Combine two queries with different 'FROM' tables but similar 'JOIN' tables - sql-server

Question

I have two queries that I'm trying to combine into one result set.
Query 1:
SELECT t1.evalID, t2.[Order], COUNT(t2.StepID) AS 'Total Categories'
FROM Evals t1
JOIN Steps t2 ON t1.TemplateID = t2.TemplateID
JOIN GradingCats t3 ON t2.StepID = t3.StepID
GROUP BY t1.EvalID, t2.[Order]
ORDER BY t2.[Order]
Query 2:
SELECT t4.EvaluatorID, t6.StepID, t6.[Order], COUNT(t4.Grade) AS 'Grades Entered'
FROM Grading t4
JOIN GradingCats t5 ON t4.GradingCatID = t5.GradingCatID
JOIN Steps t6 ON t5.StepID = t6.StepID
GROUP BY t6.StepID, t4.EvaluatorID, t6.[Order]
My end goal is to locate which steps of an evaluation have missing grades.
edit (sample data):
Query #1
|---------------------|------------------|---------------------|
| evalID | Order | Total Categories |
|---------------------|------------------|---------------------|
| 81 | 01.00 | 17 |
|---------------------|------------------|---------------------|
| 81 | 02.00 | 17 |
|---------------------|------------------|---------------------|
| 81 | 03.00 | 17 |
|---------------------|------------------|---------------------|
Query #2
|---------------------|------------------|---------------------|------------------|
| evaluatorID | Step | Order | Grades Entered |
|---------------------|------------------|---------------------|------------------|
| 1178 | 609 | 01.00 | 2 |
|---------------------|------------------|---------------------|------------------|
| 1178 | 615 | 02.00 | 3 |
|---------------------|------------------|---------------------|------------------|
| 9441 | 609 | 01.00 | 17 |
|---------------------|------------------|---------------------|------------------|
| 9441 | 609 | 02.00 | 17 |
|---------------------|------------------|---------------------|------------------|
| 9441 | 609 | 03.00 | 17 |
|---------------------|------------------|---------------------|------------------|

Answer 1

Starting with the first query which shows all the steps associated with an EVAL, you can LEFT OUTER JOIN the second query, and the steps that are NULL on the right side of the query will be the ones that are missing grades.
In order to do this, there must be some way in your tables to link Grading to Evals. This column is not evident from the code you posted, but I will assume it is there. Maybe it's through GradingCats.
In shortened psuedo-code, just to show what I mean:
SELECT ...
FROM Evals e
INNER JOIN Steps s ON e.TemplateID = s.TemplateID
LEFT OUTER JOIN Grading g ON g.EvalID = e.EvalID --use whatever means you have to show which Eval a Grade is from
LEFT OUTER JOIN Steps gs ON {join to Grading through GradingCats as in your second query}
WHERE gs.StepID IS NULL
In analyzing the result of this query, all the Steps of every Eval will be in s.StepID, and when the same row has a NULL for gs.StepID, that means that step did not get a grade.
Note that you won't want to do any GROUP BY in this query, since you want a row-level analysis.

Answer 2

A coworker (with more knowledge of the data than I) slightly modified my query:
SELECT query1.stepID, Categories, Graded
FROM
(
SELECT rs.stepid, COUNT(c.category) AS 'Categories'
FROM Evals e
JOIN RunScriptSteps rs ON e.TemplateID = rs.TemplateID
JOIN GradingCats c ON rs.StepID = c.StepID
WHERE EvalID = *(someNumber)*
GROUP BY rs.stepid
)AS query1
LEFT JOIN
(
SELECT s.StepID, COUNT(Grade) AS 'Graded'
FROM Grading g
JOIN GradingCats c ON g.GradingCatID = c.GradingCatID
JOIN Steps s ON c.StepID = s.StepID
WHERE EvalID = *(someNumber)*
GROUP BY s.stepid
) AS query2
ON query1.stepid = query2.stepid
ORDER BY stepid ASC