I have two tables in SQL that look like this:
Table 1:
ID TaxYear Earnings
01 2000 2234
01 2001 123
02 2004 12344
02 2006 234
02 2007 0
02 2008 123
Table 2:
ID JobEnd
01 1998
02 2000
02 2007
I need to combine these tables to make a new column giving the number of years between TaxYear and JobEnd. However, I need this value to reset every time TaxYear passes a new JobEnd year. So my final table would look like this:
ID TaxYear Earnings YearsSinceJobEnd
01 2000 2234 2
01 2001 123 3
02 2004 12344 4
02 2006 234 6
02 2007 0 7
02 2008 123 1
For ID 02, when YearsSinceJobEnd is calculated as TaxYear minus 2000, up until TaxYear passes the new JobEnd year of 2007, when it is subsequently calculated as TaxYear minus 2007.
I'm getting very confused about how to do this. If I join the tables I end up with multiple columns per TaxYear, which I need to avoid. But I can't think how to calculate the new column without joining them.
Any help would be much appreciated.
You can use datediff() with DATETIMEFROMPARTS ():
select t1.id, t1.TaxYear, t1.Earnings,
datediff(year, DATEFROMPARTS(t2.JobEnd, 1, 1), DATEFROMPARTS(t1.TaxYear, 1, 1)) as YearsSinceJobEnd
from t1 inner join
t2
on t2.id = t1.id;
If you don't want JOIN then use APPLY :
select t1.id, t1.TaxYear, t1.Earnings,
datediff(year, DATEFROMPARTS(t2.JobEnd, 1, 1), DATEFROMPARTS(t1.TaxYear, 1, 1)) as YearsSinceJobEnd
from t1 cross apply
( select top (1) t2.JobEnd
from t2
where t2.id = t1.id and t2.JobEnd < t1.TaxYear
order by t2.JobEnd desc
) t2;
you can user CROSS APPLY to find the required JobEnd for each ID
SELECT t1.ID, t1.TaxYear, t1.Earnings,
YearsSinceJobEnd = t1.TaxYear - e.JobEnd
FROM Table1 t1
CROSS APPLY
(
SELECT JobEnd = MAX(t2.JobEnd)
FROM Table2 t2
WHERE t2.ID = t1.ID
AND t2.JobEnd < t1.TaxYear
) e
Related
I have a table in which i am inserting some records every week. There is a column for Date. I want to compare the data of last week and this week using column key. Below is my table:
Name Date Key
ABC 07 June 1
BAC 07 June 2
WSD 07 June 3
QWE 14 June 9
QWT 14 June 2
DEF 14 June 1
CXZ 14 June 6
I want the data of 14 June in which key is same as in data of 07th june.
Desired output:
Name Date Key
QWT 14 June 2
DEF 14 June 1
I am using CTE to join but i am not getting the desired results.
;WITH T1
AS
(SELECT * FROM [Table] where [Date]= '07 June'),
T2
AS
(SELECT * FROM [Table] where [Date]= '14 June')
SELECT *
FROM T2
INNER JOIN T1 ON T1.[KEY] = T2.[KEY];
What you have should be returning the results you stated that you want. I would maybe simplify this a little bit to a single query with a self join. Something like this.
select t2.*
from [Table] t
join [Table] t2 on t.MyKey = t2.MyKey
where t.MyDate = '07 June'
and t2.MyDate = '14 June'
If you want the data of 14 June in which key is the same as in data of 07th June. You can use intersect:
select
t1.*
from
table
as t1
where
t1.MyDate = '07 June'
intersect select
t2.*
from
table
as t2
where
t2.MyDate = '14 June
You can also think everything dynamic as below. This will return you result regardless what is the date is. this will always compare a row with the row with date 7 day less.
