JDL: Multiple Menu - database

I trying to create multiple menu category using JDL. In one CategoryItem have parentID.
I already created JDL like:
microservice * with Category
entity CategoryItem{
name String required
}
relationship ManyToOne{
CategoryItem{parrent} to CategoryItem
}
service * with serviceClass
paginate CategoryItem with pagination
If the client calls a method findAll. Can I return JSON format like that:
[
{
"id": 1,
"name": "car",
"CategoryItem": [
{
"id": 2,
"name": "red car"
},
{
"id": 3,
"name": "blue car"
}
]
},
{
"id": 4,
"name": "bike",
"CategoryItem": []
}
]

Related

How filter and delete object with null or empty property in json query

I have this json :
{
"meta": {
"status": 200,
"pagination": {
"page": 1,
"perPage": 15,
"hasNext": true
}
},
"data": [
{
"id": "1",
"title": "Movie title1"
"rating": null,
"playProviders": [
]
},
{
"id": "2",
"title": "Movie title2"
"rating": {
"ratingAssessment": "7.1"
},
"playProviders": [
"HBO", "Netflix"
]
},
....
}
I want to create a page with a list of movies, I need to fetch movies but only those which have a rating and playProviders, what parameters should I use in this request?
https://api.com/movies?orderBy=views
When I filters in the code:
programs.filter((program) => program.rating !== null);
it only gets a few films per page, those that don't have null. For example, 15 are per page and I get 2. How do I filter this? (I am using react typescript)
I don't have access to the API code. I need to filter what is returned by the API or write a query so that you get already filtered data from the API.
programs = [
{rating: 1,
playProviders: ["sf"]
},
{
rating: 4,
playProviders: []
}
]
programs.filter(function(program) {
if (program.rating !== null && program.playProviders.length !== 0) {
return program;
}
})

Return one array of data in sub-document of Mongodb

I'm using Nodejs with Mongoose package.
Given I've something like this:-
let people = [
{
"_id": 1,
"name": "Person 1",
"pets": [
{
"_id": 1,
"name": "Tom",
"category": "cat"
},
{
"_id": 2,
"name": "Jerry",
"category": "mouse"
}
]
}
]
I want to get only the data of Jerry in pets array using it's _id (result shown below)
{
"_id": 2,
"name": "Jerry",
"category": "mouse"
}
Can I get it without needing to specify the _id of person 1 when using $elemMatch? Right now I code like this:-
const pet = People.find(
{ "_id": "1"}, // specifying 'person 1 _id' first
{ pets: { $elemMatch: { _id: 2 } } } // using 'elemMatch' to get 'pet' with '_id' of '2'
)
And it gave me what I want like I've shown you above. But is there any other way I can do this without needing to specify the _id of it's parent first (in this case, the _id of the people array)
Assuming nested array's _id's are unique you can filter by nested array elements directly:
const pet = People.find(
{ "pets._id": 2 },
{ pets: { $elemMatch: { _id: 2 } } }
)

