In my CakePHP 2 project, I have Projects that have many Articles, an Article can belong to many projects (a many-to-many relation).
Now I would like to find all Projects that have an Article.
My current code for getting the Projects is as follows
$projects = $this->Project->find('list', array(
'fields' => array('Project.slug', 'Project.name')
));
I tried adding contain to the query, without results
$projects = $this->Project->find('list', array(
'contain' => array('PressArticles' => array()),
'fields' => array('Project.slug', 'Project.name')
));
How can I modify this so I receive all projects that have an article?
Containing won't help, non-1:1 relations will be retrieved in a separate query, so that won't have any effect on your main query.
You could for example manually create INNER joins with the association's join and target table, that would automatically filter out all projects that have no associated articles, something along the lines of this (I've more or less guessed the names, it's just a quick and dirty example):
$projects = $this->Project->find('list', array(
'fields' => array('Project.slug', 'Project.name'),
'joins' => array(
array(
'table' => 'press_articles_projects',
'alias' => 'PressArticleProject',
'type' => 'INNER',
'conditions' => array(
'PressArticleProject.project_id = Project.id',
),
),
array(
'table' => 'press_articles',
'alias' => 'PressArticle',
'type' => 'INNER',
'conditions' => array(
'PressArticle.id = PressArticleProject.press_article_id',
),
)
),
'group' => 'Project.id'
));
Or if you are using a counter cache, then filtering by the counter would be an option too:
$projects = $this->Project->find('list', array(
'fields' => array('Project.slug', 'Project.name'),
'conditions' => array(
'Project.press_article_count >' => 0
)
));
See also
Cookbook > Models > Associations: Linking Models Together > Joining tables
Cookbook > Models > Associations: Linking Models Together > counterCache - Cache your count()
In your Project model, you can do
public $hasMany = array(
'PressArticle' => array(
'className' => 'PressArticle',
'foreignKey' => 'project_id'
)
);
For more info, check here
Related
I'm facing a problem with cakephp associations in Models.
I have to Select records which have atleast one hasMany reation row
Model
class Category extends AppModel
{
public $hasMany = array(
'Product' => array(
'className' => 'Product',
'foreignKey' => 'CategoryId',
)
);
}
Query
$categories = $this->Category->find('all');
I only needed the categories which have atleast one product entry
Categories Like : Shirts, Footwear, Glasses etc
Products like :
Small, medium, large (Shirts)
With Frame, UV protected (Glass)
So, i jus want to get Shirts and Glasses Categories only because for the above example there is no products for Footwear
Use counterCache or joins
Please refer to CakePHP - Find and count how many associated records exist
The most simple way with the best performance would be using a properly indexed counter cache field as shown in the linked answer.
Sice the linked answer is not an exact duplicate with respect to the join, here's some additional info, instead of using HAVING COUNT with the join you'd use a IS NOT NULL condition. Here's an (untested) example:
$this->Category->find('all', array(
'joins' => array(
array(
'table' => 'products',
'alias' => 'Product',
'type' => 'LEFT',
'conditions' => array('Category.id = Product.CategoryId')
)
),
'conditions' => array(
'Product.CategoryId IS NOT NULL'
)
'group' => 'Category.id'
));
Depending on the used DBMS and version you might get better performance using an inner join:
$this->Category->find('all', array(
'joins' => array(
array(
'table' => 'products',
'alias' => 'Product',
'type' => 'INNER',
'conditions' => array('Category.id = Product.CategoryId')
)
),
'group' => 'Category.id'
));
I have some deep associations using containable and need to filter back the results. For the sake of this question, let's say we are selling cars and want to narrow the results down by features.
Car hasmany make hasmany model HABTM features
$options = array(
'order' => array('Car.price'),
'contain' => array(
'make',
'model' => array(
'order' => 'Model.name ASC'
),
'features'
)
);
$cars = $this->Car->find('all', $options);
How would I go about excluding all cars that don't have power windows (Features.name != power_windows).
Containable is only suitable for you to specify what models you wanted to include when fetching data, but not limiting the parent model from fetching data at all. One obvious symptom is that sometimes your parent data may have some null contained data.