You can check DEMO HERE
SELECT A.*
FROM your_table A
INNER JOIN your_table B
ON A.[Key] = B.[Key] AND DATEADD(DD,7,B.[Date]+ ' 2019') = A.[Date] + ' 2019'
-- Added 2019 To make the string as date
I have three tables. Table Cust has a custID field, plus various other values (name, address etc)
Table List has a single column ID. Each ID is a custID in the Cust table
Edit: the purpose of this is to filter the records, restricting thge results to ones where the CustID appears in the list table.
All three tables are indexed.
Table Trans has a TransactionID field, a Cust field that holds a customer ID, And other transaction fields
Edit: I should have mentioned that in some cases there will be no transaction record. In this case I want one row of Customer info with the transaction fields null or blank.
I want a query to return cust and transaction ID for each ID in the list table. If there is more than one matching row in the transaction table, I want each included along 3with the matching cust info. So if the tables look like This:
Cust
ID Name
01 John
02 Mary
03 Mike
04 Jane
05 Sue
06 Frank
List
ID
01
03
05
06
Transact
TransID CustId Msg
21 01 There
22 01 is
23 02 a
24 03 tide
25 04 in
26 04 the
27 05 affairs
28 05 of
29 05 men
I want the result set to be:
CustID Name TransID Msg
01 John 21 There
01 John 22 is
03 Mike 24 tide
05 Sue 27 affairs
05 Sue 28 of
05 Sue 29 men
06 Frank -- --
(Where -- represents NULL or BLANK)
Obviously the actual tables are much larger (millions of rows), but that shows the pattern, one row for every item in table Transactions that matches any of the items in the List table, with matching fields from the Cust table. if there is no matching Transaction, one row of customer info from each ID in the List table. CustID is unique in the Cust and List tables, but not in the transaction table.
This needs to work on any version of SQL server from 2005 onward, if that matters.
Any suggestions?
Unless I'm missing something, this is all you need to do:
Select T.CustID, C.Name, T.TransID, T.Msg
From Transact T
Join Cust C On C.Id = T.CustId
Join List L On L.Id = C.Id
Order By T.CustID, T.TransID
;with cust (id, name) as
(
select 1, 'John' union all
select 2, 'Mary' union all
select 3, 'Mike' union all
select 4, 'Jane' union all
select 5, 'Sue'
), list (id) as
(
select 1 union all
select 3 union all
select 5
), transact (TransId, CustId, Msg) as
(
select 21, 1, 'There '
union all select 22, 1, 'is'
union all select 23, 2, 'a'
union all select 24, 3, 'tide'
union all select 25, 4, 'in'
union all select 26, 4, 'the'
union all select 27, 5, 'affairs'
union all select 28, 5, 'of'
union all select 29, 5, 'men'
)
select
CustId = c.id,
Name = c.Name,
TransId = t.TransId,
Msg = t.Msg
from cust c
inner join list l
on c.id = l.id
inner join transact t
on l.id = t.custid
yields:
CustId Name TransId Msg
----------- ---- ----------- -------
1 John 21 There
1 John 22 is
3 Mike 24 tide
5 Sue 27 affairs
5 Sue 28 of
5 Sue 29 men
I have this query:
SELECT
Table1.ID, Table1.Code1, Table1.Code2, Table1.Details,
Table1.IDS, Table2.Name
FROM
Table1
INNER JOIN
Table2 ON Table1.Code1 = Table2.Code1
WHERE
Table1.IDS = 1
ORDER BY
Table1.Code1, Table1.Code2
This is my result for query:
ID Code1 Code2 Details IDS Name
1 1001 01 D1 1 N1
2 1001 01 D2 1 N1
3 1001 02 D3 1 N1
4 1001 05 D4 1 N1
5 1002 11 D5 1 N2
6 1002 12 D6 1 N2
7 1005 21 D7 1 N3
8 1005 21 D8 1 N3
But I want this result:
ID Code1 Code2 Details IDS Name
1 1001 01 D1 1 N1
2 01 D2 1
3 02 D3 1
4 05 D4 1
5 1002 11 D5 1 N2
6 12 D6 1
7 1005 21 D7 1 N3
8 21 D8 1
How do I get this result? Please help me. Thanks a lot
Embedding presentation logic in your query isn't ideal. I recommend you process the query results programmatically, either to detect when groups change as you iterate, or to transform the query results into a nested table. The latter can be generalized as a reusable function.