How to Join Multiple Arrays inside filter function of Arrays in Typescript

I am using Typescript in an Angular/Ionic project. I have an array of users that contain an array of skills. I have to filter users based on their online status as well as skills.
[
{
"id": 1,
"name": "Vikram Shah",
"online_status": "Online",
"skills": [{
"id": 2,
"title": "CSS"
},
{
"id": 3,
"title": "JavaScript"
},
{
"id": 4,
"title": "Python"
}
]
},
{
"id": 1,
"name": "Abhay Singh",
"online_status": "Online",
"skills": [{
"id": 1,
"title": "HTML"
},
{
"id": 2,
"title": "CSS"
},
{
"id": 3,
"title": "JavaScript"
},
{
"id": 4,
"title": "Python"
}
]
},
{
"id": 1,
"name": "Test Oberoi",
"online_status": "Online",
"skills": [{
"id": 1,
"title": "HTML"
},
{
"id": 2,
"title": "CSS"
},
{
"id": 3,
"title": "JavaScript"
},
{
"id": 4,
"title": "Python"
}
]
}
]
This is how all skills look like
this.skill_types = [
{"id":8,"title":"Cleaner", checked:false},
{"id":7,"title":"Painter", checked:false},
{"id":6,"title":"Plumber", checked:false},
{"id":5,"title":"Carpenter", checked:false},
{"id":4,"title":"Advisor", checked:false},
{"id":3,"title":"Team Leader", checked:false},
{"id":2,"title":"Management", checked:false},
{"id":1,"title":"Administrator", checked:false}
];
This array contains the IDs of skills that I want to filter
filterArr = [1, 3, 6];
This solution is almost working as expected. It is filtering well based on two criteria together.But not sure how to add condition for second filtering. The second filter should apply only if filterArr is not empty.
return this.items = this.items.filter((thisUser) => {
return thisUser.online_status.toLowerCase().indexOf(onlineStatus.toLowerCase()) > -1 &&
thisUser.skills.some(c => this.filterArr.includes(c.id))
});
The issue I am facing with code above is When there is no skill selected in the filter criteria, I would like to display all users. But it is not working that way. The logic here is to not apply any filter when the size of selected skills (filter condition) is greater than zero. So I tried this way....which looks similar to the way above...but this makes everything worse.
let filteredByStatus = [];
filteredByStatus = this.items.filter((thisUser) => {
return thisUser.online_status.toLowerCase().indexOf(onlineStatus.toLowerCase()) > -1
});
//Condition can be applied if filtering is separated
let filteredBySkills = [];
filteredBySkills = this.items.filter((thisUser) => {
return thisUser.skills.some(c => this.filterArr.includes(c.id))
});
//Expecting to join results from multiple filters
return this.items = filteredByStatus.concat(filteredBySkills);
But this is not working at all. Not sure what wrong is there. I am looking for a solution that enables to join arrays of similar objects without duplicating them.
Don't think you need to join arrays for your filtering. You can use something like rxjs filter.
return from(this.items)
.pipe(
filter(user => {
return user.online_status.toLowerCase().indexOf(onlineStatus.toLowerCase()) > -1
&& user.skills.some(c => filterArr.includes(c.id));
})
);
Or if you like to split it up you can just change it to like:
return from(this.items)
.pipe(
filter(user => user.online_status.toLowerCase().indexOf(onlineStatus.toLowerCase()) > -1),
filter(user => user.skills.some(c => filterArr.includes(c.id)))
);
Stackblitz: https://stackblitz.com/edit/angular-pk3w8b
You can tweak your condition a bit and place !this.filterArr.length in your condition (in terms of OR condition AND with user status) to make your whole condition gets true so that user gets filter.

How to use OData filter in dynamic array

I am trying to filter nested array using ?$filter in odata filter
but it is not working properly
parent array got filtered but not child one.
My Array
{
"value": [
{
"Id": 1,
"Country": "India",
"language": [
{
"Lid": 1,
"State": "telengana",
"Statuelanguage": "Telgu",
"Place to visit": [
"p3","p4"
]
},
{
"Lid": 2,
"State": "Delhi",
"Statuelanguage": "Hindi",
"Place to visit": [
"p5","p6"
]
},
{
"Lid": 3,
"State": "UP",
"Statuelanguage": "Hindi",
"Place to visit": [
"p7","p8"
]
}
]
}
]
}
Expected Responce
{
"value": [
{
"Id": 1,
"Country": "India",
"language": [
{
"Lid": 1,
"State": "telengana",
"Statuelanguage": "Telgu",
"Place to visit": [
"p3","p4"
]
}
]
}
]
}
Filter query
?$filter=language/any(c: c/Lid eq 1)
but when i am trying to use the filter, it is filtering the parent one not the child
it returns all 3 child to me
So it works as expected :)
$filter parameter is used to filter collection that you're querying.
To filter expanded/related collection (language in your case) you have to use expand filter feature:
...$expand=language($filter=Lid eq 1)
BUT: It is only possible in OData v4.
ref for webapi
nested filter description

