I have written a program to find the longest word in the input. I get no errors when using valgrind or running tests locally, but the grading program I email the code to reports a segmentation fault.
int main(void)
{
char *longest = malloc(1);
size_t size = 1;
do {
char word[20];
if (scanf("%s", word) > 0) {
if (strlen(word) > size) {
longest = realloc(longest,strlen(word)+1);
strcpy(longest,word);
size = strlen(word);
}
}
} while (getchar() != EOF);
printf("%zu characters in longest word: %s\n", strlen(longest),longest);
free(longest);
return 0;
}
Your problem is in the line char word[20]; and the way scanf reads words. From scanf's point of view, a word is any sequence of non-spaces. For example, realloc(longest,strlen(word)+1); is treated as one word, and that alone is longer than 20 characters.
You should use a more robust function to read words and allocate space for them. The most cost-efficient solution is getline() for reading the line followed by strsep() for extracting words.
Without relying on the luxurities of POSIX-functions, only standard-C for variable word-length:
#include <assert.h> // assert()
#include <stddef.h> // size_t
#include <stdbool.h> // bool, true, false
#include <stdlib.h> // EXIT_FAILURE, realloc(), free()
#include <stdio.h> // fscanf(), fgetc(), ungetc(), printf(), fputs()
#include <ctype.h> // isspace()
#include <string.h> // strlen(), strcat(), strcpy()
#define WORD_BUFFER_SIZE 20
#define STRING(value) #value
#define STRINGIFY(value) STRING(value)
// reads and discards whitespace, returns false on EOF
bool skip_ws(FILE *stream)
{
int ch;
while ((ch = fgetc(stream)) != EOF && isspace(ch));
if(!isspace(ch) && ch != EOF) // if it was not whitespace and not EOF
ungetc(ch, stream); // pretend we were never here.
return ch != EOF;
}
bool read_word(char **dst, FILE *stream)
{
assert(dst);
char chunk_buffer[WORD_BUFFER_SIZE + 1];
if (!skip_ws(stream)) // if we encounter EOF before any other non-whitespace
return false;
// read chunk by chunk
for (size_t i = 0; fscanf(stream, "%" STRINGIFY(WORD_BUFFER_SIZE) "s", chunk_buffer) == 1; ++i)
{
size_t chunk_length = strlen(chunk_buffer);
// adjust *dst's size
char *tmp = realloc(*dst, (i * WORD_BUFFER_SIZE + chunk_length + 1) * sizeof(*tmp));
if (!tmp) {
free(*dst);
*dst = NULL;
return false;
}
*dst = tmp;
if (i == 0) // zero terminate it if it is the first junk
**dst = '\0'; // for strcat() to behave well.
strcat(*dst, chunk_buffer); // add the current chunk to *dst.
int next_char = fgetc(stream);
ungetc(next_char, stream);
if (chunk_length < WORD_BUFFER_SIZE || isspace(next_char) || next_char == EOF)
return true;
}
return true;
}
int main(void)
{
char *word = NULL;
char *longest_word = NULL;
size_t longest_length = 0;
while (read_word(&word, stdin)) {
size_t length = strlen(word);
if (length > longest_length) {
char *tmp = realloc(longest_word, (length + 1) * sizeof *tmp);
if (!tmp) {
fputs("Not enough memory. :(\n\n", stderr);
free(longest_word);
free(word);
return EXIT_FAILURE;
}
longest_length = length;
longest_word = tmp;
strcpy(longest_word, word);
}
}
free(word);
printf("%zu characters in the longest word: \"%s\"\n\n", longest_length, longest_word);
free(longest_word);
}
Related
My program needs to print longest word which contains only letters from a file.
#include <stdio.h>
#include <stdlib.h>
#include <string.h>
#include <ctype.h>
int checkString(const char s[]) {
unsigned char c;
while ((c = *s) && (isalpha(c) || isblank(c)))
++s;
return *s == '\0';
}
int main() {
char file_name[]="document.txt";
FILE *fp = fopen(file_name, "r");
char *largest = str;
int largest_len = 0;
while (fgets(file_name, 1000, fp) != NULL) {
char *temp = strtok(file_name, " ");
while (temp != NULL) {
if (strlen(temp) > largest_len) {
strcpy(largest, temp);
largest_len = strlen(largest);
}
temp = strtok(NULL, "\",.,1,2,4,5,6,7,8,9 ");
}
}
if(checkString(largest))
printf("%s", largest);
fclose(fp);
return 0;
}
In my code, if the largest word contains only letters it will be printed. How to modify this code to check next words if the largest doesn't contain only letters?
