I'm newbie college student for programming studies,
so recently i have task to calculate matrix from outside files for Gauss Jordan Numeric Method, in the txt file i provide has 10 (x) and (y) data, and declare with do functions to calculate the 10 data from the txt file each for x^2, x^3, x^4, xy, x^2y
my question is : how to SUM (calculate total) each x^2, x^3 ... that was calculated by program ? i try do sum file in below and still got errors (the first argument of sum must not a scalar.)
the Fortran apps i use was Plato cc from Silverfrost.
I apologize if my english bad and my pogram looks funny.
i have 10 data in my txt looks like these :
(x) (y)
12 10
5 6
28 8
9 11
20 17
6 24
32 9
2 7
1 30
26 22
in program below i open these files and want each x and y i provide read and calculate to get x^2, x^3, x^4, xy, x^2y
Program Gauss_Jordan
Real x(10),y(10),xj,yj,xj2,xj3,xj4,xjyj,xj2yj
Open (10, file='Data.txt')
Do j = 1,10
Read(10,*) x(j), y(j)
xj2 = x(j)**2
xj3 = x(j)**3
xj4 = x(j)**4
xjyj = x(j)*y(j)
xj2yj = (x(j)**2)*y(j)
Do k = 1,10
T(xj2) = SUM( xj2, dim=1)
T(xj3) = SUM (xj3, dim=1)
T(xj4) = SUM (xj4, dim=1)
T(xjyj) = SUM (xjyj, dim=1)
T(xj2yj) = SUM (xj2yj, dim=1)
End Do
End Do
Close(10)
End
for T(xj2) I want to get one result scalar result from SUM the all xj^2 that program has been calculated.
Like in excel was expected :
(A) is 1st xj^2 value that has been calculated
.
.
.
until (J) is 10th xj^2 value that has been calculated
sxj^2 = SUM(Xj^2)
SUM (A-J)
The 'sum' intrinsic needs an array argument, which we can compute from the input arrays without using a loop, so your program could be:
Program Gauss_Jordan
Real x(10), y(10), x2(10), x3(10), x4(10), xy(10), x2y(10)
Open(10, file='Data.txt')
Do j = 1, 10
Read (10, *) x(j), y(j)
End Do
Close(10)
x2 = x**2
x3 = x**3
x4 = x**4
xy = x*y
x2y = (x**2)*y
sx2 = SUM(x2)
sx3 = SUM(x3)
sx4 = SUM(x4)
sxy = SUM(xy)
sx2y = SUM(x2y)
End
From what I see I think you are misunderstanding what the SUM intrinsic does. Since your example isn't storing xj2, xj3 etc. in arrays, SUM isn't going to be useful to you. Instead you could declare totals as scalars (as you described you wanted) and simply add the individual xj2 variables in a loop as in the example below.
Also, you should get in the habit of using the implicit none declaration. It will save you from unexpected errors due to spelling mistakes.
Program Gauss_Jordan
implicit none
Real x(10),y(10),xj,yj,xj2,xj3,xj4,xjyj,xj2yj
real :: Txj2,Txj3,Txj4,Txjyj,Txj2yj
integer :: j
Txj2 = 0
Txj3 = 0
Txj4 = 0
Txjyj= 0
Txj2yj= 0
Open (10, file='Data.txt')
Do j = 1,10
Read(10,*) x(j), y(j)
xj2 = x(j)**2
xj3 = x(j)**3
xj4 = x(j)**4
xjyj = x(j)*y(j)
xj2yj = (x(j)**2)*y(j)
Txj2 = Txj2 + xj2
Txj3 = Txj3 + xj3
Txj4 = Txj4 + xj4
Txjyj = Txjyj + xjyj
Txj2yj = Txj2yj + xj2yj
End Do
print *, 'Txj2 = ', Txj2
Close(10)
End
When I ran this I got the output below which is what I believe you intended:
3175
Related
I have the following problem in my simulation.
A is an array 24 x 2. I am going to split it and get 4 or 12 array. It means that I group 6 or 2 array. It will be ok, if I use even "split" coefficient. If it is odd, I can"t split A.[ I can't group 5 or 7, because of 24/5=4*5 + 4 ( or 5*5 -1) or 24/7=7*3+3.