Dynamic form using AngularJS, multiple values binding

I am looking for a best approach to convert a static form to an angular dynamic form. I am not sure how to bind multiple values to the same answer.
The static page is available at: https://jsfiddle.net/hvuq5h46/
<div ng-repeat="i in items">
<select ng-model="i.answer" ng-options="o.id as o.title for o in i.answersAvailable" ng-visible="y.TYPE = 'SINGLE'"></select>
<input type="checkbox" ng-model="i.answer" ng-visible="y.TYPE = 'MULTIPLE'" />
</div>
The JSON file
[
{
"id": 1,
"title": "Are you a student?",
"type": "SINGLE",
"answersAvailable": [
{
"id": 1,
"title": "Yes"
},
{
"id": 2,
"title": "No"
}
],
"answer": [
1
]
},
{
"id": 2,
"title": "Would you like to be an astronaut?",
"type": "SINGLE",
"answersAvailable": [
{
"id": 4,
"title": "Yes"
},
{
"id": 5,
"title": "No"
},
{
"id": 6,
"title": "I am not sure"
}
],
"answer": [
4
]
},
{
"id": 3,
"title": "What is your favourite planet?",
"type": "MULTIPLE",
"answersAvailable": [
{
"id": 7,
"title": "Earth"
},
{
"id": 8,
"title": "Mars"
},
{
"id": 9,
"title": "Jupiter"
}
],
"answer": [
7,
8
]
}
]
Things would be much simpler if you can use a multiple select, but I understand it might be difficult for user to interact (consider something like md-select, which transforms multiple select into a list of checkbox for you)
Multiple select:
<select multiple
ng-model="i.answer"
ng-options="o.id as o.title for o in i.answersAvailable"
ng-if="i.type == 'MULTIPLE'"></select>
Anyway it is completely ok to use HTML checkbox. To do that we would need to bind checkbox model into the data as usual, and then update the answer array simultaneously.
ng-model="o.selected"
ng-change="updateAnswer(i)"
Also, we'll need to copy existing data to model during init.
ng-init="initMultiple(i)"
Working code:
angular.module('test', []).controller('Test', Test);
function Test($scope) {
$scope.items = [{
"id": 1,
"title": "Are you a student?",
"type": "SINGLE",
"answersAvailable": [{
"id": 1,
"title": "Yes"
},
{
"id": 2,
"title": "No"
}
],
"answer": [
1
]
},
{
"id": 2,
"title": "Would you like to be an astronaut?",
"type": "SINGLE",
"answersAvailable": [{
"id": 4,
"title": "Yes"
},
{
"id": 5,
"title": "No"
},
{
"id": 6,
"title": "I am not sure"
}
],
"answer": [
4
]
},
{
"id": 3,
"title": "What is your favourite planet?",
"type": "MULTIPLE",
"answersAvailable": [{
"id": 7,
"title": "Earth"
},
{
"id": 8,
"title": "Mars"
},
{
"id": 9,
"title": "Jupiter"
}
],
"answer": [
7,
8
]
}
]
$scope.initMultiple = function(item) {
item.answersAvailable.forEach(function(option) {
option.selected = item.answer.indexOf(option.id) != -1;
});
}
$scope.updateAnswer = function(item) {
item.answer = item.answersAvailable.filter(function(option) {
return option.selected;
})
.map(function(option) {
return option.id;
});
}
}
<script src="https://ajax.googleapis.com/ajax/libs/angularjs/1.5.8/angular.min.js"></script>
<div ng-app='test' ng-controller='Test'>
<div ng-repeat="i in items">
<select ng-model="i.answer[0]"
ng-options="o.id as o.title for o in i.answersAvailable"
ng-if="i.type == 'SINGLE'"></select>
<label ng-repeat="o in i.answersAvailable"
ng-if="i.type == 'MULTIPLE'"
ng-init="initMultiple(i)">
<input type="checkbox"
ng-model="o.selected"
ng-change="updateAnswer(i)" /> {{o.title}}
</label>
<div>{{i.answer}}</div>
</div>
</div>
Based on my experience, I will make a separation as two Angular models (or usually called services) for the form questions and another one which will collect the answers and eventually will be passed to the backend for further processing. This will provide me a flexibility to maintain both logic and presentation.
var myModule = angular.module('myModule', []);
myModule.factory('QuestionsFormService', function() {
var _question1;
var _question2;
var _question3;
function init(data){
//questions initiation
}
return init;
});
var myModule = angular.module('myModule', []);
myModule.factory('FormDataService', function() {
var _dataAnswer = {}
function init(){
//data initialization
}
function insertData(key, value){
_dataAnswer[key] = value
}
return init;
});
From the example of service models above, you need to make these available to your presentation through the Angular controller with Dependency Injection.
myModule.controller("MyCtrl", function($scope, FormDataService, QuestionsFormService) {
$scope.form_questions = QuestionsFormService.init();
$scope.form_answers = FormDataService.init()
//further logic to make these available on your view on your convenience
});
What you write on the HTML page as an Angular view is already close enough. You only need to change the binding to two models as I propose above. Thank you.

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