First of all, you cannot store the pointer to longest word like that. You re-use str for the next line and so the pointer is not likely to point to something useful.
Second, while strtok() appears simple, initially, I tend to apply a straightforward approach to a straightforward problem.
The problem is O(n) (where n is the length of the document). You just need to go through it character by character. Of course, since every line is ended by a \n, you can use the line based approach in this case.
So, instead of strtok, simply check each character, if it is a legal word character (an alphanumeric character, that is). You can easily do so with the standard library function isalpha() from header ctype.h.
Below is the program, copying the longest string into a dedicated buffer, using isalpha() and doing the line based reading of the file, just like the code in the original question did.
Of course, this code assumes, no line is ever longer than 999 characters.
#include <stdio.h>
#include <stdlib.h>
#include <string.h>
#include <stdint.h>
#include <ctype.h>
static size_t gulp(const char* line, size_t istart, size_t len) {
size_t n = 0;
for (size_t i = istart; i < len; i++, n++) {
if (!isalpha(line[i])) {
break;
}
}
return n;
}
int main(int argc, const char * argv[]) {
FILE* f = fopen("document.txt","r");
char line[1000];
char longest_word[1000];
size_t longest_word_length = 0;
while (fgets(line, sizeof(line), f) != NULL) {
size_t i0 = 0;
size_t line_length = strlen(line);
while (i0 < line_length) {
if (isalpha(line[i0])) {
size_t n = gulp(line, i0, line_length);
if (n > longest_word_length) {
strncpy(longest_word, &line[i0], n);
longest_word[n] = '\0';
longest_word_length = n;
}
i0 = i0 + n;
} else {
i0++;
}
}
}
fclose(f);
f = NULL;
if (longest_word_length > 0) {
printf("longest word: %s (%lu characters)\n",
longest_word, longest_word_length);
}
return 0;
}
There are a number of problems here:
you use the same buffer (str) for two different uses: as a read buffer and to store the longest word. If you find the largest word in the first line, the word will be erased when reading the second line. Furthemore, if you find a rather long word at the beginning of a line, the strings pointed to by largest and temp could overlap which leads to undefined behaviour => use a different array or strdup (and free) for largest
you only use the space as possible separator. You should wonder whether you should add tab and/or punctuations
once you have got a word you should ensure that it only contains valid letters before testing its length and ignore it if for example it contains digits.
if a single line can be longer than 1000 characters, you should wrap the end of the current part before the beginning of the next one for the possible case where a long word would be splitted there.
For additional corner case processing, you should specify what to do if a word contains illegal characters but only at one side. For example if . is not used as a word delimiter, a word with an embedded . like "a.b" should be ignored, but a terminating . should only be stripped (like "example." should become "example"
I think the order you do things should be a bit different, here is an example
#include <stdio.h>
#include <stdlib.h>
#include <ctype.h>
#include <string.h>
int isCandidate(char* word);
int main(int argc, char* argv[])
{
if (--argc == 0)
{
perror("not enough command line arguments, expecting a filename");
return -1;
}
++argv;
FILE* fp = fopen(*argv, "r");
if (fp == NULL)
{
perror(*argv);
return -1;
}
// get size of file
fseek(fp, 0L, SEEK_END);
long fileLength = ftell(fp);
if (fileLength < 1)
{
perror("file is empty");
return -1;
}
fseek(fp, 0L, SEEK_SET); // position file pointer at the beginning again
// allocate space for the whole file and then read it in
// for a text file it should be OK to do so since they
// normally are not that large.