That's why I going to do the following:
If I have 24 x 2 and need group every 5 together:
block 1 : A(1,:), A(2,:),A(3,:),A(4,:),A(5,:)
block 2 : A(6,:), A(7,:),A(8,:),A(9,:),A(10,:)
block 3 : A(11,:), A(12,:),A(13,:),A(14,:),A(15,:)
block 4 : A(16,:), A(17,:),A(18,:),A(19,:),A(20,:)
block 5 : A(21,:), A(22,:),A(23,:),A(24,:), ?
As you can see the 5th block is not full, Matlab gives me an error. My idea is to create A(25,:)=0. For my simulation it will be ok.
I am going to simulate it as function:
A=rand(m,n)
w- # number of a vector that i would like group together ( in ex., it is `5`)
if mod(w,2)==0
if mod(m,2)==0
% do....
else
% remainder = 0
end
else
if mod(m,2)==0
% remainder = 0
else
%do...
end
I was going to simulate like above, but then I have noticed that it doesn't work. Because 24/10 = 2*10+4. So I should write something else
I can find the reminder as r = rem(24,5). As an example above, MatLab gives me r=4. then I can find a difference c= w-r =1 and after that, I don't know how to do that.
Could you suggest to me how to simulate such a calculation?
Determine the number of blocks needed, calculate the virtual amount of rows needed to fill these blocks, and add as many zero rows to A as the difference between the virtual and actual amount of rows. Since you didn't mention, what the actual output should look like (array, cell array, ...), I chose a reshaped array.
Here's the code:
m = 24;
n = 2;
w = 5;
A = rand(m, n)
% Determine number of blocks
n_blocks = ceil(m / w);
% Add zero rows to A
A(m+1:w*n_blocks, :) = 0
% Reshape A into desired format
A = reshape(A.', size(A, 1) / n_blocks * n, n_blocks).'
The output (shortened):
A =
0.9164959 0.1373036
0.5588065 0.1303052
0.4913387 0.6540321
0.5711623 0.1937039
0.7231415 0.8142444
0.9348675 0.8623844
[...]
0.8372621 0.4571067
0.5531564 0.9138423
A =
0.91650 0.13730
0.55881 0.13031
0.49134 0.65403
0.57116 0.19370
0.72314 0.81424
0.93487 0.86238
[...]
0.83726 0.45711
0.55316 0.91384
0.00000 0.00000
A =
0.91650 0.13730 0.55881 0.13031 0.49134 0.65403 0.57116 0.19370 0.72314 0.81424
0.93487 0.86238 0.61128 0.15006 0.43861 0.07667 0.94387 0.85875 0.43247 0.03105
0.48887 0.67998 0.42381 0.77707 0.93337 0.96875 0.88552 0.43617 0.06198 0.80826
0.08087 0.48928 0.46514 0.69252 0.84122 0.77548 0.90480 0.16924 0.82599 0.82780
0.49048 0.00514 0.99615 0.42366 0.83726 0.45711 0.55316 0.91384 0.00000 0.00000
Hope that helps!
This is the script that I have. It works till the ------ separation. Under I do not get any error from Matlab, but neither do I get a return of bestDx nor bestDy. Please help. (The first part is given just to put you in context)
%%
% Variables after running script Read_eA3_file.m
%date_time_UTC
%reflectivity
%clutter_mask
%Convert units
dBZ = reflectivity * 0.375 - 30;
dBZ_Mask = clutter_mask * 0.375 - 30;
%Replace clutter values with NaN
weather = NaN(size(dBZ)); %initialise to constant
weather(dBZ>=dBZ_Mask) = dBZ(dBZ>=dBZ_Mask); %copy values when A >= B
%Reduce to range -- those are 384x384 arrays
dBZ_range = dBZ(:,:,1:16); %16:18 to 16:23 included
weather_range = weather(:,:,1:16); %16:18 to 16:23 included
weather1618 = weather(:,:,1); %16:18 map only
weather1623 = weather(:,:,16); %16:23 map only
% Plot maps
image(imrotate(-weather1618,90)); %of 16:18
image(imrotate(-weather1623,90)); %of 16:23
%Find x,y of strongest dBZ
%Since the value are all negative. I look for their minimun
[M,I] = min(weather1618(:)); %for 16:18
[I_row, I_col] = ind2sub(size(weather1618),I); %values are 255 and 143
[M2,I2] = min(weather1623(:)); %for 16:23
[I2_row, I2_col] = ind2sub(size(weather1623),I2); %values are 223 and 7
%Calc displacement
%I get a value of 139.7140
max_displ=sqrt((I2_row-I_row)^2+(I2_col-I_col)^2); %between 1618 and 1623
%%
% -----Section below does not work; ONLY RUN the section ABOVE---------
%% Find Dx Dy for max_corr between two maps
maxCoeff=0;
weather1618Modified = zeros(384,384); %create weather array for time range
%weather1618Modified(:) = {NaN}; % Matlab cannot mix cell & double
%%
for x = 1:384
for y = 1:384
%30 pixel appx.
