SAS insert to ARRAY only (example) first row from dataset - arrays

I have bit a problem. I need insert to Array only (example) first array, best field by field.
How Can I do it? I will be grateful if also you point how insert column by column (I will be able to load chosen columns in the future).
data have;
infile DATALINES dsd missover;
input varr1 varr2 varr3;
CARDS;
1, 2, 3
2, 3, 4
5, 4
4, 3
9, 4, 1
6,
;run;
data want;
set have;
array L[3] _temporary_ ;
if _n_ = 1 then
do;
do i = 1 to 3;
%LET j = i;
L[i] = varr&i; /*in this place I have problem*/
put L[i];
end;
end;
run;

You don't need macro, and not sure why you need temporary array L.
The array statement can be used to organize variables so they can be accessed in an array manner. Loop over the variable array in order to copy the values into the temporary array.
The elements of a temporary array are not available for output, and not part of normal implicit program data vector (PDV) behaviors that would reset variables to missing.
data want;
set have;
array V varr1-varr3;
array L[3] _temporary_;
* save first rows values in temporary array for use in other rows;
if _n_ = 1 then
do index = 1 to dim(V);
L[index] = V[index];
end;
* … for example … ;
array delta_from_1st [3]; * array statement implicitly creates three new variables that become part of PDV and get output;
do index = 1 to dim(V);
delta_from_1st[index] = V[index] - L[index];
end;
run;

Related

Problem: Referencing Array Value, but Returning Zero

I have been working on randomly selecting items within an array. Below, I have outlined my process. I have made it to successfully step 6 (with many data checks), but for some reason, when I reference the array, I receive a value of zero. This has been confusing because even when I check the raw sorted data note a certain value, the value retrieved is zero. Additionally, I ran a VNAME to see which variable it was pulling and it corresponded to the correct place within the array. Does anyone know why I am returning a zero value from the array?
*STEP 1: Set all non-codes to zero;
ARRAY CEREAL [337] ha_DTQ02_1-ha_DTQ02_337;
DO i=1 to 337;
if CEREAL[i]=88888.00 THEN CEREAL[i]=0;
END;
*STEP 2: Sort so that all zero values come first and food codes come last;
call SORTN(ha_DTQ02_1-ha_DTQ02_337);
*STEP 3: Rename array in reverse order so that zeros come last and codes are first. Sort function above only works in ascending order;
RENAME ha_DTQ02_1- ha_DTQ02_337=ha_DTQ02_337-ha_DTQ02_1;
*STEP 4: Count number of cereals selected;
ARRAY CEREALS[337]ha_DTQ02_1-ha_DTQ02_337;
NUMCEREALS=0;
DO i=1 to 337;
IF CEREALS[i] NOT IN (.,0) THEN NUMCEREALS+1;
END;
*STEP 5: get a random number between those two numbers- this works just fine;
IF NUMCEREALS NE 0 THEN rand1 = rand('integer', 1, numCereals);
*ensure that your second random number isn't the same as the first random number;
if NUMCEREALS ge 2 then do until(rand2 ne rand1);
rand2 = rand('integer', 1, numCereals);
end;
*STEP 6: Pull value from array using random number.;
Note: This is where I am stuck. I have tried alternative code where I recreated a new array and tried to pull the values from that new array. I have also tried placing the code directly below before closing the do loop. When the code does run, the value for these variables is zero. After many data checks, steps 1-5 work well and achieve their goals.
dtd020Af = CEREALS (rand1);
dtd020Bf = CEREALS (rand2);
OPTIONS NOFMTERR;
run;
The SORTN call routine needs the OF operator in order to utilize a name list.
call SORTN(of ha_DTQ02_1-ha_DTQ02_337);
A keen eye on the LOG window should have shown you the WARNING
3214 call SORTN(ha_DTQ02_1-ha_DTQ02_337);
-----
134
WARNING 134-185: Argument #1 is an expression, which cannot be updated by the SORTN subroutine
call.
You can't rename variables during run-time and reference the value with the new names.
You have declared an ARRAY listing the variables in 1..337 order. Check, that's good.
You CAN declare a second ARRAY listing the variables in reverse 337..1 order!
You also do not want to use a variable that might be missing, rand2, as a index value.
Suggested code:
data have;
call streaminit(123);
do id = 1 to 100;
array X X1-X337;
do over X;
if rand('uniform') < 0.75 then X = 88888;
else
X = rand('integer',1,10);
if id=50 then if _I_ ne 10 then X=88888; else X=5;
end;
OUTPUT;
end;
run;
data want;
set have;
ARRAY CEREAL X1-X337;
DO i=1 to DIM(CEREAL);
if CEREAL[i]=88888.00 THEN CEREAL[i]=0;
END;
* sort the variables that comprise the CEREAL array;
call SORTN(of CEREAL(*));
* second array to reference variables in reverse order;
array CEREAL_REVERSE x337-x1;
* count how many non-missing/non-zero values at the end of the sorted variables;
DO i=1 to DIM(CEREAL);
IF CEREAL_REVERSE[i] IN (.,0) then leave;
NUMCEREALS = i;
END;
IF NUMCEREALS NE 0 THEN rand1 = rand('integer', 1, numCereals);
if NUMCEREALS ge 2 then
do until(rand2 ne rand1);
rand2 = rand('integer', 1, numCereals);
end;
* assign random selection if warranted;
if NUMCEREALS > 0 then dtd020Af = CEREAL_REVERSE (rand1);
if NUMCEREALS > 1 then dtd020Bf = CEREAL_REVERSE (rand2);
run;

