C program to detect the time change and reset the counter [closed] - c

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I have an inbuilt algorithm in my application. Whenever I run the algorithm, it saves that exact run time in the database. For example, if I run the algorithm at 11.00, it saves that time. And again if I run at 11.05, it saves 11.05 in the database.
I want to detect the number of times it Ran. So that once it runs for 5 times, I need to do some action like changing the values and reset the counter to 0. So that when it reaches 5 iterations, again I should reset the counter.
I am a beginner. It will be helpful if you could help me with the syntax.
MAIN
{
int temp1, temp2, flag = 0, max = 5;
temp1 = GET_INT_VALUE(8,1,84,1,0);
if flag = 0;
while(1)
{
if (templ == temp2)
flag++;
else
flag = 0;
if (flag == max)
{
//sprintf(Message,"SE value is %d",temp2);
PRINTOUT("Message");
flag = 0;
break;
}
}
}
END

Answer 1

The best way is to use a static local variable, like this:
void foo(void) {
static int counter = 0;
counter++;
if(counter > 5) {
counter = 0;
/* Do something every fifth time */
}
}
Note that you can't use a normal local variable (e.g. int counter = 0;) because its contents will be lost when the function returns. The static makes it work more like a global variable (so its value isn't lost when the function returns).