char* buffer = malloc(fileLength+1);
if (fread(buffer, 1, fileLength, fp) != 0)
{
buffer[fileLength] = '\0'; // make sure the buffer ends with \0
}
else
{
perror("Failed reading into buffer");
return -1;
}
fclose(fp); // we are done with the file
const char filter[] = " \n\r";
char* longestWord = malloc(fileLength+1); // max length in theory
long unsigned int maxLength = 0;
for (char* token = strtok(buffer, filter); token != NULL; token = strtok(NULL, filter))
{
if (isCandidate(token))
{
if (strlen(token) > maxLength)
{
strcpy(longestWord, token);
maxLength = strlen(token);
}
}
}
printf("Longest word:'%s', len=%lu\n", longestWord, maxLength);
free(longestWord);
free(buffer);
}
int isCandidate(char* word)
{
if (word == NULL)
{
perror("invalid argument to isCandidate");
return 0;
}
for (char* ch = word; *ch; ++ch)
{
if (!isalpha(*ch)) return 0;
}
return 1;
}
So I am trying to read input from a text file and print the exact same thing I read in C.So this below is the input followed by enter:
input: Hi
output: Hi
#include <stdio.h>
#include <stdlib.h>
char *inputString(FILE *fp, size_t size) {
//The size is extended by the input with the value of the provisional
char *str;
int ch;
size_t len = 0;
str = realloc(NULL, sizeof(char) * size); //size is start size
if (!str)
return str;
while (EOF != (ch = fgetc(fp)) && ch != '\n') {
str[len++] = ch;
if (len == size) {
str = realloc(str, sizeof(char) * (size += 16));
if (!str)
return str;
}
}
str[len++] = '\0';
return realloc(str, sizeof(char) * len);
}
int main(void) {
char *m;
// printf("input string : ");
m = inputString(stdin, 10);
printf("%s\n", m);
free(m);
return 0;
}
For this input:
Hi, this is the first line
This is the second line
This is the third line \n
This is the output I expected:
Hi, this is the first line
This is the second line
This is the third line \n
This is what I got:
Hi, this is the first line
It makes sense that the code is printing only the first line, but since the condition in the guard will no longer be true after hitting the new line, but I don't know how to structure my code so it reads line by line and prints them respectively.
If you want the code to read each line, remove && ch != '\n' from the condition of the while loop.
Also, the code is reading from stdin instead of a file. Use fopen to read from a file, i.e. m = inputString(fopen("filename.txt", "r"), 512).
Try this,
#include<stdio.h>
void main(int argc, char **argv)
{
int cnt=0;
char buf[1024];
FILE *fptr=stdin;
printf("Input: \n");
char ch=fgetc(fptr);
buf[cnt++]=ch;
while(ch!='$')
{
buf[cnt++]=ch;
ch=fgetc(fptr);
}
buf[cnt++]='$';
buf[cnt]='\0';
printf("Output:\n");
fputs(buf,stdout);
fclose(fptr);
}
I have put '$' as the delimiter.
I have used an extra buffer as newline is bound to EOF for stdin. So if I print out the character immediately it comes out of loop.
All you need is repeat the process as long as you can read lines:
int main(void) {
char *m;
// printf("input strings: ");
while ((m = inputString(stdin, 10)) != NULL) {
printf("%s\n", m);
free(m);
}
return 0;
}
For this to work correctly, you must return NULL at end of file:
#include <stdio.h>
#include <stdlib.h>
char *inputString(FILE *fp, size_t size) {
//The size is extended by the input with the value of the provisional
int ch;
size_t len = 0;
char *str = malloc(size);
if (str == NULL)
return NULL;
while ((ch = fgetc(fp)) != EOF && c != '\n') {
if (len + 2 > size) {
char *new_str = realloc(str, size += 16);
if (!new_str) {
free(str);
return NULL;
str = new_str;
}
str[len++] = ch;
}
if (c == EOF && len == 0) {
/* at end of file */
free(str);
return NULL;
}
str[len++] = '\0';
return realloc(str, len);
}
Instead of:
while(EOF!=(ch=fgetc(fp))&& ch != '\n' ){
// stuff
}
you could do:
while(EOF!=(ch=fgetc(fp))){
// stuff
if (ch == '\n') break;
}
Now you have consumed the newline.
If I don't know how long the word is, I cannot write char m[6];,
The length of the word is maybe ten or twenty long.
How can I use scanf to get input from the keyboard?
#include <stdio.h>
int main(void)
{
char m[6];
printf("please input a string with length=5\n");
scanf("%s",&m);
printf("this is the string: %s\n", m);
return 0;
}
please input a string with length=5
input: hello
this is the string: hello
Enter while securing an area dynamically
E.G.
#include <stdio.h>
#include <stdlib.h>
char *inputString(FILE* fp, size_t size){
//The size is extended by the input with the value of the provisional
char *str;
int ch;
size_t len = 0;
str = realloc(NULL, sizeof(*str)*size);//size is start size
if(!str)return str;
while(EOF!=(ch=fgetc(fp)) && ch != '\n'){
str[len++]=ch;
if(len==size){
str = realloc(str, sizeof(*str)*(size+=16));
if(!str)return str;
}
}
str[len++]='\0';
return realloc(str, sizeof(*str)*len);
}
int main(void){
char *m;
printf("input string : ");
m = inputString(stdin, 10);
printf("%s\n", m);
free(m);
return 0;
}
With the computers of today, you can get away with allocating very large strings (hundreds of thousands of characters) while hardly making a dent in the computer's RAM usage. So I wouldn't worry too much.