for Dx = -max_displ:30: max_displ
for Dy = -max_displ:30: max_displ
%Limit range of x+Dx and y+Dy to 1:384
if x+Dx<1 | y+Dy<1 | x+Dx>384 | y+Dy>384
continue
%weather1618Modified is the forecasted weather1823
weather1618Modified(x+Dx,y+Dy) = weather1618(x,y)
%Find the best correlation; Is corrcoef the right formula?
newCoeff=corrcoef(weather1623,weather1618Modified);
if newCoeff>maxCoeff
maxCoeff=newCoeff;
bestDx=Dx;
bestDy=Dy;
end
end
end
end
end
end
%% Calc displacement
bestDispl = sqrt(bestDx^2+bestDy^2); %bestDispl for a 5 min frame
%Calc speed
speed = bestDispl/time;
You have to delete the continue statement after the first if (or place it somewhere else).
The continue statement makes the program skip the remaining part of the for-loop and go directly to the next iteration. Therefore bestDx and bestDy will never be set.
Documentation: https://se.mathworks.com/help/matlab/ref/continue.html
Ok, so In my program I'm supposed to take in the name of the data file from the user than open it and read the contents. But when I open and read it all that characters just end up being ****** and all the integers end up being 0. IDK if it's how I'm reading in the file or the format?
The file will contain something like this: (where the number of cities is the first number)
4
SanDiego
0
350
900
1100
Phoenix
350
0
560
604
Denver
900
560
0
389
Dallas
1100
604
389
0
So far my code is this where first I take in the first number than on every firstnumber * I + I pass is supposed to go into the character array city. Now the rest of the numbers I am storing into a integer array, but really want it into a integer matrix called d_table but I couldn't think of a way to do that immediately on the read.
PROGRAM p4
IMPLICIT NONE
INTEGER :: number, status, I, J, K, permutation = 0, distance = 0, distance = 999999
CHARACTER(50) :: filename ! Filenames longer than 50 are truncated
CHARACTER(20), DIMENSION(10) :: city
INTEGER, DIMENSION(100) :: temp
INTEGER, DIMENSION(10,10) :: d_table
INTEGER, DIMENSION(10) :: path, best_path
WRITE (*, '(1x,A)', ADVANCE="NO") "Enter filename: "
READ *, filename
! Open the file we created and read the contents
OPEN(UNIT=15, FILE=filename, STATUS="OLD", ACTION="READ",&
IOSTAT=status)
IF(status /= 0) THEN
PRINT *, "ERROR, could not open file for reading."
STOP
END IF
READ (UNIT=15, FMT = 100, IOSTAT=status) number
J = 0
K = 0
DO I = 0, number*number
IF(I == J*number+J) THEN
READ (UNIT=15, FMT = 200, IOSTAT=status) city(J)
J = J + 1
ELSE
READ (UNIT=15, FMT = 100, IOSTAT=status) temp(K)
K = K + 1
END IF
END DO
K = 0
DO I = 0, number
DO J = 0, number
d_table(I,J) = temp(K)
K = K + 1
END DO
END DO
100 FORMAT(I6)
200 FORMAT (A)
END PROGRAM p4
This line
DO I = 0, number*number
looks wonky to me; the loop will be executed 17 times. Surely you want to read number groups of 5 lines, each group being one city name followed by four integers ? That would be a good case for a little loop nest, something like
do ix = 1, number
read(15,*) city(ix)
do jx = 1, 4
read(15,*) d_table(ix,jx)
end do
end do
Given such a simple input file format there's no need to bother with format statements, list-directed input will work just fine.