set length of a 1d array with a variable

I would like to set the length of an array depending on what value i obtain from reading a dataset:number which has one variable num with one numeric value. But I am getting an error message: saying that I cannot initiate the probs array. Can i get any suggestion on how to solve this issue? (I really don't want to hardcode the length of the probs array)
data test;
if _n_=1 then do;
set work.number;
i = num +1;
end;
array probs{i} _temporary_ .....
SAS Data step arrays can not be dynamically sized during step run-time.
One common approach is to place the computed number of rows of the data set into a macro variable before the data step.
I'm not sure what you are doing with probs.
What values will be going into the array elements ?
Do you need all prob data while iterating through each row of the data set ?
Is a single result computed from the probs data ?
Example - Compute row count in a data null using nobs set option:
data _null_;
if 0 then set work.number nobs=row_count;
call symputx ('ROW_COUNT', row_count);
stop;
run;
data test;
array probs (&ROW_COUNT.) _temporary_;
* something with probs[index] ;
* maybe fill it ?
do index = 1 by 1 until (last_row);
set work.number;
probs[index] = prob; * prob from ith row;
end;
* do some computation that a procedure isn't able to;
…
result_over_all_data = my_magic; * one result row from processing all prob;
output;
stop;
run;
Of course your actual use of the array will vary.
The many other ways to get row_count include dictionary.table views, sql select count(*) into and a variety of ATTRN invocations.

Multiple Dynamic Array with conditional in SAS

I have two arrays and I would like to make one conditional on the other. ARRAY1 contains binary flags (0 or 1) and I would like to make the second array be blank if the contents in ARRAY1[i] is 0. ARRAY1 and ARRAY2 have the same number of elements.
data test;
set test_data;
array ARRAY1 &variable_flags;
array ARRAY2 $ &variable_list &variable_list_initial_values;
do i=1 to &variable_count;
if ARRAY1[i]=0 then ARRAY2[i]="";
end;
run;
My output works until it hits a 0 in ARRAY[i]. When that happens the column is blank after words. I end up with something like the attach image. Why is this happening?
The initial values for an array are set only once. They are not re-applied at the start of each iteration of the data step. You could change your logic to have another array with the initial values. Let's make some test data.
data test_data;
input matt_flg ## ;
cards;
1 1 0 0 1 1
;
Now let's set the value to either the default value or empty based on the value of the FLAG variable.
%let variable_flags=matt_flg;
%let variable_list=matt;
%let variable_list_initial_values="MATT";
%let variable_count=%sysfunc(countw(&variable_list));
%let maxlength=20 ;
data test;
set test_data;
array flags &variable_flags;
array vars $&maxlength. &variable_list ;
array default (&variable_count) $&maxlength. _temporary_ (&variable_list_initial_values);
do i=1 to dim(vars);
if flags(i) then vars(i)=default(i);
else vars(i)=' ';
end;
run;