However, in the old days, when memory was at a premium, the common practice was to read strings in chunks. fgets reads up to a maximum number of chars from the input, but leaves the rest of the input buffer intact, so you can read the rest from it however you like.
in this example, I read in chunks of 200 chars, but you can use whatever chunk size you want of course.
#include <stdio.h>
#include <stdlib.h>
#include <string.h>
char* readinput()
{
#define CHUNK 200
char* input = NULL;
char tempbuf[CHUNK];
size_t inputlen = 0, templen = 0;
do {
fgets(tempbuf, CHUNK, stdin);
templen = strlen(tempbuf);
input = realloc(input, inputlen+templen+1);
strcpy(input+inputlen, tempbuf);
inputlen += templen;
} while (templen==CHUNK-1 && tempbuf[CHUNK-2]!='\n');
return input;
}
int main()
{
char* result = readinput();
printf("And the result is [%s]\n", result);
free(result);
return 0;
}
Note that this is a simplified example with no error checking; in real life you will have to make sure the input is OK by verifying the return value of fgets.
Also note that at the end if the readinput routine, no bytes are wasted; the string has the exact memory size it needs to have.
I've seen only one simple way of reading an arbitrarily long string, but I've never used it. I think it goes like this:
char *m = NULL;
printf("please input a string\n");
scanf("%ms",&m);
if (m == NULL)
fprintf(stderr, "That string was too long!\n");
else
{
printf("this is the string %s\n",m);
/* ... any other use of m */
free(m);
}
The m between % and s tells scanf() to measure the string and allocate memory for it and copy the string into that, and to store the address of that allocated memory in the corresponding argument. Once you're done with it you have to free() it.
This isn't supported on every implementation of scanf(), though.
As others have pointed out, the easiest solution is to set a limit on the length of the input. If you still want to use scanf() then you can do so this way:
char m[100];
scanf("%99s",&m);
Note that the size of m[] must be at least one byte larger than the number between % and s.
If the string entered is longer than 99, then the remaining characters will wait to be read by another call or by the rest of the format string passed to scanf().
Generally scanf() is not recommended for handling user input. It's best applied to basic structured text files that were created by another application. Even then, you must be aware that the input might not be formatted as you expect, as somebody might have interfered with it to try to break your program.
There is a new function in C standard for getting a line without specifying its size. getline function allocates string with required size automatically so there is no need to guess about string's size. The following code demonstrate usage:
#include <stdio.h>
#include <stdlib.h>
int main(void)
{
char *line = NULL;
size_t len = 0;
ssize_t read;
while ((read = getline(&line, &len, stdin)) != -1) {
printf("Retrieved line of length %zu :\n", read);
printf("%s", line);
}
if (ferror(stdin)) {
/* handle error */
}
free(line);
return 0;
}
If I may suggest a safer approach:
Declare a buffer big enough to hold the string:
char user_input[255];
Get the user input in a safe way:
fgets(user_input, 255, stdin);
A safe way to get the input, the first argument being a pointer to a buffer where the input will be stored, the second the maximum input the function should read and the third is a pointer to the standard input - i.e. where the user input comes from.
Safety in particular comes from the second argument limiting how much will be read which prevents buffer overruns. Also, fgets takes care of null-terminating the processed string.
More info on that function here.
EDIT: If you need to do any formatting (e.g. convert a string to a number), you can use atoi once you have the input.
Safer and faster (doubling capacity) version:
char *readline(char *prompt) {
size_t size = 80;
char *str = malloc(sizeof(char) * size);
int c;
size_t len = 0;
printf("%s", prompt);
while (EOF != (c = getchar()) && c != '\r' && c != '\n') {
str[len++] = c;
if(len == size) str = realloc(str, sizeof(char) * (size *= 2));
}
str[len++]='\0';
return realloc(str, sizeof(char) * len);
}
Read directly into allocated space with fgets().
Special care is need to distinguish a successful read, end-of-file, input error and out-of memory. Proper memory management needed on EOF.
This method retains a line's '\n'.
#include <stdio.h>
#include <stdlib.h>
#define FGETS_ALLOC_N 128
char* fgets_alloc(FILE *istream) {
char* buf = NULL;
size_t size = 0;
size_t used = 0;
do {
size += FGETS_ALLOC_N;
char *buf_new = realloc(buf, size);
if (buf_new == NULL) {
// Out-of-memory
free(buf);
return NULL;
}
buf = buf_new;
if (fgets(&buf[used], (int) (size - used), istream) == NULL) {
// feof or ferror
if (used == 0 || ferror(istream)) {
free(buf);
buf = NULL;
}
return buf;
}
size_t length = strlen(&buf[used]);
if (length + 1 != size - used) break;
used += length;
} while (buf[used - 1] != '\n');
return buf;
}
Sample usage
int main(void) {
FILE *istream = stdin;
char *s;
while ((s = fgets_alloc(istream)) != NULL) {
printf("'%s'", s);
free(s);
fflush(stdout);
}
if (ferror(istream)) {
puts("Input error");
} else if (feof(istream)) {
puts("End of file");
} else {
puts("Out of memory");
}
return 0;
}
I know that I have arrived after 4 years and am too late but I think I have another way that someone can use. I had used getchar() Function like this:-
#include <stdio.h>
#include <stdlib.h>
#include <string.h>
//I had putten the main Function Bellow this function.