I can't see the point of all the index arithmetic the code is doing, perhaps I've missed something.
I have an array with a set of chronological serial numbers and another source array with random serial numbers associated with a numeric value. The code creates a new cell array in MATLAB with the perfectly chronological serial numbers in one column and in the next column it inserts the associated numeric value if the serial numbers match in both original source arrays. If they don't the code simply copies the previous associated value until there is a new match.
j = 1;
A = {random{1:end,1}};
B = cell2mat(A);
value = random{1,2};
data = cell(length(serial), 1);
data(:,1) = serial(:,1);
h = waitbar(0,'Please Wait...');
steps = length(serial);
for k = 1:length(serial)
[row1, col1, vec1] = find(B == serial{k,1});
tf1 = isempty(vec1);
if (tf1 == 0)
prices = random{col1,2};
data(j,2) = num2cell(value);
j = j + 1;
else
data(j,2) = num2cell(value);
j = j + 1;
end
waitbar(k/steps,h,['Please Wait... ' num2str(k/steps*100) ' %'])
end
close(h);
Right now, the run-time for the code is approximately 4 hours. I would like to make this code run faster. Please suggest any methods to do so.
UPDATE
source input (serial)
1
2
3
4
5
6
7
source input (random)
1 100
2 105
4 106
7 107
desired output (data)
SR No Value
1 100
2 105
3 105
4 106
5 106
6 106
7 107
Firstly, run the MATLAB profiler (see 'doc profile') and see where the bulk of the execution time is occuring.
Secondly, don't update the waitbar on every iteration> Particularly if serial contains a large (> 100) number of elements.
Do something like:
if (mod(k, 100)==0) % update on every 100th iteration
waitbar(k/steps,h,['Please Wait... ' num2str(k/steps*100) ' %'])
end
Some points:
Firstly it would help a lot if you gave us some sample input and output data.
Why do you initialize data as one column and then fill it's second in the loop? Rather initialize it as 2 columns upfront: data = cell(length(serial), 2);
Is j ever different from k, they look identical to me and you could just drop both the j = j + 1 lines.
tf1 = isempty(vec1); if (tf1 == 0)... is the same as the single line: if (!isempty(vec1)) or even better if(isempty(vec1)) and then swap the code from your else and your if.
But I think you can probably find a fast vecotrized solution if you provide some (short) sample input and output data.
I have the following code
B=[1 2 3; 10 20 30 ; 100 200 300 ; 500 600 800];
A=[100; 500; 300 ; 425];
SA = sum(A);
V={}; % number of rows for cell V = num of combinations -- column = 1
n = 1;
arr = zeros(1,length(B))
for k = 1:length(B)
for idx = nchoosek(1:numel(B), k)'
rows = mod(idx, length(B))
if ~isequal(rows, unique(rows)) %if rows not equal to unique(rows)
continue %combination possibility valid
end %Ignore the combination if there are two elements from the same row
B_subset = B(idx)
if (SA + sum(B_subset) <= 3000) %if sum of A + (combination) < 3000
rows( rows==0 )=4
arr(rows) = B_subset(:)
V(n,1) = {arr}
n = n + 1
arr = zeros(1,length(B))
end
end
end
The combinations are supposed to be valid if the sum of A and some values of B are less than 3000.
Problem with my code is, the last value of B, B(3,3), is only accounted for once in the code.
If you run the code, you will notice one cell of V containing [0;0;0;800] at row 12. But there are other combinations possible as well such as [1;0;0;800]. Where SA + (1 + 800) < 3000 , however the code does not print this possibility.
I cannot figure out why, can someone please help me debug this and find out why some combinations are skipped ? especially B(3,3) ?
I suspect that this line is not doing exactly what you intended:
if ~isequal(rows, unique(rows))
Instead, try this:
if ~isequal(length(rows), length(unique(rows)))