So to achieve it, I think we should use joins here so you can specify condition:
$options = array(
'order' => array('Car.price'),
'contain' => array(
'make',
'model' => array(
'order' => 'Model.name ASC'
),
'features'
),
'joins' => array(
array(
'table' => 'features',
'alias' => 'Feature',
'type' => 'LEFT',
'conditions' => array(
'Car.id = Feature.car_id'
)
)
),
'conditions' => array(
'Features.name !=' => 'power_windows',
)
);
But one drawback of this is that you might have duplicated Car due to joining. That's a separate issue ;)
In my CakePHP app I have three tables:
Businesses, Towns and Categories.
A business can belong to multiple towns and multiple categories so I have created joining tables and hasMany and belongsTo relationships. Everything works fine when finding businesses by either Town or Category by using the Town or Category model to search, but I am completely stuck when I want to search for businesses in a certain town AND a certain category, eg. Plumbers in London.
The associations just don't seem to work when searching with the Business model and I get column not found errors when trying to use the associated tables. I would think that this would be along the lines of what needs to be done, but I can't get it to work:
$this->set('listings', $this->Business->find('all', array(
'conditions' => array(
'Business.approved' => 1,
'BusinessesCategory.category_id' => $id,
'BusinessesTown.town_id' => $town_id,
'Business.sasite' => 1
)
You need to join the tables to do that.
I will put above a example how has to work with category and you can do the town yourself.
$this->Business->find("all", array(
"joins" => array(
array(
"table" => "businness_categories",
"alias" => "BusinessesCategory",
"type" => "LEFT",
"conditions" => array(
"Businesses.id = BusinessesCategory.business_id"
)
),
array(
"table" => "categories",
"alias" => "Category",
"type" => "LEFT",
"conditions" => array(
"BusinessesCategory.category_id = Category.id"
)
)
),
'conditions' => array(
'Business.approved' => 1,
'Category.id' => $id,
)
));
You also could use a behavior to do that for you:
https://github.com/Scoup/SuperJoin
Hi I had a very similar setup and the same problem. This is how I would solve your problem:
As you dont give away to much of your code I make some assumptions:
- You implemented your search method in the BusinessController
- Your search argument for the town is stored in vaiable $where and the one for Category is stored in $what
Code if you only have conditions for one table
$this->Businesses->Town->recursive = -1;
....
$options['joins'] = array(
array('table' => 'towns',
'alias' => 'Town',
'type' => 'inner',
'conditions' => array(
'Business.town_id = Town.id',
)
)
);
$options['conditions'] = array(
'Town.townName' => $where
);
$result = $this->Business->find('all', $options);
Code if you have conditions for two table
$this->Businesses->Town->recursive = -1;
$this->Businesses->Category->recursive = -1;
....
$options['joins'] = array(
array('table' => 'towns',
'alias' => 'Town',
'type' => 'inner',
'conditions' => array(
'Business.town_id = Town.id',
)
),
array('table' => 'categories',
'alias' => 'Category',
'type' => 'inner',
'conditions' => array(
'Business.category_id = category.id',
)
)
);
$options['conditions'] = array(
'Town.townName' => $where,
'Category.categoryName' => $what
);
$result = $this->Business->find('all', $options);
You can use
$this->Business->find('all', array(
'conditions' => array(
'AND' => array(
'BusinessesTown.town_id' => $town_id,
'BusinessesCategory.category_id' => $id
)
),
'recursive' => 2
));
I have a query that I am running through paginate. This query contains a model ("PaymentException") that has an afterfind method that tacks on a copy of the last "ExceptionWorkflowLog", and calls it "LastWorkflowLog".