//d for asking string,f is pointer to the string pointer
void GetStr(char *d,char **f)
{
printf("%s",d);
for(int i =0;1;i++)
{
if(i)//I.e if i!=0
*f = (char*)realloc((*f),i+1);
else
*f = (char*)malloc(i+1);
(*f)[i]=getchar();
if((*f)[i] == '\n')
{
(*f)[i]= '\0';
break;
}
}
}
int main()
{
char *s =NULL;
GetStr("Enter the String:- ",&s);
printf("Your String:- %s \nAnd It's length:- %lu\n",s,(strlen(s)));
free(s);
}
here is the sample run for this program:-
Enter the String:- I am Using Linux Mint XFCE 18.2 , eclispe CDT and GCC7.2 compiler!!
Your String:- I am Using Linux Mint XFCE 18.2 , eclispe CDT and GCC7.2 compiler!!
And It's length:- 67
Take a character pointer to store required string.If you have some idea about possible size of string then use function
char *fgets (char *str, int size, FILE* file);
else you can allocate memory on runtime too using malloc() function which dynamically provides requested memory.
i also have a solution with standard inputs and outputs
#include<stdio.h>
#include<malloc.h>
int main()
{
char *str,ch;
int size=10,len=0;
str=realloc(NULL,sizeof(char)*size);
if(!str)return str;
while(EOF!=scanf("%c",&ch) && ch!="\n")
{
str[len++]=ch;
if(len==size)
{
str = realloc(str,sizeof(char)*(size+=10));
if(!str)return str;
}
}
str[len++]='\0';
printf("%s\n",str);
free(str);
}
I have a solution using standard libraries of C and also creating a string type (alias of char*) like in C++
#include <stdio.h>
#include <stdlib.h>
#include <string.h>
typedef char* string;
typedef struct __strstr {
char ch;
struct __strstr *next;
}Strstr;
void get_str(char **str) {
char ch, *buffer, a;
Strstr *new = NULL;
Strstr *head = NULL, *tmp = NULL;
int c = 0, k = 0;
while ((ch = getchar()) != '\n') {
new = malloc(sizeof(Strstr));
if(new == NULL) {
printf("\nError!\n");
exit(1);
}
new->ch = ch;
new->next = NULL;
new->next = head;
head = new;
}
tmp = head;
while (tmp != NULL) {
c++;
tmp = tmp->next;
}
if(c == 0) {
*str = "";
} else {
buffer = malloc(sizeof(char) * (c + 1));
*str = malloc(sizeof(char) * (c + 1));
if(buffer == NULL || *str == NULL) {
printf("\nError!\n");
exit(1);
}
tmp = head;
while (tmp != NULL) {
buffer[k] = tmp->ch;
k++;
tmp = tmp->next;
}
buffer[k] = '\0';
for (int i = 0, j = strlen(buffer)-1; i < j; i++, j--) {
a = buffer[i];
buffer[i] = buffer[j];
buffer[j] = a;
}
strcpy(*str, buffer);
// Dealloc
free(buffer);
while (head != NULL) {
tmp = head;
head = head->next;
free(tmp);
}
}
}
int main() {
string str;
printf("Enter text: ");
get_str(&str);
printf("%s\n", str);
return 0;
}
If I don't know how long the word is, I cannot write char m[6];,
The length of the word is maybe ten or twenty long.
How can I use scanf to get input from the keyboard?
#include <stdio.h>
int main(void)
{
char m[6];
printf("please input a string with length=5\n");
scanf("%s",&m);
printf("this is the string: %s\n", m);
return 0;
}
please input a string with length=5
input: hello
this is the string: hello
Enter while securing an area dynamically
E.G.
