1.Length - 1
' clone the initial array
result(i) = arr1.Clone()
' only change the element at index = i
result(i)(i) += 1
Next
' print result
For i = 0 To result.Length - 1
For j = 0 To result(i).Length - 1
Console.Write(result(i)(j) & " ")
Next
Console.WriteLine()
Next
Console.ReadKey(True)
End Sub
End Module
In case you want to make a function.
Function CopyArray(ByVal source As Integer(), i As Integer) As Integer()
' clone the initial array
Dim temp = source.Clone()
' only change the element at index = i
temp(i) += 1
Return temp
End Function
You call the function inside the iteration.
For i = 0 To arr1.Length - 1
result(i) = CopyArray(arr1, i)
Next
Full source with function:
Module Module1
Sub Main()
' declare initial array
Dim arr1 = {1, 8, 9, 8}
' declare a jagged array for the result
Dim result(arr1.Length - 1)() As Integer
For i = 0 To arr1.Length - 1
result(i) = CopyArray(arr1, i)
Next
' print result
For i = 0 To result.Length - 1
For j = 0 To result(i).Length - 1
Console.Write(result(i)(j) & " ")
Next
Console.WriteLine()
Next
Console.ReadKey(True)
End Sub
Function CopyArray(ByVal source As Integer(), i As Integer) As Integer()
' clone the initial array
Dim temp = source.Clone()
' only change the element at index = i
temp(i) += 1
Return temp
End Function
End Module
I want to find the index of the nth largest value in an array. I can do the following but it runs into trouble when 2 values are equal.
fltArr(0)=31
fltArr(1)=15
fltArr(2)=31
fltArr(3)=52
For i = 0 To UBound(fltArr)
If fltArr(i) = Application.WorksheetFunction.Large(fltArr, n) Then
result = i
End If
Next
n=1 ---> 3
n=2 ---> 2 (but I want this to be 0)
n=3 ---> 2
n=4 ---> 1
Uses a second array to quickly get what you want without looping through each element for every value of n
Sub test()
Dim fltArr(0 To 3)
Dim X
Dim n As Long
Dim lngPos As Long
fltArr(0) = 31
fltArr(1) = 15
fltArr(2) = 31
fltArr(3) = 52
X = fltArr
For n = 1 To 4
lngPos = Application.WorksheetFunction.Match(Application.Large(X, n), X, 0) - 1
Debug.Print lngPos
X(lngPos) = Application.Max(X)
Next
End Sub
Edit:
Public Sub RunLarge()
Dim n%, i%, result%, count%
Dim fltArr(3) As Integer
Dim iLarge As Integer
fltArr(0) = 31:
fltArr(1) = 15:
fltArr(2) = 31:
fltArr(3) = 52
n = 1
Debug.Print " n", "iLarge", "result"
While n <= 4
count% = n - 1
iLarge = Application.WorksheetFunction.Large(fltArr, n)
For i = 0 To UBound(fltArr)
If fltArr(i) = iLarge Then
result = i
count% = count% - 1
If count% <= 0 Then Exit For
End If
Next
Debug.Print n, iLarge, result
n = n + 1
Wend
End Sub
result:
n iLarge result
1 52 3
2 31 0
3 31 2
4 15 1
It's a bit "dirty" but seeing as you're in Excel...
' Create a sheet with codename wsTemp...
For i = 0 To UBound(fltArr)
wsTemp.cells(i,1) = i
wsTemp.cells(i,2) = fltArr(i)
Next
with wsTemp
.range(.cells(1,1),.cells(i,2)).sort(wsTemp.cells(1,2),xlDescending)
end with
Result = wsTemp.cells(n,1)
Then you could also expand the sort to "sort by value then by index" if you wanted to control the "which of two equal 2nds should i choose" thing...
Perhaps this:
Public Sub RunLarge()
Dim fltArr() As Variant, X As Long
fltArr = Array(31, 15, 31, 52) 'Create the array
For X = 1 To 4 'Loop the number of large values you want to index
For i = LBound(fltArr) To UBound(fltArr) 'Loop the array
If fltArr(i) = Application.WorksheetFunction.Large(fltArr, 1) Then 'Find first instance of largest value
result = i
fltArr(i) = -9999 'Change the value in the array to -9999
Exit For
End If
Next
Debug.Print result
Next
End Sub
As it finds the first instance of the large number it replaces it with -9999 so on the next sweep it will pick the next instance of it.
Here's code for finding the nth largest item in collection. All you need to do is to write a function that would return it's index.
Sub testColl()
Dim tempColl As Collection
Set tempColl = New Collection
tempColl.Add 57
tempColl.Add 10
tempColl.Add 15
tempColl.Add 100
tempColl.Add 8
Debug.Print largestNumber(tempColl, 2) 'prints 57
End Sub
and the function itself, the easiest I could come up with.
Function largestNumber(inputColl As Collection, indexMax As Long)
Dim element As Variant
Dim result As Double
result = 0
Dim i As Long
Dim previousMax As Double
For i = 1 To indexMax
For Each element In inputColl
If i > 1 And element > result And element < previousMax Then
result = element
ElseIf i = 1 And element > result Then
result = element
End If
Next
previousMax = result
result = 0
Next
largestNumber = previousMax
End Function