The query being passed to paginate:
$this->paginate = array(
'fields' => array(
'PaymentException.*', 'Procedure.id', 'Procedure.cpt',
'Procedure.expected_amount', 'Procedure.allowed_amount', 'Procedure.difference_amount',
'Claim.id', 'Claim.number', 'Payer.abbr'
),
'limit' => 50,
'joins' => array(
array(
'table' => 'procedures',
'alias' => 'Procedure',
'conditions' => array('Procedure.id = PaymentException.procedure_id')
),
array(
'table' => 'claims',
'alias' => 'Claim',
'conditions' => array('Claim.id = Procedure.claim_id')
),
array(
'table' => 'payers',
'alias' => 'Payer',
'conditions' => array('Payer.id = Procedure.payer_id')
),
array(
'table' => 'groups',
'alias' => 'Groups',
'conditions' => array('Groups.id = Claim.group_id')
)
),
'conditions' => $conditions,
'contain' => array('ExceptionWorkflowLog')
);
The resulting array (from the query that combines both "PaymentException", "ExceptionWorkflowLog", and "LastWorkflowLog") looks like below:
0 =>
'PaymentException' => array(fields and values),
'ExceptionWorkflowLog' => array(of ExceptionWorkflowLogs),
'LastWorkflowLog' => array(fields and values of the last indexed ExceptionWorkflowLog)
1 => ...
ExceptionWorkflowLog is mapped to PaymentException by PaymentException.id. It's a many to one relationship (thus the array of results under the ExceptionWorkflowLog).
I would like to use paginate to sort on the "updated" field on either the last indexed ExceptionWorkflowLog or the LastWorkflowLog.
Is there a way to do this with paginate? Currently, if I set the table heading to point to "LastWorkflowLog.updated", the query returns false because the query doesn't know what "LastWorkflowLog" is.
Since this has a couple hundred views, I figured I'd come back and post what I did. CakePHP's handling of joins is absolutely terrible. I rewrote the query to not use joins, but use contains. That seems to have solved it. I feel dirty.
i have multiple habtm like these :
// User model
var $hasMany = array('Post');
// Post model
var $hasAndBelongsToMany = array('Category', 'Tag');
// Category model
var $hasAndBelongsToMany = array('Post');
// Tag model
var $hasAndBelongsToMany = array('Post');
I tried to fetch all post along with its user and tags (within a certain category), somehow if i fetch tags, the result was wrong.
$this->paginate = array
(
'Post' => array
(
'limit' => 2,
'fields' => array(
'Post.title', 'Post.content', 'Post.slug', 'Post.created',
'Tag.name',
'User.username', 'User.created', 'User.post_count', 'User.avatar_file_name'),
'joins' => array
(
array(
'table' => 'categories_posts',
'alias' => 'CategoriesPost',
'type' => 'inner',
'conditions'=> array('CategoriesPost.post_id = Post.id')
),
// FETCH USER
array(
'table' => 'users',
'alias' => 'User',
'type' => 'inner',
'conditions'=> array('Post.user_id = User.id')
),
// FETCH TAGS
array(
'table' => 'posts_tags',
'alias' => 'PostsTag',
'type' => 'inner',
'conditions'=> array('PostsTag.post_id = Post.id')
),
array(
'table' => 'tags',
'alias' => 'Tag',
'type' => 'inner',
'conditions'=> array('Tag.id = PostsTag.tag_id')
),
array(
'table' => 'categories',
'alias' => 'Category',
'type' => 'inner',
'conditions'=> array('Category.id = CategoriesPost.category_id', 'Category.slug' => $slug)
)
)
)
);
$posts = $this->paginate();
could anyone gimme a solution since i'm a newbie?
many thanks...
I've run into a similar problem, when trying to paginate a resultset using an associated model. I ended up having to manually bind my models together, run the query, and then unbind them in order to get Cake to contain the right data together. ( http://book.cakephp.org/view/86/Creating-and-Destroying-Associations-on-the-Fly )
You could also try the containable behaviour which will allow you to specify which models you want to include in your result set. Containable is core in 1.2+ ( http://book.cakephp.org/view/474/Containable ), otherwise you'll need to grab it yourself.
I'm not too sure on why you have such a gargantuan query there though. I would be more inclined to do something similar to the following.
$this->Model->recursive = 2;
$this->Model->paginate();
And let Cake get all the related data for me through my associations. Then I would adjust the return using a conditions array ( http://api.cakephp.org/class/controller#method-Controllerpaginate ) to specify the category.
Sorry it's not a defacto solution, but I'm a CakePHP amateur myself! You might find it easier to view the queries, results etc, using DebugKit, http://github.com/cakephp/debug_kit