#include <stdio.h>
#include <stdlib.h>
char *inputString(FILE* fp, size_t size){
//The size is extended by the input with the value of the provisional
char *str;
int ch;
size_t len = 0;
str = realloc(NULL, sizeof(*str)*size);//size is start size
if(!str)return str;
while(EOF!=(ch=fgetc(fp)) && ch != '\n'){
str[len++]=ch;
if(len==size){
str = realloc(str, sizeof(*str)*(size+=16));
if(!str)return str;
}
}
str[len++]='\0';
return realloc(str, sizeof(*str)*len);
}
int main(void){
char *m;
printf("input string : ");
m = inputString(stdin, 10);
printf("%s\n", m);
free(m);
return 0;
}
With the computers of today, you can get away with allocating very large strings (hundreds of thousands of characters) while hardly making a dent in the computer's RAM usage. So I wouldn't worry too much.
However, in the old days, when memory was at a premium, the common practice was to read strings in chunks. fgets reads up to a maximum number of chars from the input, but leaves the rest of the input buffer intact, so you can read the rest from it however you like.
in this example, I read in chunks of 200 chars, but you can use whatever chunk size you want of course.
#include <stdio.h>
#include <stdlib.h>
#include <string.h>
char* readinput()
{
#define CHUNK 200
char* input = NULL;
char tempbuf[CHUNK];
size_t inputlen = 0, templen = 0;
do {
fgets(tempbuf, CHUNK, stdin);
templen = strlen(tempbuf);
input = realloc(input, inputlen+templen+1);
strcpy(input+inputlen, tempbuf);
inputlen += templen;
} while (templen==CHUNK-1 && tempbuf[CHUNK-2]!='\n');
return input;
}
int main()
{
char* result = readinput();
printf("And the result is [%s]\n", result);
free(result);
return 0;
}
Note that this is a simplified example with no error checking; in real life you will have to make sure the input is OK by verifying the return value of fgets.
Also note that at the end if the readinput routine, no bytes are wasted; the string has the exact memory size it needs to have.
I've seen only one simple way of reading an arbitrarily long string, but I've never used it. I think it goes like this:
char *m = NULL;
printf("please input a string\n");
scanf("%ms",&m);
if (m == NULL)
fprintf(stderr, "That string was too long!\n");
else
{
printf("this is the string %s\n",m);
/* ... any other use of m */
free(m);
}
The m between % and s tells scanf() to measure the string and allocate memory for it and copy the string into that, and to store the address of that allocated memory in the corresponding argument. Once you're done with it you have to free() it.
This isn't supported on every implementation of scanf(), though.
As others have pointed out, the easiest solution is to set a limit on the length of the input. If you still want to use scanf() then you can do so this way:
char m[100];
scanf("%99s",&m);
Note that the size of m[] must be at least one byte larger than the number between % and s.
If the string entered is longer than 99, then the remaining characters will wait to be read by another call or by the rest of the format string passed to scanf().
Generally scanf() is not recommended for handling user input. It's best applied to basic structured text files that were created by another application. Even then, you must be aware that the input might not be formatted as you expect, as somebody might have interfered with it to try to break your program.
There is a new function in C standard for getting a line without specifying its size. getline function allocates string with required size automatically so there is no need to guess about string's size. The following code demonstrate usage:
#include <stdio.h>
#include <stdlib.h>
int main(void)
{
char *line = NULL;
size_t len = 0;
ssize_t read;
while ((read = getline(&line, &len, stdin)) != -1) {
printf("Retrieved line of length %zu :\n", read);
printf("%s", line);
}
if (ferror(stdin)) {
/* handle error */
}
free(line);
return 0;
}
If I may suggest a safer approach:
Declare a buffer big enough to hold the string:
char user_input[255];
Get the user input in a safe way:
fgets(user_input, 255, stdin);
A safe way to get the input, the first argument being a pointer to a buffer where the input will be stored, the second the maximum input the function should read and the third is a pointer to the standard input - i.e. where the user input comes from.
Safety in particular comes from the second argument limiting how much will be read which prevents buffer overruns. Also, fgets takes care of null-terminating the processed string.
More info on that function here.
EDIT: If you need to do any formatting (e.g. convert a string to a number), you can use atoi once you have the input.
Safer and faster (doubling capacity) version:
char *readline(char *prompt) {
size_t size = 80;
char *str = malloc(sizeof(char) * size);
int c;
size_t len = 0;
printf("%s", prompt);
while (EOF != (c = getchar()) && c != '\r' && c != '\n') {
str[len++] = c;
if(len == size) str = realloc(str, sizeof(char) * (size *= 2));
}
str[len++]='\0';
return realloc(str, sizeof(char) * len);
}
Read directly into allocated space with fgets().
Special care is need to distinguish a successful read, end-of-file, input error and out-of memory. Proper memory management needed on EOF.
This method retains a line's '\n'.
