I need help to convert from infix to postfix in C - c

Question

I was practising some data structures problems that I did previously but this time I don't know what is going wrong in my code. I looked over a long time but I did not found the mistake. When I'm printing I'm just getting the first character and it looks like e is not being updated. But I've written e++.
#include<stdio.h>
#include "ctype.h"
int stack[20];
int top = -1;
void push(int x)
{
stack[++top] = x;
}
int pop()
{
return stack[top--];
}
int priorityof(char x)
{
if(x=='(')
return 3;
else if(x=='+'|| x=='-')
return 1;
else if(x=='*'|| x=='/')
return 2;
}
int main()
{
char exp[20];
char *e;
e=exp;char x;
scanf("%c",exp);
while(*e!='\0')
{
if(isalnum(*e))
{
printf("%c", *e);
}
else if(*e=='(')
{
push(*e);
}
else if(*e==')')
{
while((x=pop())!='(')
printf("%c",x);
}
else {
while (priorityof(stack[top]) >= priorityof(*e)) {
printf("%c", pop());
push(*e);
}
}
e++;
}
while(top!=-1)
{
printf("%c",pop());
}
}

Answer 1

%c is for single character and reading your question it seems like you are giving more than one character so its a string, use %s.
#include<stdio.h>
#include "ctype.h"
int stack[20]; int top = -1;
void push(int x) {
stack[++top] = x;
}
int pop() { return stack[top--]; }
int priorityof(char x) {
if(x=='(') return 3;
else if(x=='+'|| x=='-') return 1;
else if(x=='*'|| x=='/') return 2;
}
int main() {
char exp[20];
char *e;
e=exp;char x;
scanf("%s",exp);
while(*e!='\0') { if(isalnum(*e)) { printf("%c", *e); } else if(*e=='(') { push(*e); } else if(*e==')') { while((x=pop())!='(') printf("%c",x); } else { while (priorityof(stack[top]) >= priorityof(*e)) { printf("%c", pop()); push(*e); } } e++; } while(top!=-1) { printf("%c",pop()); } }