Using arrays in SAS

I am a SAS beginner. I have an array-like piece of data in my code, which needs to be passed to a different data step much lower in the code to do computations with it. My code does something like this (computation simplified for this example):
data _null_;
call symput('numRuns', 10000);
run;
/* this is the pre-computation step, building CompressArray for later use */
data _null_;
do i = 1 to &numRuns;
value = exp(rand('NORMAL', 0.1, 0.5)));
call symput(compress('CompressArray'||i), value);
end;
run;
data reportData;
set veryLargeDataSet; /* 100K+ observations on 30+ vars */
array outputValues[10000];
do i = 1 to &numRuns;
precomputedValue = symget(compress('CompressArray'||i));
outputValues[i] = /* calculation using precomputedValue */
end;
run;
I am trying to redo this using arrays, is that possible? E.g. to store it in some global array and access it later...
Arrays in SAS only exist for the duration of the data step in which they are created. You would need to save the contents of your array in a dataset or, as you have done, in a series of macro variables.
Alternatively, you might be able to rewrite some of your code to do all of the work that uses the array within one data step. DOW-loops are quite good in this regard.
Based on the updates to your question, it sounds as though you could use a temporary array to do what you want:
data reportData;
set veryLargeDataSet; /* 100K+ observations on 30+ vars */
array outputValues[&numruns];
array precomputed[&numruns] _temporary_;
if _n_ = 1 then do i = 1 to &numruns;
if i = 1 then call streaminit(1);
precomputed[i] = exp(rand('NORMAL', &meanNorm, &stDevNorm));
end;
do i = 1 to &numRuns;
outputValues[i] = /* calculation using precomputed[i] */
end;
run;
Defining an array as _temporary_ causes the values of the array elements to be retained across iterations of the data step, so you only have to populate it once and then you can use it for the rest of the data step.
There are a lot of ways to do this, but the hash table lookup is one of the most straightforward.
%let meannorm=5;
%let stDevNorm=1;
%let numRuns=10000;
/* this is the pre-computation step, building CompressArray for later use */
data my_values;
call streaminit(7);
do i = 1 to &numRuns;
Value= rand('Normal',&meannorm., &stDevNorm.);
output;
end;
run;
data reportData;
if _n_=1 then do;
declare hash h(dataset:'my_values');
h.defineKey('i'); *the "key" you are looking up from;
h.defineData('value'); *what you want back;
h.defineDone();
call missing(of i value);
end;
set sashelp.class; /* 100K+ observations on 30+ vars */
array outputValues[10000];
do i = 1 to &numRuns;
rc=h.find();
outputValues[i] = value;
end;
run;
Basically, you need to 'load' the table in some fashion and do [something] with it. Here's one easy way.
In your particular example there's another pretty simple way: bring it in an as array.
In this case we don't put 10k rows out, but 10k variables - then declare it as an array (again) in the new data step. (Arrays are, as noted by user667489, transient; they're not stored on the dataset in any way, except as the underlying variables, so they have to be re-declared each data step.)
%let meannorm=5;
%let stDevNorm=1;
%let numRuns=10000;
/* this is the pre-computation step, building CompressArray for later use */
data my_values;
call streaminit(7);
array values[&numruns.];
do i = 1 to &numRuns;
Values[i]= rand('Normal',&meannorm., &stDevNorm.);
end;
run;
data reportData;
if _n_=1 then set my_values(drop=i);
set sashelp.class; /* 100K+ observations on 30+ vars */
array outputValues[&numruns.];
array values[&numruns.]; *this comes from my_values;
do i = 1 to &numRuns;
outputValues[i] = values[i];
end;
drop values:;
run;
Here note that I have the set in if _n_=1 still - otherwise it would terminate the data step after the first iteration.
You could also use a format, as Reeza notes, or several other options - but I think these are the simplest.

Compute inner poduct without IML

I am trying to create a macro that compute the inner(dot) product of a vector and a matrix.
Y*X*t(Y) ## equivalent to the Sum(yi*Xij*yj)
I don't have IML, so I try to do it using array manipulation.
How to create a multidimensional array from the data to avoid index
translation within single array.
How to debug my loop, or at least print some variable to control my program?
How to delete temporary variables?
I am a SAS newbie, but this is what I have tried so far:
%macro dot_product(X = ,y=, value= );
/* read number of rows */
%let X_id=%sysfunc(open(&X));
%let nrows=%sysfunc(attrn(&X_id,nobs));
%let rc=%sysfunc(close(&X_id));
data &X.;
set &X.;
array arr_X{*} _numeric_;
set &y.;
array arr_y{*} _numeric_;
do i = 1 to &nrows;
do j = 1 to &nrows;
value + arr_y[i]*arr_X[j + &nrows*(i-1)]*arr_y[j];
end;
end;
run;
%mend;
When I run this :
%dot_product(X=X,y=y,value=val);
I get this error :
ERROR: Array subscript out of range at line 314 column 158.
I am using this to generate data :
data X;
array myCols{*} col1-col5;
do i = 1 to 5;
do j = 1 to dim(myCols);
myCols{j}=ranuni(123);
end;
output;
end;
drop i j;
run;
/* create a vector y */
data y;
array myCols{*} col1-col5;
do j = 1 to dim(myCols);
myCols{j}=ranuni(123);
end;
output;
drop j;
run;
Thanks in advance for your help or any idea to debug my data.
Edit: The following relates to the description of the question, how to evaluate a quadratic form using dot, inner or scalar products. The actual code is nearly fine. end edit
If you want to reduce it to dot products, then your value is the dot product of the linearization of X_ij and the same linearization applied to Z_ij=Y_i*Y_j.
The other way is to portion X_ij into its rows or columns depending on the linearization of the matrix, and compute separate dot products of Y with, say, each row. Of the resulting vector you the compute the dot product again with Y.
Edit added: The length nrows of the nested loops in the code should be determined from the length of the vector y, perhaps with a check that the length of x is nrows*nrows.

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