#include <stdio.h>
#include <stdlib.h>
#define FGETS_ALLOC_N 128
char* fgets_alloc(FILE *istream) {
char* buf = NULL;
size_t size = 0;
size_t used = 0;
do {
size += FGETS_ALLOC_N;
char *buf_new = realloc(buf, size);
if (buf_new == NULL) {
// Out-of-memory
free(buf);
return NULL;
}
buf = buf_new;
if (fgets(&buf[used], (int) (size - used), istream) == NULL) {
// feof or ferror
if (used == 0 || ferror(istream)) {
free(buf);
buf = NULL;
}
return buf;
}
size_t length = strlen(&buf[used]);
if (length + 1 != size - used) break;
used += length;
} while (buf[used - 1] != '\n');
return buf;
}
Sample usage
int main(void) {
FILE *istream = stdin;
char *s;
while ((s = fgets_alloc(istream)) != NULL) {
printf("'%s'", s);
free(s);
fflush(stdout);
}
if (ferror(istream)) {
puts("Input error");
} else if (feof(istream)) {
puts("End of file");
} else {
puts("Out of memory");
}
return 0;
}
I know that I have arrived after 4 years and am too late but I think I have another way that someone can use. I had used getchar() Function like this:-
#include <stdio.h>
#include <stdlib.h>
#include <string.h>
//I had putten the main Function Bellow this function.
//d for asking string,f is pointer to the string pointer
void GetStr(char *d,char **f)
{
printf("%s",d);
for(int i =0;1;i++)
{
if(i)//I.e if i!=0
*f = (char*)realloc((*f),i+1);
else
*f = (char*)malloc(i+1);
(*f)[i]=getchar();
if((*f)[i] == '\n')
{
(*f)[i]= '\0';
break;
}
}
}
int main()
{
char *s =NULL;
GetStr("Enter the String:- ",&s);
printf("Your String:- %s \nAnd It's length:- %lu\n",s,(strlen(s)));
free(s);
}
here is the sample run for this program:-
Enter the String:- I am Using Linux Mint XFCE 18.2 , eclispe CDT and GCC7.2 compiler!!
Your String:- I am Using Linux Mint XFCE 18.2 , eclispe CDT and GCC7.2 compiler!!
And It's length:- 67
Take a character pointer to store required string.If you have some idea about possible size of string then use function
char *fgets (char *str, int size, FILE* file);
else you can allocate memory on runtime too using malloc() function which dynamically provides requested memory.
i also have a solution with standard inputs and outputs
#include<stdio.h>
#include<malloc.h>
int main()
{
char *str,ch;
int size=10,len=0;
str=realloc(NULL,sizeof(char)*size);
if(!str)return str;
while(EOF!=scanf("%c",&ch) && ch!="\n")
{
str[len++]=ch;
if(len==size)
{
str = realloc(str,sizeof(char)*(size+=10));
if(!str)return str;
}
}
str[len++]='\0';
printf("%s\n",str);
free(str);
}
I have a solution using standard libraries of C and also creating a string type (alias of char*) like in C++
#include <stdio.h>
#include <stdlib.h>
#include <string.h>
typedef char* string;
typedef struct __strstr {
char ch;
struct __strstr *next;
}Strstr;
void get_str(char **str) {
char ch, *buffer, a;
Strstr *new = NULL;
Strstr *head = NULL, *tmp = NULL;
int c = 0, k = 0;
while ((ch = getchar()) != '\n') {
new = malloc(sizeof(Strstr));
if(new == NULL) {
printf("\nError!\n");
exit(1);
}
new->ch = ch;
new->next = NULL;
new->next = head;
head = new;
}
tmp = head;
while (tmp != NULL) {
c++;
tmp = tmp->next;
}
if(c == 0) {
*str = "";
} else {
buffer = malloc(sizeof(char) * (c + 1));
*str = malloc(sizeof(char) * (c + 1));
if(buffer == NULL || *str == NULL) {
printf("\nError!\n");
exit(1);
}
tmp = head;
while (tmp != NULL) {
buffer[k] = tmp->ch;
k++;
tmp = tmp->next;
}
buffer[k] = '\0';
for (int i = 0, j = strlen(buffer)-1; i < j; i++, j--) {
a = buffer[i];
buffer[i] = buffer[j];
buffer[j] = a;
}
strcpy(*str, buffer);
// Dealloc
free(buffer);
while (head != NULL) {
tmp = head;
head = head->next;
free(tmp);
}
}
}
int main() {
string str;
printf("Enter text: ");
get_str(&str);
printf("%s\n", str);
return 0;
}
I need a version of read line that is memory save. I have this "working" solution. But I'm not sure how it behaves with memory. When I enable free(text) it works for a few lines and then I get an error. So now neither text nor result is ever freed although I malloc text. Is that correct ? And why is that so ?
