reverse an array with recursion - c

Question

When I try to run this it asks me to input 11 numbers instead of 10 with is really weird then it out puts like an even weirder result please help.
void function(int array[],int length,int start)
{
if (length<start)
{
return;
}
int temp=array[start];
array[start]=array[length];
array[length]=temp;
function(array,length-1,start+1);
}
int main()
{
int array[10],num=0,num2=10;
printf("enter the array:\n");
for (int i =0; i<num2; i++)
{
scanf("%d\n",&array[i]);
}
function(array,num2,num);
for (int t = 0; t<num2; t++)
{
printf("%d\n",array[t]);
}
}
then this is the out put for the array 1,2 ... 10,11
enter the array:
1
2
3
4
5
6
7
8
9
10
11
return
214696143
10
9
8
7
6
5
4
3
2
(lldb)
please help

Answer 1

The last index of an array with size 10 is actually 9. So this line:
function(array,num2,num);
Should be:
function(array,num2-1,num);
Also, your use of scanf is incorrect. Eliminate the \n character. Read more about scanf here: http://www.cplusplus.com/reference/cstdio/scanf/
I corrected your code and tested it here: https://onlinegdb.com/B1Yy4yBqN

Answer 2

Try this:
#include <stdio.h>
void function(int array[],int start, int end)
{
if (start < end)
{
int temp;
temp = array[start];
array[start] = array[end];
array[end] = temp;
function(array, start+1, end-1);
}
}
int main()
{
int array[10],num=0,num2=10;
printf("enter the array:\n");
for (int i =0; i<num2; i++)
{
scanf("%d",&array[i]);
}
function(array,num,num2 - 1);
for (int t = 0; t<num2; t++)
{
printf("%d\n",array[t]);
}
}
Note that in C, the array starts from 0. The last index is 9 not 10. You need to access to the last element using length - 1 instead of length