storage of a result in a vector - c

Question

I have tried to store a result in a vector and then to print all those stored values, I think I'm very far, but that's what I was able to develop until now, I'd like some help on what's wrong and how it could you do it, thank you and good night
#include <stdio.h>
int main(void) {
int i;
int x;
int vetor[]={};
int a, b;
int resultado;
printf("Quantos resultados esse vetor vai receber tem ? ");
scanf("%d", &x);
printf("\n");
for(i=1; i<=x; i++){
printf("Digite valores para serem somados e armazenados no vetor:\n");
scanf("%d%d", &a, &b);
resultado = a+b;
resultado = *vetor;
printf("vetor contém: %d\n", *vetor);
}
printf("\n");
printf("você conseguiu !!!");
return 0;
}
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Answer 1

#include <stddef.h>
#include <stdio.h>
#define ARRAY_SIZE(arr) (sizeof(arr) / sizeof((arr)[0]))
#define ARRAY_SSIZE(arr) ((ptrdiff_t)ARRAY_SIZE(arr))
int main(void)
{
ptrdiff_t x;
int a, b;
int resultado;
printf("Quantos resultados esse vetor vai receber tem ? ");
scanf("%ti", &x);
int vector[x] = {0};
printf("\n");
for (ptrdiff_t i = 0; i < ARRAY_SSIZE(vector); i++) {
printf("Digite valores para serem somados e armazenados no vetor:\n");
scanf("%d%d", &a, &b);
resultado = a + b;
vector[i] = resultado;
printf("vetor contém: %d\n", vetor[i]);
}
printf("\n");
printf("você conseguiu !!!\n");
return 0;
}
You should give the array (not vector) a size (x in this case) to create it.
Assignments (a = b;) work this way: the program calculates whatever is on the right hand side, and copies that value into the variable that is on the left hand side of the =.
When you use (access, write, ...) an array, you have to specify the index (position) of the array you want to use.
It is better to use sizeof to calculate the size of an array for loop limits so that if you change the declaration of the array, the code still works (see ARRAY_SIZE, and ARRAY_SSIZE which is a signed version, so that comparison is done between integers of the same sign, to avoid unexpected bugs).
Always end your last printf with a \n, so that it doesn't get mixed with other text in the terminal.