#include <stdio.h>
#include <stdlib.h>
#include <string.h>
char* readFromIn()
{
char* text = malloc(1024);
char* result = fgets(text, 1024, stdin);
if (result[strlen(result) - 1] == 10)
result[strlen(result) - 1] = 0;
//free(text);
return result;
}
I have A LOT of short lines to read with this and I also need stdin to be replaceable with a FILE* handle. There is no need for me to realloc text because I have only short lines.
fgets returns a pointer to the string, so after the fgets line, result will be the same memory address as text. Then when you call free (text); you are returning invalid memory.
You should free the memory in the calling function when you have finished with result
You could also avoid the malloc/free stuff by structuring your code to pass a buffer something like this:
void parent_function ()
{
char *buffer[1024];
while (readFromIn(buffer)) {
// Process the contents of buffer
}
}
char *readFromIn(char *buffer)
{
char *result = fgets(buffer, 1024, stdin);
int len;
// fgets returns NULL on error of end of input,
// in which case buffer contents will be undefined
if (result == NULL) {
return NULL;
}
len = strlen (buffer);
if (len == 0) {
return NULL;
}
if (buffer[len - 1] == '\n') {
buffer[len - 1] = 0;
return buffer;
}
Trying to avoid the malloc/free is probably wise if you are dealing with many small, short lived items so that the memory doesn't get fragmented and it should faster as well.
char *fgets(char *s, int size, FILE *stream) reads in at most one less than size characters from stream and stores them into the buffer pointed to by s. Reading stops after an EOF or a newline. If a newline is read, it is stored into the buffer. A terminating null byte ('\0') is stored after the last character in the buffer.
Return Value: returns s on success, and NULL on error or when end of file occurs while no characters have been read.
So there are 2 critical problems with your code:
You don't check the return value of fgets
You want to deallocate the memory, where this string is stored and return a pointer to this memory. Accessing the memory, where such a pointer (dangling pointer) points to, leads to undefined behaviour.
Your function could look like this:
public char* readFromIn() {
char* text = malloc(1024);
if (fgets(text, 1024, stdin) != NULL) {
int textLen = strlen(text);
if (textLen > 0 && text[textLen - 1] == '\n')
text[textLen - 1] == '\0'; // getting rid of newline character
return text;
}
else {
free(text);
return NULL;
}
}
and then caller of this function should be responsible for deallocating the memory that return value of this function points to.
I know you mentioned that the lines are only short, but none of the solutions provided will work for lines greater than 1024 in length. It is for this reason that I provide a solution which will attempt to read entire lines, and resize the buffer when there's not enough space.
#include <stdio.h>
#include <stdlib.h>
#include <string.h>
#define MINIMUM_CAPACITY 16
size_t read_line(char **buffer, size_t *capacity) {
char *buf = *buffer;
size_t cap = *capacity, pos = 0;
if (cap < MINIMUM_CAPACITY) { cap = MINIMUM_CAPACITY; }
for (;;) {
buf = realloc(buf, cap);
if (buf == NULL) { return pos; }
*buffer = buf;
*capacity = cap;
if (fgets(buf + pos, cap - pos, stdin) == NULL) {
break;
}
pos += strcspn(buf + pos, "\n");
if (buf[pos] == '\n') {
break;
}
cap *= 2;
}
return pos;
}
int main(void) {
char *line = NULL;
size_t size = 0;
for (size_t end = read_line(&line, &size); line[end] == '\n'; end = read_line(&line, &size)) {
line[end] = '\0'; // trim '\n' off the end
// process contents of buffer here
}
free(line);
return 0;
}
An ideal solution should be able to operate with a fixed buffer of 1 byte. This requires a more comprehensive understanding of the problem, however. Once achieved, adapting such a solution would achieve the most optimal solution.
#include <stdio.h>
#include <stdlib.h>
#include <string.h>
char *readFromIn(FILE *fp)
{
char text[1024];
size_t len;
if (!fgets(text, sizeof text, fp)) return NULL;
len = strlen(text);
while (len && text[len-1] == '\n') text[--len] = 0;
return strdup(text);
}
Why did no one propose to move the buffer from heap to stack ? This is my solution now:
char input[1024]; // held ready as buffer for fgets
char* readFromIn()
{
char* result = fgets(input, 1024, stdin);
if (result == null)
return "";
if (result[strlen(result) - 1] == '\n')
result[strlen(result) - 1] = 0;
return result;
}