If you can rely on the ID column for ordering the groups (or a combination of other rows, like code1,code2) then you can do this in a few different ways.
If your server is 2012+ then you can use the LAG() window function to access previous rows and if the previous rows Code1 is the same as the current rows Code1 replace it with null (or an empty string if that suits you better). However, if you're using a version < 2012 then you can accomplish it using a self join.
This kind of formatting might be better to handle on the client side (or reporting layer) though if can.
The query below includes both versions, but I commented out the self-join stuff:
SELECT
Table1.ID,
-- CASE WHEN Table1.Code1 = t1.Code1 THEN NULL ELSE Table1.Code1 END AS Code1,
CASE WHEN LAG(Table1.Code1) OVER (ORDER BY Table1.ID) = Table1.Code1 THEN NULL ELSE Table1.Code1 END AS Code1,
Table1.Code2, Table1.Details, Table1.IDS,
-- CASE WHEN Table1.Name = t1.Name THEN NULL ELSE Table1.Name END AS Name,
CASE WHEN LAG(Table2.Name) OVER (ORDER BY Table1.ID) = Table2.Name THEN NULL ELSE Table2.Name END AS Name
FROM
Table1
INNER JOIN
Table2 ON Table1.Code1 = Table2.Code1
-- LEFT JOIN Table1 t1 ON Table1.ID = t1.ID + 1
WHERE
Table1.IDS = 1
ORDER BY
Table1.Code1, Table1.Code2
Sample SQL Fiddle
Morteza,
This is a clear case of a presentation/UI layer requirement. Databases are made for a particular purpose and that is to crunch data and present you with results. I'd highly recommend you to turn to the front end logic for achieving your purpose.
Using ROW_NUMBER() within CTE or a subquery, here is one way to get your expected output:
;WITH q1 as
(
SELECT
t1.ID,
t1.Code1,
t1.Code2,
t1.Details,
t1.IDS,
t2.Name,
ROW_NUMBER() OVER (PARTITION BY t1.Code1 ORDER BY t1.ID) as rn
FROM
table1 t1
INNER JOIN
Table2 t2 ON t1.Code1 = t2.Code1
)
SELECT
q1.ID,
CASE
WHEN rn = 1 THEN q1.Code1
ELSE ''
END as Code1, --only populate first row for each code1
q1.Code2,
q1.Details,
q1.IDS,
CASE
WHEN rn = 1 THEN q1.Name
ELSE ''
END as Name --only populate first row for each name
FROM
q1
WHERE
q1.IDS = 1
ORDER BY
q1.Code1, q1.Code2
SQL Fiddle Demo
Given the following set of data, I'm trying to determine how I can select the start and end dates of the combined date ranges, when they intersect with each other.
For instance, for PartNum 115678, I would want my final result set to display the date ranges 2012/01/01 - 2012/01/19 (rows 1, 2 and 4 combined since the date ranges intersect) and 2012/02/01 - 2012/03/28 (row 3 since this ones does not intersect with the range found previously).
For PartNum 213275, I would want to select the only row for that part, 2012/12/01 - 2013/01/01.
Edit:
I'm currently playing around with the following SQL statement, but it's not giving me exactly what I need.
with DistinctRanges as (
select distinct
ha1.PartNum "PartNum",
ha1.StartDt "StartDt",
ha2.EndDt "EndDt"
from dbo.HoldsAll ha1
inner join dbo.HoldsAll ha2
on ha1.PartNum = ha2.PartNum
where
ha1.StartDt <= ha2.EndDt
and ha2.StartDt <= ha1.EndDt
)
select
PartNum,
StartDt,
EndDt
from DistinctRanges
Here are the results of the query shown in the edit:
You're better off having a persisted Calendar table, but if you don't, the CTE below will create it ad-hoc. The TOP(36000) part is enough to give you 10 years worth of dates from the pivot ('20100101') on the same line.
SQL Fiddle
MS SQL Server 2008 Schema Setup:
create table data (
partnum int,
startdt datetime,
enddt datetime,
age int
);
insert data select
12345, '20120101', '20120116', 15 union all select
12345, '20120115', '20120116', 1 union all select
12345, '20120201', '20120328', 56 union all select
12345, '20120113', '20120119', 6 union all select
88872, '20120201', '20130113', 43;
Query 1:
with Calendar(thedate) as (
select TOP(36600) dateadd(d,row_number() over (order by 1/0),'20100101')
from sys.columns a
cross join sys.columns b
cross join sys.columns c
), tmp as (
select partnum, thedate,
grouper = datediff(d, dense_rank() over (partition by partnum order by thedate), thedate)
from Calendar c
join data d on d.startdt <= c.thedate and c.thedate <= d.enddt
)
select partnum, min(thedate) startdt, max(thedate) enddt
from tmp
group by partnum, grouper
order by partnum, startdt
Results:
| PARTNUM | STARTDT | ENDDT |
------------------------------------------------------------------------------
| 12345 | January, 01 2012 00:00:00+0000 | January, 19 2012 00:00:00+0000 |
| 12345 | February, 01 2012 00:00:00+0000 | March, 28 2012 00:00:00+0000 |
| 88872 | February, 01 2012 00:00:00+0000 | January, 13 2013 00:00:00+0000 |
I am struggling to write a query to result in the following records.
I have a table with records as
c1 c2 c3 c4 c5 c6
1 John 2.3.2010 12:09:54 4 7 99
2 mike 2.3.2010 13:09:59 8 6 88
3 ahmad 2.3.2010 14:09:59 1 9 19
4 Jim 23.3.2010 16:35:14 4 5 99
5 run 23.3.2010 12:09:54 3 8 12
I want to fetch only the records :-
3 ahmad 2.3.2010 14:09:59 1 9 19
4 Jim 23.3.2010 16:35:14 4 5 99
I mean the records that are sort by column c3 and the one which is latest for that day. here i have 1, 2, 3 records that are at different times of the day. there i need the records that are sort by date desc and then only top 1 record. similarly for 4 and 5. can you please help me in writing a query.
If you're on SQL Server 2008 or 2008 R2, you can try this:
WITH TopPerDay AS
(
SELECT
c1, c2, c3, c4, c5, C6,
ROW_NUMBER() OVER
(PARTITION BY CAST(c3 AS DATE) ORDER BY c3 DESC) 'RowNum'
FROM dbo.YourTable
)
SELECT *
FROM TopPerday
WHERE RowNum = 1
I basically partition the data by day (using the DATE type in SQL Server 2008 and up), and order by the c3 column in a descending order. This means, for every day, the oldest row will have RowNum = 1 - so I just select those rows from the Common Table Expression and I'm done.
Tried this on a SQL Server 2005 database.
SELECT *
FROM dbo.YourTable t1
WHERE (t1.c3) =
(
SELECT MAX(t2.c3)
FROM dbo.YourTable t2
WHERE DATEDIFF(dd,t2.c3, t1.c3) = 0
)
ORDER BY t1.c3 ASC
Thanks for the responses!
I have found the solution too.
select * from
(select convert(varchar(10),c3,104) as date, max(c3) as date1 from MYTABLE
group by convert(varchar(10),c3,104)) as T1 innerjoin MYTABLE as T2 on
convert(varchar(10),T2.c3,104) = T1.date and t2.c3 = T2.date1